 Home
 Products
 Integration
 Tutorial
 Barcode FAQ
 Purchase
 Company
barcode reader code in asp.net ZR1 ZL in Software
ZR1 ZL QR Code JIS X 0510 Scanner In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. QRCode Generation In None Using Barcode maker for Software Control to generate, create Quick Response Code image in Software applications. L ix(t) Recognize QR In None Using Barcode reader for Software Control to read, scan read, scan image in Software applications. Generating QR In C# Using Barcode creation for .NET framework Control to generate, create QR Code image in .NET framework applications. Ix( j ) VS ( j ) + ~ ZC I1( j ) I2( j ) Z R2
Printing QR Code In VS .NET Using Barcode maker for ASP.NET Control to generate, create QR Code image in ASP.NET applications. QRCode Printer In Visual Studio .NET Using Barcode creator for VS .NET Control to generate, create Quick Response Code image in .NET applications. vS(t) Encoding QR Code In VB.NET Using Barcode creator for Visual Studio .NET Control to generate, create QR Code ISO/IEC18004 image in .NET framework applications. Make GS1  12 In None Using Barcode creation for Software Control to generate, create UPCA image in Software applications. + ~
EAN13 Creation In None Using Barcode maker for Software Control to generate, create GTIN  13 image in Software applications. Printing USS Code 39 In None Using Barcode encoder for Software Control to generate, create Code 39 Extended image in Software applications. C i1(t) i2(t) Bar Code Creation In None Using Barcode printer for Software Control to generate, create barcode image in Software applications. Create Data Matrix In None Using Barcode generation for Software Control to generate, create Data Matrix ECC200 image in Software applications. A sample circuit for AC analysis
Generate USS ITF 2/5 In None Using Barcode generator for Software Control to generate, create Uniform Symbology Specification ITF image in Software applications. Generate Barcode In Java Using Barcode creation for Eclipse BIRT Control to generate, create bar code image in BIRT reports applications. The same circuit in phasor form
Paint UPCA In .NET Framework Using Barcode generator for Reporting Service Control to generate, create Universal Product Code version A image in Reporting Service applications. GS1128 Encoder In ObjectiveC Using Barcode encoder for iPad Control to generate, create GS1128 image in iPad applications. Figure 442 An AC circuit
Recognize Code 3/9 In Visual Basic .NET Using Barcode scanner for Visual Studio .NET Control to read, scan read, scan image in .NET framework applications. Drawing Bar Code In Visual Studio .NET Using Barcode maker for .NET framework Control to generate, create barcode image in VS .NET applications. The rst step in the analysis of an AC circuit is to note the frequency of the sinusoidal excitation Next, all sources are converted to phasor form, and each circuit element to impedance form This is illustrated in the phasor circuit of Figure 442 At this point, if the excitation frequency, , is known numerically, it will be possible to express each impedance in terms of a known amplitude and phase, and a numerical answer to the problem will be found It does often happen, however, that one is interested in a more general circuit solution, valid for an arbitrary excitation frequency In this latter case, the solution becomes a function of This point will be developed further in 6, where the concept of sinusoidal frequency response is discussed With the problem formulated in phasor notation, the resulting solution will be in phasor form and will need to be converted to timedomain form In effect, the use of phasor notation is but an intermediate step that greatly facilitates the computation of the nal answer In summary, here is the procedure that will be followed to solve an AC circuit analysis problem Example 415 illustrates the various aspects of this method Generate Matrix 2D Barcode In C# Using Barcode generator for .NET framework Control to generate, create 2D Barcode image in .NET framework applications. Making Code 3/9 In Visual C#.NET Using Barcode generator for .NET Control to generate, create Code 39 Full ASCII image in .NET applications. F O C U S O N M E T H O D O L O G Y
AC Circuit Analysis Identify the sinusoidal source(s) and note the excitation frequency Convert the source(s) to phasor form Represent each circuit element by its impedance Solve the resulting phasor circuit, using appropriate network analysis tools 5 Convert the (phasorform) answer to its timedomain equivalent, using equation 446 1 2 3 4 4
AC Network Analysis
EXAMPLE 415 Phasor Analysis of AC Circuit
Problem
50 iS(t) + v (t) ~ S
Apply the phasor analysis method just described to the circuit of Figure 443 to determine the source current 200 100 F Solution
vS(t) = 10 cos(100t) Known Quantities: = 100 rad/s; R1 = 50 Find: The source current iS (t) ; R2 = 200
, C = 100 F
Analysis: De ne the voltage v at the top node and use nodal analysis to determine v Then observe that vS (t) v(t) iS (t) = R1 Next, we follow the steps outlined in the Methodology Box: AC Circuit Analysis Step 1: vS (t) = 10 cos(100t) V; = 100 rad/s Step 2: VS (j ) = 10 0 V Step 3: ZR1 = 50 , ZR2 = 200 , ZC = 1/(j 100 10 4 ) = j 100 The resulting phasor circuit is shown in Figure 444 Step 4: Next, we solve for the source current using nodal analysis First we nd V: VS V V = ZR1 ZR2 ZC 1 1 VS =V + ZR1 ZR2 ZC ZR1 V= 1 1 + ZR2 ZC ZR1 VS = ZR1
1 1 + 40 j 80 50
VS 50
= 7428 0381 V Then we compute IS : IS = VS V = 0083 0727 A ZR1
Step 5: Finally, we convert the phasor answer to time domain notation: is (t) = 0083 cos(100t + 0727) A Z1 = 50 IS
VS = 10e j0
+ ~
Z2 = 200 Z3 = j100
Figure 444 Focus on ComputerAided Tools: You will nd the solution to the same example
computed by MathCad in the electronic les that accompany this book An EWB solution is also enclosed
Part I
Circuits
EXAMPLE 416 AC Circuit Solution for Arbitrary Sinusoidal Input
Problem
Determine the general solution of Example 415 for any sinusoidal source, A cos( t + ) Solution
Known Quantities: R1 = 50
; R2 = 200
, C = 100 F
Find: The phasor source current IS (j ) Analysis: Since the radian frequency is arbitrary, it will be impossible to determine a numerical answer The answer will be a function of The source in phasor form is represented by the expression VS (j ) = A The impedances will be ZR1 = 50 ; ZR2 = 200 ; ZC = j 104 / Note that the impedance of the capacitor is a function of Taking a different approach from Example 415, we observe that the source current is given by the expression IS = VS ZR1 + ZR2 ZC 2 106 ZR2 ZC 200 104 /j = 4 = 4 /j ZR2 + ZC 200 + 10 10 + j 200 25 106 + j 104 2 106 = + j 200 104 + j 200

