barcode reader integration with asp.net COMPUTERS IN PROCESS CONTROL in Software

Paint Code 128 Code Set C in Software COMPUTERS IN PROCESS CONTROL

COMPUTERS IN PROCESS CONTROL
Decoding Code 128C In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
Encoding ANSI/AIM Code 128 In None
Using Barcode creation for Software Control to generate, create Code 128 Code Set A image in Software applications.
TABLE 34.1
ANSI/AIM Code 128 Reader In None
Using Barcode decoder for Software Control to read, scan read, scan image in Software applications.
Encoding Code128 In Visual C#
Using Barcode generator for .NET Control to generate, create Code 128B image in .NET applications.
Step response of second-order system of Example 34.1
Draw Code 128 Code Set B In .NET Framework
Using Barcode printer for ASP.NET Control to generate, create Code 128 Code Set A image in ASP.NET applications.
ANSI/AIM Code 128 Drawer In Visual Studio .NET
Using Barcode generation for VS .NET Control to generate, create USS Code 128 image in .NET framework applications.
RUN T 0.5000 1.0000 Il.5000 2.0000 2.5000 3.0000 3.5000 4.0000 Y.5000 5.0000 5.5000 6.0000 b.5000 7.0000 7.5000 8.0000 8.5000 9.0000 9.5000 ll0.0000 Ok
USS Code 128 Creator In VB.NET
Using Barcode generation for VS .NET Control to generate, create USS Code 128 image in VS .NET applications.
Data Matrix ECC200 Creation In None
Using Barcode generation for Software Control to generate, create Data Matrix image in Software applications.
0.1077 0.3599 0.6582 0.7273 ll.L22L ll.228L II.2532 Il.2189 L.ll5L7 L.07bl L.0ll00 0.9637 o.=lr100 0.93b2 0.9Yb5 0.9bV3 0.9833 0.7995 ll.olloII L.0157
Create EAN / UCC - 14 In None
Using Barcode creator for Software Control to generate, create UCC - 12 image in Software applications.
Barcode Creator In None
Using Barcode drawer for Software Control to generate, create barcode image in Software applications.
To obtain the differential equations for use in the Runge-Kutta method, we proceed as follows. From the controller block, we may write
UPC Symbol Creation In None
Using Barcode encoder for Software Control to generate, create UPCA image in Software applications.
Painting Code 128 Code Set B In None
Using Barcode creator for Software Control to generate, create Code 128 image in Software applications.
(71s + 1) =K,K,----71s
USD-3 Creation In None
Using Barcode generator for Software Control to generate, create Uniform Symbology Specification Code 93 image in Software applications.
Barcode Recognizer In None
Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications.
(34.27)
Print UPC Code In Visual Basic .NET
Using Barcode creation for .NET framework Control to generate, create UPC A image in Visual Studio .NET applications.
Data Matrix ECC200 Decoder In None
Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications.
Cross-multiplying gives
Painting EAN-13 In Objective-C
Using Barcode generation for iPhone Control to generate, create EAN / UCC - 13 image in iPhone applications.
Code 3 Of 9 Decoder In Java
Using Barcode scanner for Java Control to read, scan read, scan image in Java applications.
qsM(s) = K,K,rIsE(s) + K,K,E(s)
Printing Code 39 In Java
Using Barcode creator for BIRT reports Control to generate, create ANSI/AIM Code 39 image in Eclipse BIRT applications.
Paint GS1 DataBar-14 In Visual Studio .NET
Using Barcode generator for Visual Studio .NET Control to generate, create GS1 DataBar Truncated image in Visual Studio .NET applications.
This may be converted to the time domain to give
riz = KcK,i + [K,K,Irl]e
From the comparator of Fig. 34.5, we have e=l-c and & = -k
(34.28)
(34.29) (34.30)
Replacing e and 1 in Eq. (34.28) by the expressions in Eqs. (34.29) and (34.30) gives
i = -K,K,t+ Y(l - c)
(34.31)
DIGITAL COMPUTER SIMULATION OF CONTROL SYSTEMS
4 Dtz%~&y -= ---= ---
PI Controller
Q -z ------
i, bd
1 1 4 -pm-_-.
2s + 1 s+l s+l
(b) FIGURE 3 4 - 4
Process for Example 34.2: (a) liquid-level control system, (b) block diagram. The three tanks are represented by 0.55 M(s) = (2s + l)(S + 1)2
C(s)
(34.32)
The differential equation represented by Eq. (34.32) can be formed by crossmultiplying. The result is (2s + l)(S + l) (s) = 0.55M(s) or (2s3 + 5s2 + 4s + l)C(s) = 0.55M(s) (34.33) Recognizing PC(s) to be the nth derivative of c in the time domain, Q. (34.33) can be written as 2 + 5 % + 4; + c = 0.55m
COMPUTERS IN PROCESS CONTROL
FIGURE 34-5 Reduced diagram of control system for Example 34.2. or i: = -0.52 - 2t - 2.5 + 0.275m (34.34) In order to apply the Rung+Kutta method, we must express Eq. (34.34) as three first-order differential equations. The procedure will now be shown. Let x = c y=i z=% Equation (34.34) can now be written i=y g=z i = -0.5~ - 2y - 2.5~ + 0.275m (34.38) (34.39) (34.40) (34.35) (34.36) (34.37)
We can now summarize the set of first-order differential equations with initial conditions by listing Eqs. (34.38), (34.39), (34.40), and (34.31). In Eq. (34.31), c and have been replaced by x and y according to Eqs. (34.35) and (34.36). Summary of differential equations (34.38) (34.39) (34.40) (34.41)
i = -0.5~ - 2y - 2.5~ + 0.275m riz = K,K,y + (K,K&)(l - x) Initial conditions x(O) = 0 Y(O) = 0 z(O) = 0 m(O) = K,K,
Notice that the control problem has been converted to a state-variable representation in which the state variables am x, y, z, and m. The initial conditions for the state variables x, y, and z are all zero, in keeping with the fact that these variables represent deviation variables that are, by definition, zero initially. In this formulation x, y, and z represent level, derivative of level, and second derivative of level, respectively.
A comment is needed to explain the fact that the initial value of m is K&v. At time zero, the system is disturbed by a unit-step change in set point. This signal is transmitted through the controller block and causes m to jump to KcKV because of the proportional action present in the controller. The Runge-Kutta method will now be applied to solving Eqs. (34.38) to (34.41). The Runge-Kutta equations given by Eqs. (34.11) through (34.21) must, of course, be extended to handle the four differential equations. A BASIC computer pmgram for this problem is shown in Fig. 34.6. The output from running the program is given in Table 34.2.
Example 34.3. Simulation of a control system with transport lag. Consider the
proportional control system in Fig. 34.7 in which a transport lag is located in the feedback path. The equations representing this system are as follows: jl = -gy + +
m = K,e e=r-x x = y(t -T-d)
The difference between this problem and the previous ones considered in this chapter is the presence of a transport lag. In the previous digital simulations, only the current value of y was needed and hence stored. In this problem, we must store values of y over the time interval t - 7d to t (i.e., over the interval rd). Since we
Copyright © OnBarcode.com . All rights reserved.