barcode reader project in asp.net MACRO DEVELOPMENT in Software

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MACRO DEVELOPMENT
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application. In many of the example application programs presented in this book, you ll see that the second or third line of an application is
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#de ne _version 1.00
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Because it is at the top of the source, I can see the version number as soon as the source code is brought up in an editor. This de ne can be used throughout the code to provide the version information without me having to update when I come up with a new version. Often I will output the version information to indicate what source code is burned into the PIC microcontroller. This #de ne statement above can be put into a dt statement and read out of a table using conventional table read code:
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dt Version: , _version, 0
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In this code, each byte of the _version de ne is added to the string of characters used with the dt statement as if the code was entered as
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dt Version: 1.00 , 0
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De ne labels do not have to have strings associated with them. This may seem unusual (and seem to defeat the purpose of de nes), but this allows them to be used as assembly-time execution control ags that I will show later in this chapter. This function allows fast customization of an application modi cation for debug. De nes can be used for many different purposes. While macros can be used only for replacing full lines of text, de nes can simplify instruction programming and provide common information or text strings. Neither macros nor de nes can replace each other, but their functions are complementary and allow you to create richer, more easily programmed and understood applications.
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The Assembler Calculator
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While not really part of the macro processor, the ability of the MPASM assembler (and most compilers) to do constant calculations during assembly or compilation can make applications easier to develop and avoid your having to spend time with a handheld calculator working out the constant values needed in your application. The assembler calculator provides capabilities for both your macros and regular programming that can be taken advantage of in a variety of situations. The assembler calculator works on algebraic equations, similar to how they re used in high level languages. It is important to remember that the calculator works as part of the last pass of the assembler to allow the insertion of data generated during the build cycle, such as the address of an application variable. This can be confusing because variables available for use by the assembler calculator are declared within the source in a manner similar to that of variables used in the application.
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THE ASSEMBLER CALCULATOR
So far in this book you have seen the assembler calculator in operation calculating constant-value arguments for instructions such as
movlw (1 << GIE) | (1 << T0IE)
This instruction loads w register with a byte, destined for the INTCON register, which has the GIE (7) and T0IF (5) bits set. In this case, the assembler calculator is used to change bit numbers to actual values to be loaded into a byte. The trick in this statement is knowing that shifting one by the bit number converts the bit number into a constant value that will set the bit when loaded into a register. This is useful and avoids having to gure out what value is used for speci c bits being set. In the preceding example, if this trick had not been used, I would have to remember (or generate on a calculator) that bit 7 being set is the same as adding 128 and that bit 5 being set is the same as adding 32. The result of these two values is 160 decimal or 0x0A0. Using the assembler calculator, I didn t have to worry about any of this. To reset speci c bits, the same trick can be used, but the bits have to be reset, which is done by a bitwise inversion of the bits and then ANDing the result with the current value. XORing the set bit value with 0x0FF accomplishes the bitwise inversion. For example, to clear bits 4, 2, and 1 in the w register, the following instruction could be used:
andlw 0x0FF ^ ((1 << 4) | (1 << 2) | (1 << 1))
If you were to do this manually, you would have to follow these steps:
1 Calculate the values for bits 4, 2, and 1 being set: (1 << 4) = 16 (1 << 2) = 4 (1 << 1) = 2
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