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This method will take three instruction cycles longer than the previous code, but it requires 12 fewer instructions.
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The code below is really a rearrangement of the preceding snippet. Using the aspect that the high nybble of ASCII A to F is one greater than the high nybble of 0 to 9, a value is conditionally added to make the result 0x000 to 0x00F.
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ASCIItoNybble: addlw 0x0C0 btfss STATUS, C addlw 7 addlw 9 return
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; If A to F , Set the Carry Flag ; If Carry Set, then A - F ; Add Difference Between 9 and A
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Note that ASCII characters other than 0 to 9 and A to F will result in an incorrect result.
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Some time ago, a question came up on the PICList asking if the timer input pin could be used as an interrupt source pin. The answer to this is yes if the timer (and prescaler) is set up so that the next transition will increment the timer and cause an interrupt. Here s some code to do it in a mid-range PIC microcontroller:
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movlw B 11000000 ; First Setup with Instruction Clock option ; as TMR0 Source movlw B 11100000 ; Option Setup for TOCK1 TMR0 Source clrf TMR0 ; Set TMR0 to 0x0FF decf TMR0, f option ; Enable Timer on Outside Interrupt ; Edge ; NOTE - Executing this Instruction ; after decf will Load the ; Synchronizer with a 1
REUSE, RETURN, AND RECYCLE
movlw movwf
0x0A0 INTCON
; Enable TMR0 Over ow Interrupt ; Interrupt will occur when edge received
This code also can be used on a low-end PIC microcontroller to monitor when an input changes instead of continuously polling the input pin.
DIVIDING BY 3
As much as you try to avoid it, sometimes you have to divide. Here s an algorithm from Andy Warren for dividing a positive value by 3 by knowing that divide by 3 can be represented by the series x/3 = x/2 x/4 + x/8 x/16 + x/32 x/64 The algorithm
int DivideBy3( int Value ) Return it { int Quotient = 0; while (Value != 0) { Value = Int(Value / 2); // Quotient + 1/2 if (Value != 0) { Quotient = Quotient + Value; Value = int(Value / 2); // Quotient 1/4 if (Value != 0) Quotient = Quotient - Value; } } return Quotient; } // End DivideBy3 // Divide Value by 3 and
can be implemented in mid-range PIC microcontrollers as
Div3: movwf clrf Div3_Loop: Dividend Quotient ; Loop Until the Dividend == 0 ; Divide Contents of w by 3
APPENDIX G
bcf rrf movf btfsc goto addwf rrf movf btfsc goto subwf goto Div3_Done: movf return
STATUS, C Dividend, f Dividend, w STATUS, Z Div3_Done Quotient Dividend, f Dividend, w STATUS, Z Div3_Done Quotient, f Div3_Loop
; Dividend /2 (ie x/2 in Series) ; Is it Equal to Zero ; If it is, then Stop ; Add the Value to the Quotient ; Dividend /2 (ie x/4 in Series)
; Quotient = Quotient-(Dividend / 4)
Quotient, w
; Return the Quotient
SIXTEEN-BIT COUNTER WITH A CONSTANT LOOP DELAY
When I rst started working with the PIC microcontroller, I thought I was exceedingly clever when I came up with
movlw HiDlay movwf HiCount movlw LoDlay movwf LoCount Dlay: decfsz LoCount, f goto Dlay decfsz HiCount, f goto Dlay ; Load the Delay Values
; Loop Here Until HiCount/LoCount == 0
Then Marc Heuler showed the code
movlw HiDlay ; Load the Delay Values movwf HiCount movlw (LoDlay ^ 0x0FF) + 1 Dlay: addlw 1 ; Increment the Counter by 1 btfsc STATUS, Z decfsz HiCount, f ; Decrement the High Counter goto Dlay
REUSE, RETURN, AND RECYCLE
This loop takes ve cycles to execute regardless of whether or not HiCount is to be decremented (and uses one less le register than my method above). The actual time delay is calculated using the 16-bit number from
Time Dlay = 16BitDlay * 5 ins/loop * 4 clocks/ins / clock frequency
This formula is a lot easier to use than having to (correctly) gure out the delay for the Dlay loop code given above this. In the rst edition of this book, it took three printings to get the rst Dlay loop s delay printed correctly. The rst method is useful if you require approximately a 200,000-instruction-cycle delay. To implement this, rather than loading HiDlay and LoDlay with constants, simply clear them before entering the two decfsz instruction loops.
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