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The following exercise will demonstrate that the cosmological constant has no effect over the scale of the solar system. Start with the general form of the
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Schwarzschild metric ds 2 = e2 (r ) dt 2 e2 (r ) dr 2 r 2 d 2 + sin2 d 2
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With a nonzero cosmological constant, the Ricci scalar for this metric satis es (a) R = (b) R = 0 (c) R = 4 (d) R = It can be shown that (r ) = ln k (r ). If A and B are constants of integration, then (a) r e = A + Br kr 3 (b) r e = A + Br (c) r e = A + Br r 2
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By considering the eld equation R = (a) B = 0 (b) B = k (c) B = 4k
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With the previous results in mind, choosing k =1 we can write the spatial part of the line element as dr 2 (a) dl 2 = + r 2 d 2 + r 2 sin2 d 2 2m 1 1 r3 r 3 dr 2 2 (b) dl = + r 2 d 2 + r 2 sin2 d 2 1 1 r3 3 dr 2 2 (c) dl = + r 2 d 2 + r 2 sin2 d 2 1 1+ r3 3 If the cosmological constant is proportional to the size of the universe, say a =
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(a) the Ricci scalar vanishes (b) particles would experience additional accelerations as revealed in tidal effects (c) the presence of the cosmological constant could not be detected by observations within the solar system
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