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Rain climatic zones. Refer to Table 16.2. (Courtesy of Rec. ITU-R PN.837-1, with permission from the copyright holder ITU. Sole responsibility for the reproduction rests with the author. The complete volume of the ITU material from which the material is extracted can be obtained from the International Telecommunication Union, Sales and Marketing Service, Place des Nations CH-1211, Geneva 20, Switzerland.)
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548 A 0.1 0.8 2 5 8 14 22 0.5 2 3 6 12 21 32 0.7 2.8 5 9 15 26 42 2.1 4.5 8 13 19 29 42 0.6 2.4 6 12 22 41 70 1.7 4.5 8 15 28 54 78 3 7 12 20 30 45 65 2 4 10 18 32 55 83 8 13 20 28 35 45 55 1.5 4.2 12 23 42 70 100 2 7 15 33 60 105 150 B C D E F G H J K L M 4 11 22 40 63 95 120 N 5 15 35 65 95 140 180 P 12 34 65 105 145 200 250 Q 24 49 72 96 115 142 170
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TABLE 16.2
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Rainfall Intensity Exceeded (mm/h) (Refer to Fig. 16.8)
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1.0 0.3 0.1 0.03 0.01 0.003 0.001
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Table 16.2 and Fig. 16.8 reproduced from ITU Recommendation ITU-R PN.837-1 (1994), with permission.
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From Eq. (3.10): A a sina sin ZB Z sin b By inspection, lE angle is: b 15.37
0; therefore, Fig. 3.3d applies and the required azimuth
AZ From Eq. (3.11): d 2R2 263712 a2 GSO
180
195.37
2 # R # aGSO cos b 2 6371 42164 cos 46.04
38019.1 km Equation (3.12) gives the required angle of elevation as El a cosa aGSO d sin bb a cosa 42164 38019.1 sin 46.04 b > 37
As noted in Sec. 3.2, the calculated values for azimuth and elevation provide a guide. Practical adjustments would be made to maximize the received signal. Equation (12.10), with d in km and f in MHz gives: [FSL] 5 32.4 1 20 log d 1 20 log f 5 205.94 dB Adding in the miscellaneous losses, Eq. (12.12) gives the total losses as [LOSSES] 5 [FSL] 1 2 5 207.94 dB The system noise temperature, from Eq. (12.23) is TS Teq Tant 100 70 170 K
In decibels relative to 1 K this is [TS] 10 log TS 22.3 dBK
From Eq. (12.5), with f in GHz and D in ft: G (3.192 f D)2 0.55 (3.192 12.5 1.5)2 1970.1
In decibels this is [G] 10 log 1970.1 32.94 dB
Sixteen
From Eq. (12.35): B Equation (12.53) gives B C N0 R [EIRP] 55 B G T R [LOSSES] 228.6 [K] G T R [G] [TS] 10.64 dBK
86.3 dBHz The downlink bit rate in decibels relative to 1 bps is [Rb] 5 10 log s40 3 106d > 76 dBbps Equation (10.24) gives: B C Eb R 5 B R 2 [Rb] > 10.3 dB N0 N0
As noted in Sec. 16.8, a [Eb/N0] of at least 6 dB is required. The value obtained provides a margin of 4.3 dB under clear-sky conditions.
Example 16.2
Table 16.2 and Fig. 16.8 show the rainfall intensity in mm/h exceeded for given percentages of time. Calculate the upper limit for [Eb/N0] set by the rainfall for the percentage of time equal to 0.01 percent. The earth station is at mean sea level, and the rain attenuation may be assumed entirely absorptive, and the apparent absorber temperature may be taken as 272 K.
Solution
It is first necessary to calculate the attenuation resulting from the rain. The given data are shown below. Because the CCIR formula contains hidden conversion factors, units will not be attached to the data, and it is understood that all lengths and heights are in km, and rain rate is in mm/h. From Fig. 16.8, the earth station is seen to be located within region K. From the accompanying Table 16.2, the rainfall exceeds 42 mm/h for 0.01 percent of the time. Table 4.2 does not give the coefficients for 12.5 GHz; therefore, the values must be found by linear interpolation between 12 and 15 GHz. Denoting the 12-GHz values with subscript 12 and the 15-GHz values with subscript 15, then and using the values from Table 4.2, ah ah12 0.0188 0.0218 ah15 15 ah12 12 0.0188 3 0.5 (12.5 12)
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