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the third constructor to create a temporary String object that duplicates the constant C-string "Natalie B." Then it uses the copy constructor to create the String object sis to duplicate the temporary object. The Assignment Operator The assignment operator is used whenever one object is assigned to another object that has already been declared of the same class. Like the copy constructor, the assignment operator is automatically provided by the compiler if we don't write our own version.
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Note! It is unwise to rely upon the automatically generated assignment operator for classes whose objects contain pointers, because duplicating pointers does not duplicate the data to which they point.
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Example 10.3 Using the Compiler Default Assignment Operator This example shows what can go wrong when you rely upon the automatically generated assignment operator for the String class: String myCar = "Infiniti G20"; String yourCar = "Lexus ES300"; cout <<"\t myCar = [" <<myCar <<"]\n"; cout <<"\tyourCar = [" <<yourCar <<"]\n"; myCar = yourCar; // memberwise assignment cout <<"After: myCar = yourCar\n"; cout <<"\t myCar = [" <<myCar <<"]\n"; cout <<"\tyourCar = [" <<yourCar <<"]\n"; yourCar[6] = 'L'; cout <<"After: yourCar[6] = 'L'\n"; cout <<" MyCar = [" <<myCar <<"]In"; cout <<" yourCar = [" <<yourCar <<"] \n";
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MyCar = [Infiniti G20] yourCar = [Lexus ES300] After: myCar = yourCar MyCar = [Lexus ES300] yourCar = [Lexus ES300] After: yourCar[6] = 'L' MyCar = [Lexus LS300] yourCar = [Lexus LS300]
The default assignment operator uses "member-wise assignment." For our String class, that means that in the fifth statement in main ( ), yourCar. len is assigned to myCar.len and yourCar.buf is assigned to myCar.buf. But the buf members are pointers, so the result is that both yourCar.buf and myCar.buf point to the same C-string in memory: the one that contains "Lexus ES300." So when you buy a new Lexus LS3OO, it becomes my car too! In other words, the assignment myCar = yourCar in this program means that I become a co-owner of your new Lexus LS3OO (and that I lost my Lexus ES3OO). Both objects, yourCar and myCar, point to the same character string in memory. The assignment myCar = yourCar simply duplicated the integer len and the pointer buf, without duplicating the character string. So when the "E" is changed to an "L," it gets changed in both objects. To overcome this problem, we need to define our own assignment operator so that an assignment y = x replaces the object y with a duplicate of the object x. Here is our own assignment operator, defined explicitly: String& String: operator (const String& s) { if (&s == this) return *this; len = s.len; delete [ ] buf; buf = new char[s.len + 1]; strcpy(buf, s.buf); return *this; } First, it checks whether the object s is different from the object to which it is to be assigned. If they are the same object, then nothing more needs to be done. If the two objects are not the same, then we recreate the current object so that it becomes a duplicate of s. After setting len to s. len, we deallocate the memory currently assigned to buf and then allocate a new string of bytes of the correct length (s. len+l). Then we use the strcpy ( ) function (defined in string.h) to copy s.buf into buf and return *this.
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The Addition Operator The addition operator + is a natural choice for the concatenation function in a String class. After all, concatenation means adding two strings together to form a new string. Here is the concatenation function for our String class: String operator+(const const String& s1, const String& s2) { string s(s1.len + s2.len); strcpy(s.buf, s1.buf); strcat(s.buf, s2.buf); return s; }
First, it constructs a String object s of length s1. len+s2. len. Then it uses the strcpy ( ) and strcat ( ) (in <string.h>) to copy s1.buf to s.buf and append s2.buf to it. An Append Operator The += operator is one of a series of arithmetic assignment operators that combine the arithmetic operators (+, -, *, etc.) with the assignment operator.
Don't Forget! Like most operators, the arithmetic assignment operators can be overloaded to perform whatever operations you want. However, it is unwise to define an overloaded operator to do anything that is not similar to the action of the original operator.
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