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Node@7182c1 Node@3f5d07 Node@f4a24a Node@cac268 Node@a16869
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The first node is constructed at line 3. Then the for loop at lines 5 7 constructs the other four nodes. The second for loop at lines 8 10 prints the node data in the first five lines of output. The third for loop at lines 11 13 gives the actual memory addresses of the five Node objects. When you use an object reference like p in a string expression such as
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System.out.println(p);
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the system automatically invokes that object s toString() method. Unless it has been overridden, the version of the toString() method that is defined in the Object class will execute, as it did in the program in Example 3.9. The string returned by that version merely contains the object s type (Node) followed by the @ sign and the memory address of the object (7182c1). So the last five lines of output report that the five Node objects are stored at the (hexadecimal) memory addresses 0x7182c1, 0x3f5d07, 0xf4a24a, 0xcac268, and 0xa16869. These then are the actual values stored in the reference variables start, start.next, start.next.next, start.next.next.next, and start.next.next.next.next. You can see from Figure 3.17 why we usually draw linked lists using arrows to represent the Node references. Showing the actual memory address values instead requires more effort to see which node references which. Moreover, those memory address values are runtime dependent: They will be different on different computers, and maybe even on the same computer at different times. One final note: At line 6 we use the chained assignment
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p = p.next = new Node(22+11*i);
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It is important to remember the order of operations in such a statement. Here, the first thing that happens is the evaluation of the expression 22 + 11*i. When i is 1, that evaluates to 33; when i is 4, it evaluates to 66. After the value is obtained, it is passed to the Node class constructor at line 5 of Example 3.3 on page 50. That constructs a node with that value in its data field and null in its next field. The constructor returns a reference to the Node object. It is that reference that is assigned first to p.next, and then to p. The key is that the assignments are made from right to left. So we know that p is not updated until after its next field is. So, first the next field is set to point to the new node, and then the loop control variable p is advanced to that next node.
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Figure 3.17 The five Node objects
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INSERTING AN ELEMENT INTO A LINKED LIST Recall how new elements were inserted into the linked list that was built in Figure 3.16 on page 53. To simplify the process, we add a two-argument constructor to our Node class, as shown in Example 3.10 on page 56. This allows us to create the node and insert it all at once. Figure 3.18 illustrates the invocation of the two-argument Node constructor. It shows next as a reference to a Node object and x as an int with value 50. Passing these two arguments to the constructor creates a new Node object that contains 50 and whose next field points to the same object that the given next pointer points to. The constructor then returns a reference to the new Node object, which is assigned to q.
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The code for inserting an element into a nonempty linked list is given in Example 3.11. To appreciate its simplicity, compare it with the equivalent method in Example 3.2 on page 49. EXAMPLE 3.10 A Node Class with Two Constructors
1 2 3 4 5 6 7 8 9 10 11 12 13
class Node { int data; Node next; Node(int data) { this.data = data; } Node(int data, Node next) { this.data = data; this.next = next; } }
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