barcode generator for ssrs Let x l ( 1 7 ) be the sequence in Software

Generate Code 128 Code Set A in Software Let x l ( 1 7 ) be the sequence

Let x l ( 1 7 ) be the sequence
Code 128A Recognizer In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
USS Code 128 Encoder In None
Using Barcode creator for Software Control to generate, create Code 128 Code Set C image in Software applications.
Perform the N-point circular convolution of x l ( n ) with lz(n) by forming the product H ( k ) X I(k) and then finding the inverse DFT, y l ( n ) . The first L - 1 values of the circular convolution are aliased, and the last
ANSI/AIM Code 128 Recognizer In None
Using Barcode decoder for Software Control to read, scan read, scan image in Software applications.
Code 128A Generator In Visual C#
Using Barcode printer for Visual Studio .NET Control to generate, create ANSI/AIM Code 128 image in .NET applications.
Discard
Painting Code 128C In Visual Studio .NET
Using Barcode maker for ASP.NET Control to generate, create USS Code 128 image in ASP.NET applications.
Create Code 128 In .NET Framework
Using Barcode creation for .NET framework Control to generate, create Code128 image in Visual Studio .NET applications.
Discard
Code 128C Drawer In VB.NET
Using Barcode maker for .NET framework Control to generate, create USS Code 128 image in VS .NET applications.
Paint Code 128 Code Set B In None
Using Barcode generation for Software Control to generate, create Code 128C image in Software applications.
~ 3 ( 7 4
Bar Code Drawer In None
Using Barcode creator for Software Control to generate, create barcode image in Software applications.
UCC - 12 Generation In None
Using Barcode printer for Software Control to generate, create UPC-A Supplement 5 image in Software applications.
Discard Fig. 6-5. Illustration of the overlap-save method of block convolution.
Make Data Matrix 2d Barcode In None
Using Barcode generation for Software Control to generate, create Data Matrix image in Software applications.
Create Bar Code In None
Using Barcode generator for Software Control to generate, create barcode image in Software applications.
CHAP. 61
MSI Plessey Generator In None
Using Barcode creator for Software Control to generate, create MSI Plessey image in Software applications.
EAN13 Scanner In .NET
Using Barcode decoder for .NET Control to read, scan read, scan image in .NET framework applications.
THE DFT
GTIN - 12 Drawer In Java
Using Barcode generator for Java Control to generate, create UPC A image in Java applications.
UCC.EAN - 128 Generator In Java
Using Barcode generation for BIRT Control to generate, create EAN / UCC - 14 image in Eclipse BIRT applications.
N - L 1 values correspond to the linear. convolution of x ( n ) with h ( n ) . Due to the zero padding at the start of x l ( n ) , these last N - L I values are the first N -- L 1 values of y ( n ) :
Print Bar Code In Java
Using Barcode generator for Java Control to generate, create barcode image in Java applications.
Barcode Decoder In Visual Studio .NET
Using Barcode Control SDK for ASP.NET Control to generate, create, read, scan barcode image in ASP.NET applications.
3. Let x 2 ( n ) be the N-point sequence that is extracted from x ( n ) with the first L - 1 values overlapping with those of x, ( n ) . 4. Perform an N -point circular convolution of x 2 ( n ) with h ( n ) by forming the product H ( k ) X 2 ( k ) and taking the inverse DFT. The first L - I values of y 2 ( n ) are discarded and the final N - L + 1 values are saved and concatenated with the saved values of yl ( n ) :
Reading Barcode In Java
Using Barcode Control SDK for BIRT Control to generate, create, read, scan barcode image in Eclipse BIRT applications.
Read Code128 In None
Using Barcode decoder for Software Control to read, scan read, scan image in Software applications.
Steps 3 and 4 are repeated until all of the values in the linear convolution have been evaluated.
The reason for the name overlap-save is that x ( n ) is partitioned into overlapping sequences of length N and, after performing the N-point circular convolution, only the last N - L 1 values are saved.
Solved Problems
Discrete Fourier Series
Find the DFS expansion of the sequence
Because i ( n ) is periodic with a period N = 4, the DFS coefficients may be found by evaluating the sum
Alternatively, ~fwe express i ( n ) in terns of complex exponentials,
and use the fact that
we may pick efthe DFS coefficients directly as follows. Using the periodicity of the complex exponentials,
we may express f ( n ) as
A 2" + -,J$sn A i(n) = -,IT" 2 2 Comparing Eys. (6.15) and (6.16 ), we see that
THE DFT
[CHAP. 6
If i ( n ) is a periodic sequence with a period N ,
2 ( n ) is also periodic with period 2N. Let g ( k ) denote the DFS coefficients when f ( n ) is considered to be periodic with a period N , and let 2 z ( k ) be the DFS coefficients when the period is assumed to be 2N. Express the DFS coefficientsg 2 ( k ) in terms of g ( k ) .
If we considerP(n) to be periodic with a period 2 N , the DFS coefficients are
BecauseP(n) = P(n
+ N), this sum may be written as
Note that the term in brackets is equal to 2 when k is even, and it is equal to zero when k is odd. When k is even,
Therefore, the DFS coefficients g2(k) are
If i ! ( n )and i z ( n ) are periodic with period N with DFS coefficients2 ( ( k )and x 2 ( k ) ,respectively, show that the sequence with DFS coefficientsf ( k ) = f I ( k ) X z ( k )is equal to the periodic convolution of ,( n ) i I and i 2 ( n ) :
i(n)= xil(k),iz(n -k )
Given that X(k) = X I(k)z2(k),the sequence .P(n) is
Because we would like to express 3(n) in terms of l ( n ) and Pz(n), we begin by substituting
for Xl(k) into Eq. (6.17). With this substitution. we have
Rearranging the sums and combining the exponentials yields I f(n) =
EP( I ) ~=fOz ( k ) e 1 2 " ' n - ' ) k ~ N I=,, k
CHAP. 6 1 Note that
THE DFT
Therefore, we have
as was to be shown.
Let x,(t) be a periodic continuous-time signal
that is sampled with a sampling frequency f, = 1 kHz.Find the DFS coefficients of the sampled signal
Z ( n ) = xa(nTT).
With a sampling frequency f, = 1 kHz, the sampling period is T, = l/f, = IW3. and the sampled signal is J(n) = x,(nTv) = A cos - n
(3 ) + (3)
B cos
The first term is periodic with a period N I= 10, and the second is periodic with a period N2 = 4. Therefore, the sum is periodic with period N = 20, and we may write
Expressingi(n) in terms of complex exponentials, we have J(n) = t e i % 2 n + t e - i % 2 f l
+ L!J%sn
t e - i % ~ n
Using the periodicity of the complex exponentials, it follows that
e-j$$2n
- ej$18n
e-j%5n
== e,%15n
As a result, i ( n ) may be written as J ( ~= ~ )
~ l g 2 +l $ e ~ $ 1 8 " f +9%5n
+ej$$l~n
which is in the form of a DFS decomposition,
Copyright © OnBarcode.com . All rights reserved.