how to generate barcode in ssrs report CIRCUIT ANALYSIS USING SPICE AND PSPICE in Software

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CIRCUIT ANALYSIS USING SPICE AND PSPICE
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.STEP .AC .PROBE .END
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The frequency response is plotted by Probe for the frequency varying from 10 kHz to 10 MHz as shown in Fig. 15-33(b).
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Fig. 15-33
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15.13 Model the op amp of Fig. 15-34(a) as a subcircuit and use it to nd the frequency response of V3 =Vac in Fig. 15-34 b for f varying from 1 MHz to 1 GHz.
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The source le is Closed loop frequency response of ampli er, Fig. 15-34 .SUBCKT OPAMP 1 2 3 4
CIRCUIT ANALYSIS USING SPICE AND PSPICE
[CHAP. 15
Fig. 15-34
CHAP. 15]
CIRCUIT ANALYSIS USING SPICE AND PSPICE
* node * node * node * node * node Rin Cin Rout Eout .ENDS Vac R1 Rf X1 .MODEL .STEP .AC .PROBE .END
1 2 3 4 5
is is is is is
the non-inverting input the inverting input the output the output reference (negative end of dependent source) the positive end of dependent source 1 2 10 E5 1 2 100 pF 3 5 10 k 5 4 1 2 1 E5 1 0 1 2 2 3 0 2 3 0 GAIN LIN LIN AC 10 m 0 10 k Rgain 1 OPAMP RES(R 1 RES Rgain(R) 1 k 801 k 500 1000 k 1 000 000 k
200 k
The frequency response is graphed in Fig. 15-34(c). Compared with the open-loop circuit of Fig. 1533(a), the dc gain is reduced and the bandwidth is increased.
15.14 Referring to the RC circuit of Fig. 15-22, choose the height of the initial pulse such that the voltage across the capacitor reaches 10 V in 0.5 ms. Verify your answer by plotting Vc for 0 < t < 2 ms.
The pulse amplitude A is computed from A 1 e 1=2 10 from which A 25:415 V
We describe the voltage source using PULSE syntax. Pulse-Step Vs R C .TRAN .PROBE .END
The source le is
response of RC, dead beat in RC/2 seconds 1 0 PULSE( 10 25:415 1:0E 6 1:0E 6 0:5 m 3 m 1 2 1k 2 0 1u 1:0E 6 2:0E 3 UIC
The response shape is similar to the graph in Fig. 15-22(b). During the transition period of 0 < t < 0:5 ms, the voltage increases exponentially toward a dc steady state value of 25.415 V. However, at t 0:5 ms, when the capacitor voltage reaches 10 V, the source also has 10 V across it. The current in the resistor becomes zero and steady state is reached.
15.15 Plot the voltage across the capacitor in the circuit in Fig. 15-35(a) for R 0:01
and 4:01
. The current source is a 1 mA square pulse which lasts 1256.64 ms as shown in the i t graph.
Model the resistor as a single-parameter resistor element with a single parameter R and change the value of R from 0.01 to 4.01 in step of 4. We use the .AC command to sweep the frequency from 500 Hz to 3 kHz in 100 steps. The source le is Pulse response of RLC with variable R Is 0 1 Pulse( 0 1 m 100 u 0:01 u 0:01 u R 1 2 LOSS 1 C 1 0 2000 n IC 0 L 2 0 5m IC 0 1256:64 u 5000 u
CIRCUIT ANALYSIS USING SPICE AND PSPICE
[CHAP. 15
.MODEL .STEP .TRAN .PROBE .END
LOSS RES 10 u
RES R 1 LOSS(R) .01 4.01 4 3500 u 0 1u UIC
The result is shown in Fig. 15-35(b). The transient response is almost zero for R 0:01
. This is because pulse width is a multiple of the period of natural oscillations of the circuit.
Fig. 15-35
CHAP. 15]
CIRCUIT ANALYSIS USING SPICE AND PSPICE
Supplementary Problems
In the following problems, use PSpice to repeat the indicated problems and examples.
15.16 15.17 15.18 15.19 15.20 15.21 15.22 15.23 15.24 15.25 15.26 15.27 15.28 15.29 15.30 15.31 15.32 15.33 15.34 15.35 15.36 15.37 15.38 15.39 15.40 15.41 15.42 15.43 15.44 15.45 15.46 Solve Example 5.9 (Fig. 5-12). Solve Example 5.11 (Fig. 5-16). Solve Example 5.14 (Fig. 5-20). Solve Example 5.15 (Fig. 5-21). Solve Example 5.20 (Fig. 5-28) for x t 1 V. Solve Problem 5.12 (Fig. 5-37). Solve Problem 5.16 (Fig. 5-39). Solve Problem 5.25 (Fig. 5-48). Solve Problem 5.26 (Fig. 5-49). Solve Problem 5.48 (Fig. 5-55) for vs1 vs2 1 V. Solve Example 7.3. Solve Example 7.6 (Fig. 7-12). Solve Example 7.7 [Fig. 7-13(a)]. Solve Example 7.11 [Fig. 7-17(a)]. Solve Problem 8.27 (Fig. 8-31). Solve Problem 9.11 (Fig. 9-20). Solve Problem 9.18 (Fig. 9-28). Solve Problem 9.19 (Fig. 9-29). Solve Example 11.5 [Fig. 11-15(a)]. Solve Example 11.6 [Fig. 11-16(a)]. Solve Example 11.7 (Fig. 11-17). Solve Problem 12.7. Solve Problem 12.14 (Fig. 12-40). Solve Problem 12.16 (Fig. 12-43). Solve Problem 13.28 (Fig. 13-31) for s j. Solve Problem 13.31 (Fig. 13-33) Solve Problem 14.8 (Fig. 14-24). Solve Problem 14.12 (Fig. 14-28). Solve Problem 14.13 (Fig. 14-29) Solve Problem 14.20 (Fig. 14-35) Solve Problem 14.21 (Fig. 14-36) for s j.
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