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For the ampli er of Fig. 3-10, show that if the source internal impedance Ri is not negligible, but Ri ( RB R1 kR2 , then the low-frequency cuto point is given by !L hie Ri hfe 1 RE RE CE hie Ri
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Show that, for the ampli er of Fig. 3-10 as described in Problem 8.5, if RB ) RE hie , then the current-gain ratio becomes independent of frequency. In the ampli er of Fig. 3-10, let CC ! 1; CE 100 F; RE 20 k; hie 100 ; hfe 75, RC RL 2 k, R1 2 k, and R2 20 k. Determine (a) the low-frequency current gain, (b) the midfrequency current gain, and (c) the low-frequency cuto point. Ans: a 3:11; b 35:54; c 5:71 rad/s In the ampli er of Problem 8.6, let Ri 500  and all else remain unchanged. Determine the value of the emitter bypass capacitor required to ensure that fL 200 Hz. Compare your result with that of Problem 8.6 to see that consideration of the source internal impedance allows the use of a smaller bypass capacitor. (Hint: See Problem 8.31.) Ans: CE ! 101:3 F In the ampli er of Fig. 3-10, CC ! 1, Ri 500 , RE 30 k, R1 3:2 k, R2 17 k, RL 10 k, hoe hre 0, hfe 100, and hie 100 . Determine RC and CE so that the ampli er has a midfrequency current-gain ratio jAi j ! 30 with low-frequency cuto fL ! 20 Hz. (Hint: See Problem 8.5.) Ans: RC ! 4517:8 ; CE ! 3:13 F In the CE ampli er of Fig. 3-10, let CC ! 1, CE 100 F, RE 100 , Ri 0, RB 5 k, RC RL 2 k, hoe hre 0, hfe 75, and hie 1 k. The small-signal ac equivalent circuit is given by Fig. 8-4. If a sinusoidal signal vi Vm sin !t is impressed (with ! 400 rad/s), determine (a) the phase angle between vi and ii , (b) the phase shift between input and output voltages, and (c) the phase shift between input and output currents. Ans: a Current leads voltage by 35.528; (b) output voltage lags input voltage by 128.988; (c) output current lags input current by 1808 In the ampli er of Problem 8.13, let CE 200 F, CC 10 F, RE 50 , RC RL 2 k, Ri 100, hre hoe 0, hie 1 k, and hfe 50. (a) Sketch the asymptotic Bode plot (Mdb only) for the voltage-gain ratio. (b) Is the 3-db attenuation point below 40 Hz Ans: a Av s 0:548s 0:01s 1 = 0:04s 1 0:00301s 1 . The associated Bode plot is given in Fig. 8-30; (b) no, because Mdb j1 Mdb j80 3:79 db In the CE ampli er of Example 8.7, let gm 0:035 S, r 8 k, rx 30 , RC RL 10 k, C 10 pF, and C 2 pF. (a) Determine the high-frequency cuto point. (b) Find the midfrequency gain. Ans: a fH 16:49 MHz; b Avmid 174:3 In the CB ampli er of Problem 8.17, let RS 100 ; RE 1 k; RC RL 10 k; C 2 pF; C 40 pF; gm 0:035 S; and r 5 k. Determine (a) the midfrequency gain and (b) the high-frequency cuto point. Ans: a Avmid 37:88; b fH 15:91 MHz Add a source resistance Ri to the high-frequency small-signal equivalent circuit for the CS ampli er given by Fig. 8-11. Let Cgs 3 pF; Cds 1 pF; Cgd 2:7 pF; rds 50 k; gm 0:016 S; RL RD 2 k, and RG 1 M. Determine the high-frequency cuto point (a) with Ri 0 and (b) with Ri 100. Ans: a fH 43:875 MHz; b fH 13:69 MHz For the hybrid- model of a CB BJT ampli er circuit given by Fig. 8-24, let RE 200 , RC RL 10 k, rx 25 , r 5 k, gm 0:02 S, and C C 2 pF. Use SPICE methods to determine the midfrequency voltage gain and the high-frequency cuto point. (Netlist code available at the author s website.) Ans: Avmid 100, fH 16:1 MHz
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