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barcode font reporting services 3.84, we reject the hypothesis in Software
3.84, we reject the hypothesis Reading Quick Response Code In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. QR Encoder In None Using Barcode drawer for Software Control to generate, create Quick Response Code image in Software applications. (b) The critical value x2 for 1 degree of freedom is 6.63. Then since 4.50 6.63, we cannot reject the 0.99 hypothesis that the coin is fair at a 0.01 level of significance. We conclude that the observed results are probably significant and the coin is probably not fair. For a comparison of this method with previous methods used, see Method 1 of Problem 7.36. (c) The P value is P(x2 P 0.039. 4.50). The table in Appendix E shows 0.025 P 0.05. By computer software, Decoding Quick Response Code In None Using Barcode scanner for Software Control to read, scan read, scan image in Software applications. Generating QR In C# Using Barcode maker for .NET Control to generate, create QR Code 2d barcode image in Visual Studio .NET applications. 7.35. Work Problem 7.34 using Yates correction.
Quick Response Code Creator In .NET Using Barcode encoder for ASP.NET Control to generate, create QR Code image in ASP.NET applications. Paint QR Code ISO/IEC18004 In .NET Framework Using Barcode creation for .NET Control to generate, create QR Code image in .NET framework applications. x2 (corrected) (u x (u115 1 np1 u np1 100u 100 0.5)2 0.5)2 (u x2 ( u 85 np2 u np2 100 u 100 0.5)2 0.5)2 (14.5)2 100 (14.5)2 100 QR Code Printer In VB.NET Using Barcode generation for VS .NET Control to generate, create QR Code image in VS .NET applications. Drawing Code 128 Code Set A In None Using Barcode drawer for Software Control to generate, create Code 128 Code Set B image in Software applications. The corrected P value is 0.04 Since 4.205 3.84 and 4.205 6.63, the conclusions arrived at in Problem 7.34 are valid. For a comparison with previous methods, see Method 2 of Problem 7.36. Barcode Creation In None Using Barcode creator for Software Control to generate, create barcode image in Software applications. Print ECC200 In None Using Barcode generator for Software Control to generate, create Data Matrix ECC200 image in Software applications. 7.36. Work Problem 7.34 by using the normal approximation to the binomial distribution.
EAN / UCC  14 Creation In None Using Barcode generator for Software Control to generate, create EAN / UCC  14 image in Software applications. Paint GTIN  13 In None Using Barcode drawer for Software Control to generate, create EAN13 image in Software applications. Under the hypothesis that the coin is fair, the mean and standard deviation of the number of heads in 200 tosses of a coin are m np (200)(0.5) 100 and s !(200)(0.5)(0.5) 7.07. !npq Method 1 115 heads in standard units (115 100) > 7.07 2.12. USS Codabar Generator In None Using Barcode maker for Software Control to generate, create Ames code image in Software applications. Bar Code Reader In Java Using Barcode reader for Java Control to read, scan read, scan image in Java applications. Using a 0.05 significance level and a twotailed test, we would reject the hypothesis that the coin is fair if the z score were outside the interval 1.96 to 1.96. With a 0.01 level the corresponding interval would be 2.58 to 2.58. It follows as in Problem 7.34 that we can reject the hypothesis at a 0.05 level but cannot reject it at a 0.01 level. The P value of the test is 0.034. Note that the square of the above standard score, (2.12)2 4.50, is the same as the value of x2 obtained in Problem 7.34. This is always the case for a chisquare test involving two categories. See Problem 7.60. Method 2 Using the correction for continuity, 115 or more heads is equivalent to 114.5 or more heads. Then 114.5 in standard units (114.5 100) > 7.07 2.05. This leads to the same conclusions as in the first method. The corrected P value is 0.04. Note that the square of this standard score is (2.05)2 4.20, agreeing with the value of x2 corrected for continuity using Yates correction of Problem 7.35. This is always the case for a chisquare test involving two categories in which Yates correction is applied, again in consequence of Problem 7.60. Reading Data Matrix ECC200 In None Using Barcode scanner for Software Control to read, scan read, scan image in Software applications. Generating UCC  12 In .NET Using Barcode drawer for VS .NET Control to generate, create UCC.EAN  128 image in .NET framework applications. 7.37. Table 710 shows the observed and expected frequencies in tossing a die 120 times. (a) Test the hypothesis that the die is fair, using a significance level of 0.05. (b) Find the P value of the test. Code 39 Extended Maker In ObjectiveC Using Barcode encoder for iPad Control to generate, create Code39 image in iPad applications. UPC  13 Generation In ObjectiveC Using Barcode drawer for iPhone Control to generate, create EAN / UCC  13 image in iPhone applications. CHAPTER 7 Tests of Hypotheses and Significance
Printing Code 128 In .NET Framework Using Barcode creator for Reporting Service Control to generate, create Code 128A image in Reporting Service applications. EAN 13 Printer In None Using Barcode generation for Online Control to generate, create EAN 13 image in Online applications. (a) Face 1 25 20 Table 710 2 17 20 3 15 20 4 23 20 5 24 20 6 16 20 Observed Frequency Expected Frequency
(x1 (25 20 np1)2 np1 20)2 (x2 (17 20 np2)2 np2 20)2 (x3 (15 np3)2 np3 20)2 20 (x4 (23 np4)2 np4 20)2 20 (x5 (24 np5)2 np5 20)2 20 (x6 (16 np6)2 np6 20)2 20 5.00 Since the number of categories or classes (faces 1, 2, 3, 4, 5, 6) is k 6, n k 1 6 1 5. The critical value x2 for 5 degrees of freedom is 11.1. Then since 5.00 11.1, we cannot reject the 0.95 hypothesis that the die is fair. For 5 degrees of freedom x2 1.15, so that x2 5.00 1.15. It follows that the agreement is not so 0.05 exceptionally good that we would look upon it with suspicion. (b) The P value of the test is P(x2 software, P 0.42. 5.00). The table in Appendix E shows 0.25 P 0.5. By computer 7.38. A random number table of 250 digits had the distribution of the digits 0, 1, 2, . . . , 9 shown in Table 711. (a) Does the observed distribution differ significantly from the expected distribution (b) What is the P value of the observation (a) Digit Observed Frequency Expected Frequency (17 25 0 17 25 1 31 25 2 29 25 Table 711 3 18 25 4 14 25 5 20 25 6 35 25 7 30 25 8 20 25 9 36 25 25)2 (31 25 25)2 (29 25 25)2 (18 25 25)2 (36 25 25)2 The critical value x2 for n k 1 9 degrees of freedom is 21.7, and 23.3 21.7. Hence we 0.99 conclude that the observed distribution differs significantly from the expected distribution at the 0.01 level of significance. Some suspicion is therefore upon the table. (b) The P value is P(x2 23.3). The table in Appendix E shows that 0.005 software, P 0.0056. P 0.01. By computer 7.39. In Mendel s experiments with peas he observed 315 round and yellow, 108 round and green, 101 wrinkled and yellow, and 32 wrinkled and green. According to his theory of heredity the numbers should be in the proportion 9:3:3:1. Is there any evidence to doubt his theory at the (a) 0.01, (b) 0.05 level of significance (c) What is the P value of the observation The total number of peas is 315 108 101 32 556. Since the expected numbers are in the proportion 9:3:3:1 (and 9 3 3 1 16), we would expect 9 (556) 16 3 (556) 16 312.75 round and yellow 104.25 round and green 3 (556) 16 1 (556) 16 104.25 wrinkled and yellow 34.75 wrinkled and green

