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ssrs 2012 barcode font Nonparametric Tests in Software
CHAPTER 10 Nonparametric Tests Scan Quick Response Code In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. Denso QR Bar Code Printer In None Using Barcode creation for Software Control to generate, create QRCode image in Software applications. 10.2. Work Problem 10.1 by using a normal approximation to the binomial distribution.
Recognize Quick Response Code In None Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications. Create QR In Visual C#.NET Using Barcode generation for .NET framework Control to generate, create Denso QR Bar Code image in .NET framework applications. For a normal approximation to the binomial distribution, we use the fact that the z score corresponding to the number of heads is Z X s m X Np !Npq . QR Code Encoder In .NET Framework Using Barcode encoder for ASP.NET Control to generate, create QR image in ASP.NET applications. Creating QR In .NET Framework Using Barcode creation for .NET framework Control to generate, create QR Code image in .NET framework applications. Because the variable X for the binomial distribution is discrete while that for a normal distribution is continuous, we make a correction for continuity (for example, 3 heads are really a value between 2.5 and 3.5 heads). This amounts to decreasing X by 0.5 if X Np and to increasing X by 0.5 if X Np. Now N 12, m Np (12)(0.5) 6, and s !(12)(0.5)(0.5) 1.73, so that !Npq z (3 0.5) 1.73 6 1.45 Make QR Code ISO/IEC18004 In VB.NET Using Barcode drawer for .NET Control to generate, create Denso QR Bar Code image in .NET applications. Draw EAN / UCC  13 In None Using Barcode maker for Software Control to generate, create GTIN  13 image in Software applications. Since this is greater than 1.96 (the value of z for which the area in the lefthand tail is 0.025), we arrive at the same conclusion in Problem 10.1. Note that Pr5Z 1.456 0.0735, which agrees very well with the Pr5X 3 heads6 0.07299 of Problem 10.1. Make Barcode In None Using Barcode maker for Software Control to generate, create barcode image in Software applications. Encoding Bar Code In None Using Barcode creator for Software Control to generate, create bar code image in Software applications. 10.3. The PQR Company claims that the lifetime of a type of battery that it manufactures is more than 250 hours. A consumer advocate wishing to determine whether the claim is justified measures the lifetimes of 24 of the company s batteries; the results are listed in Table 103. Assuming the sample to be random, determine whether the company s claim is justified at the 0.05 significance level. Table 103 271 253 264 230 216 295 198 262 211 275 288 252 282 236 294 225 291 243 284 253 272 219 224 268 USS128 Creation In None Using Barcode maker for Software Control to generate, create UCC.EAN  128 image in Software applications. Code 3 Of 9 Creator In None Using Barcode encoder for Software Control to generate, create Code 3/9 image in Software applications. Let H0 be the hypothesis that the company s batteries have a lifetime equal to 250 hours, and let H1 be the hypothesis that they have a lifetime greater than 250 hours. To test H0 against H1, we can use the sign test. To do this, we subtract 250 from each entry in Table 103 and record the signs of the differences, as shown in Table 104. We see that there are 15 plus signs and 9 minus signs. Table 104 Paint EAN8 In None Using Barcode drawer for Software Control to generate, create EAN8 Supplement 5 AddOn image in Software applications. Printing EAN 13 In ObjectiveC Using Barcode generator for iPad Control to generate, create GS1  13 image in iPad applications. Fig. 102 Scan Bar Code In Visual Studio .NET Using Barcode decoder for .NET framework Control to read, scan read, scan image in VS .NET applications. Encoding Data Matrix 2d Barcode In Java Using Barcode encoder for Java Control to generate, create Data Matrix image in Java applications. Using a onetailed test at the 0.05 significance level, we would reject H0 if the z score were greater than 1.645 (Fig. 102). Since the z score, using a correction for continuity, is z (15 0.5) (24)(0.5) 1.02 Paint Bar Code In None Using Barcode drawer for Font Control to generate, create bar code image in Font applications. Painting UPCA In None Using Barcode generator for Word Control to generate, create UPC A image in Office Word applications. !(24)(0.5)(0.5) Matrix 2D Barcode Encoder In Visual C#.NET Using Barcode generator for Visual Studio .NET Control to generate, create Matrix Barcode image in VS .NET applications. Barcode Maker In ObjectiveC Using Barcode maker for iPhone Control to generate, create barcode image in iPhone applications. the company s claim cannot be justified at the 0.05 level.
10.4. A sample of 40 grades from a statewide examination is shown in Table 105. Test the hypothesis at the 0.05 significance level that the median grade for all participants is (a) 66, (b) 75. CHAPTER 10 Nonparametric Tests
Table 105 71 78 67 73 67 46 95 40 55 84 70 78 64 93 43 70 82 72 70 64 66 54 73 86 74 78 57 76 58 86 64 62 79 48 60 95 61 52 83 66 (a) Subtracting 66 from all the entries of Table 105 and retaining only the associated signs gives us Table 106, in which we see that there are 23 pluses, 15 minuses, and 2 zeros. Discarding the 2 zeros, our sample consists of 38 signs: 23 pluses and 15 minuses. Using a twotailed test of the normal distribution with probabilities 1 0.025 in each tail (Fig. 103), we adopt the following decision rule: 2 (0.05) Accept the hypothesis if 1.96 Reject the hypothesis otherwise. Table 106 0 z 1.96. Fig. 103 Since
0.5) (38)(0.5) !Npq
!(38)(0.5)(0.5) we accept the hypothesis that the median is 66 at the 0.05 level. Note that we could also have used 15, the number of minus signs. In this case z with the same conclusion. (b) Subtracting 75 from all the entries in Table 105 gives us Table 107, in which there are 13 pluses and 27 minuses. Since z (13 0.5) (40)(0.5) !(40)(0.5)(0.5) 2.06 (15 0.5) (38)(0.5) !(38)(0.5)(0.5) 1.14 we reject the hypothesis that the median is 75 at the 0.05 level. Table 107 Using this method, we can arrive at a 95% confidence interval for the median grade on the examination. (see Problem 10.30.) The Mann Whitney U test 10.5. Referring to Table 102, determine whether there is a difference at the 0.05 significance level between cables made of alloy I and alloy II. We organize the work in accordance with steps 1, 2, and 3 (described earlier in this chapter):

