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ssrs export to pdf barcode font (g) The probability of neither four nor club can be denoted by P(4r > Cr). But 4r > Cr in Software
(g) The probability of neither four nor club can be denoted by P(4r > Cr). But 4r > Cr QR Reader In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. Making QR Code In None Using Barcode generation for Software Control to generate, create QR Code JIS X 0510 image in Software applications. CHAPTER 1 Basic Probability
Read Denso QR Bar Code In None Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications. Encoding QR Code In C#.NET Using Barcode encoder for Visual Studio .NET Control to generate, create QR Code JIS X 0510 image in Visual Studio .NET applications. Therefore, P(4r > Cr) P[(4 < C)r] 1 1 1 P(4 < C) [P(4) B 1 13 P(C) 1 4 1 R 52 P(4 > C)] 9 13 Generating QR Code JIS X 0510 In Visual Studio .NET Using Barcode drawer for ASP.NET Control to generate, create QR Code ISO/IEC18004 image in ASP.NET applications. QRCode Drawer In VS .NET Using Barcode creation for VS .NET Control to generate, create Denso QR Bar Code image in .NET framework applications. We could also get this by noting that the diagram favorable to this event is the complement of the event shown circled in Fig. 18. Since this complement has 52 16 36 sample points in it and each sample point is assigned probability 1 > 52, the required probability is 36 > 52 9 > 13. QR Code JIS X 0510 Printer In VB.NET Using Barcode encoder for Visual Studio .NET Control to generate, create QR Code image in VS .NET applications. Generating Code 128 Code Set B In None Using Barcode generator for Software Control to generate, create Code 128B image in Software applications. Fig. 18 Code39 Encoder In None Using Barcode printer for Software Control to generate, create Code 39 Extended image in Software applications. Make Barcode In None Using Barcode creation for Software Control to generate, create bar code image in Software applications. 1.7. A ball is drawn at random from a box containing 6 red balls, 4 white balls, and 5 blue balls. Determine the probability that it is (a) red, (b) white, (c) blue, (d) not red, (e) red or white. Creating EAN128 In None Using Barcode maker for Software Control to generate, create UCC  12 image in Software applications. Create Bar Code In None Using Barcode generator for Software Control to generate, create barcode image in Software applications. (a) Method 1 Let R, W, and B denote the events of drawing a red ball, white ball, and blue ball, respectively. Then P(R) ways of choosing a red ball total ways of choosing a ball 6 4 6 15 2 5 Leitcode Maker In None Using Barcode creation for Software Control to generate, create Leitcode image in Software applications. Generating 2D Barcode In Visual C#.NET Using Barcode printer for .NET framework Control to generate, create Matrix Barcode image in VS .NET applications. Method 2 Our sample space consists of 6 4 5 15 sample points. Then if we assign equal probabilities 1 > 15 to each sample point, we see that P(R) 6 > 15 2 > 5, since there are 6 sample points corresponding to red ball. 4 4 (b) P(W) 6 4 5 15 5 5 1 (c) P(B) 6 4 5 15 3 2 3 (d) P(not red) P(Rr) 1 P(R) 1 by part (a). 5 5 (e) Method 1 P(red or white) P(R < W ) ways of choosing a red or white ball total ways of choosing a ball 6 6 4 4 5 10 15 2 3 EAN128 Decoder In Visual Basic .NET Using Barcode scanner for Visual Studio .NET Control to read, scan read, scan image in .NET framework applications. Creating Linear 1D Barcode In .NET Using Barcode printer for .NET framework Control to generate, create Linear image in VS .NET applications. This can also be worked using the sample space as in part (a). Method 2 P(R < W) P(Br) 1 P(B) 1 1 3 2 by part (c). 3 Data Matrix 2d Barcode Creation In ObjectiveC Using Barcode generator for iPhone Control to generate, create DataMatrix image in iPhone applications. Create Data Matrix In Java Using Barcode creation for Java Control to generate, create ECC200 image in Java applications. Method 3 Since events R and W are mutually exclusive, it follows from (4), page 5, that P(R < W) P(R) P(W) 2 5 4 15 2 3 EAN / UCC  13 Maker In ObjectiveC Using Barcode creation for iPhone Control to generate, create EAN 128 image in iPhone applications. Encoding EAN / UCC  13 In None Using Barcode printer for Font Control to generate, create EAN 128 image in Font applications. CHAPTER 1 Basic Probability
Conditional probability and independent events 1.8. A fair die is tossed twice. Find the probability of getting a 4, 5, or 6 on the first toss and a 1, 2, 3, or 4 on the second toss. Let A1 be the event 4, 5, or 6 on first toss, and A2 be the event 1, 2, 3, or 4 on second toss. Then we are looking for P(A1 > A2). Method 1 P(A1 > A2) P(A1) P(A2 u A1) P(A1) P(A2) 3 4 6 6 1 3 We have used here the fact that the result of the second toss is independent of the first so that P(A2 u A1) P(A2). Also we have used P(A1) 3 > 6 (since 4, 5, or 6 are 3 out of 6 equally likely possibilities) and P(A2) 4 > 6 (since 1, 2, 3, or 4 are 4 out of 6 equally likely possibilities). Method 2 Each of the 6 ways in which a die can fall on the first toss can be associated with each of the 6 ways in which it can fall on the second toss, a total of 6 6 36 ways, all equally likely. Each of the 3 ways in which A1 can occur can be associated with each of the 4 ways in which A2 can occur to give 3 4 12 ways in which both A1 and A2 can occur. Then P(A1 > A2) This shows directly that A1 and A2 are independent since P(A1 > A2) 1 3 12 36 1 3 1.9. Find the probability of not getting a 7 or 11 total on either of two tosses of a pair of fair dice. The sample space for each toss of the dice is shown in Fig. 19. For example, (5, 2) means that 5 comes up on the first die and 2 on the second. Since the dice are fair and there are 36 sample points, we assign probability 1 > 36 to each. 3 4 6 6 P(A1) P(A2) Fig. 19 If we let A be the event 7 or 11, then A is indicated by the circled portion in Fig. 19. Since 8 points are included, we have P(A) 8 > 36 2 > 9. It follows that the probability of no 7 or 11 is given by P(Ar) 1 P(A) 1 2 9 7 9

