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The declaration Vet tor u ; would construct the vector u having 1 element with the value 0.0; the declaration Vet t or v ( 4 ) ; would construct the vector v with 4 elements all with the value 0.0; and the declaration Vector w( 8, 3.14159) ; would construct the vector w with 8 elements all with the value 3.14159. This constructor uses the initialization list s i ze ( s z > to assign the argument s z to the data member s i z e. Then it uses the new operator to allocate that number of elements to the array data. Finally, it initializes each element with the value t. The copy constructor is almost the same as the default constructor: Vector: :Vector(const Vector& v) : size(v.size)
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data = new double[v.size]; for (int i = 0; i < size; i++) data[i] = v.data[i];
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It uses the data members of the vector argument v to initialize the object being constructed. So it assigns v . s i z e to the new object s s i z e member, and it assigns v . data [ i ] to the elements of the new object s data member. The destructor simply restores the storage allocated to the data array and then sets data to NULL and size too: Vector:: -Vector() { delete [] data; data = NULL; size = 0;
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The overloaded assignment operator creates a new object that duplicates the vector v: const Vector& Vector: :operator=(const Vector& -l if (&v != this) { delete [] data; size = v.size; data = new double[v.size]; for (int i = 0; i < size; i++) data[i] = v.data[i]; > return *this; v)
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The condition ( &v ! = thi s ) determines whether the object that owns the call is different from the vector v. If the address of v is the same as this (which is the address of the current object), then they are the same object and nothing needs to be done. This check is a safety precaution to guard against the possibility that an object might, directly or indirectly, be assigned to itself, like this: w = v = w; . Before creating a new object, the function restores the allocated data array. Then it copies the vector v the same way that the copy constructor did.
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[CHAP. 9
The overloaded subscript operator simply returns the i double& Vector: :operator[] (int i) const data[i];
th component of the object s data
array:
return
Supplementary Programming Problems
9.15 Implement the addition and division operators for the Rat i onal
class (see Example 9.1).
9.16 Implement the operators + =, - = , a n d /= for the Rational class (see Example 9.1). 9.17 Implement the other five relational operators (c, >, < =, >=, and ! =) for the Rational class
(see Example 9.1).
9.18 Rewrite the overloaded input operator for the Rat ional class (Example 9.9) so that, instead
of prompting for the numerator and denominator, it reads a fraction type as 2 2 / 7 .
9.19 Implement a conversion operator in the Rat ional class to convert to float type. 9.20 Implement a conversion operator in the Rational class to round to in t type. 9.21 Implement pre-decrement and post-decrement operator in the Rat ional class. 9.22 Implement an exponentiation operator for the Rat ional class with prototype: Rational operator&&(const Rational&, const unsigned&);
For example, if x represents the fraction 2/5, then x&&4 would return the Rat ional that represents the fraction 16/625.
9.23 Implement an exponentiation operator for the Rat i onal class with prototype: Rational operator&&(const Rational&, const irk&);
For example, if x represents the fraction 2/5, then xscsc - 4 would return the Rat ional that represents the fraction 625/16. (See Problem 9.22.)
9.24 Implement addition for the Vet t or class (Problem 9.14) by overloading the + operator. 9.25 Implement subtraction for the vet tor class (Problem 9.14) by overloading the - operator. 9.26 Implement scalar multiplication for the Vector class (Problem 9.14) by overloading the * operator. If t is a double and v is a vector, then t *V would return the Vet tor obtained by multiplying each element of v by t. 9.27 Implement an inner product (i.e., the dot product ) for the Vet tor class (Problem 9.14) by overloading the * operator. If v and w are vectors, then V*W would return the double
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