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main0 1 String x("ABCDEFGHIJKLABCDEFGHIJKL"); String y("FGH"); tout <c x.firstLocation(y) << endl; tout << x.firstLocation(y, 8) << endl; tout <c x.firstLocation(y, 20) << endl; String z("FGZ"); tout c< x.firstLocation(z) << endl; )
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Implement and test the other five comparison operators ! =, <, < =, >, and >= for the S t r ing class directly, without using functions from the standard s tr ing . h header file. Implement and test the following constructor for the string class: String(const char* s, unsigned n, unsigned k=O); This has the same effect as our third constructor, except that it uses n characters from the Cstring S, beginning with character s [ k ] . For example, the declarations String x("ABCDEFGHIJKL", 3); String y("ABCDEFGHIJKL", 3, 5); would construct the object x representing the substring I ABC I and the object Y representing the substring I FGH 'I. Implement and test the following modification of the copy constructor for the string class: String(const String& s, unsigned n, unsigned k=O); This uses n characters from the object s, beginning with character s . bu f [ k] . For example, if x is a String object representing " ABCDEFGHI JKL II, then String y(x, 3); String z(x, 3, 5); would construct the object Y representing the substring I ABC I and the object z representing the substring I FGH II. (See Problem 10.9.) Implement and test the following member function for the string class: int frequency(char c); This returns the number of occurrences of the character c in the string For example, is x is the string "Mississippi", then the call frequency ( Ii I) would return 4.
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A String CLASS
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10.12 Implement and test the following member function for the string class: void remove(unsigned n, unsigned k=O); This removes n characters from the object, beginning with character buf [ k] . For example, String x("ABCDEFGHIJKL"); x.remove(3, 5); would remove the substring I FGH I from the object X, changing it to " ABCDEI JKL I'. lo.13 Implement and test the following member function for the String class: void insert(const String& s, unsigned k=O); This inserts the string s into the current object, beginning with character buf [ k] . For example, String x("ABCDEFGHIJKL"); String y("XYZ"); x.insert(y, 5); would insert I XYZ I into the object X, changing it to " ABCDEXYZFGHI JKL II. Note that the third constructor would be invoked automatically to produce the same effect from the call: x.insert("XYZ", 5); Also note that x. insert (y> prepends y to x, and that x. insert (y, x. n ( > > is equivalent to x + = y, appending y to X. 10.14 Implement and test the following member function for the String class: void replace(const String& s, unsigned n, unsigned k=O); This replaces n characters from the object, beginning with character buf [k] with string S: String x("ABCDEFGHIJKL"); String y("XYZ"); x.replace(y, 6, 5); would replace the substring " FGHI JK " in the object x with the string s, changing x to "ABCDEXYZL". Note that the third constructor would be invoked automatically to produce the same effect from the call: x.replace("XYz", 6, 5); Also note that x . replace ( y , m, n > ; is equivalent to x.remove(6, 5); x.insert("XYZ", 5); 10.15 Implement and test the following member function for the String class: int lastLocation(const String& s, unsigned k=O); This searches the object s buffer, beginning with character buf [k] for the string S. If s is found to be a substring, then the index of its last occurrence is returned; otherwise -1 is returned. For example, String x("ABCDEFGHIJKLABCDEFGHIJKL"); String y("FGH"); tout << x.lastLocation(y) << endl; tout << x.lastLocation(y, 20) << endl; String z("FGZ"); tout << x.lastLocation(z) << endl; would print 17, -1, and -1. (See Problem 10.7.)
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