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class template with
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the enhancements added in Problem 13.38.
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13.36 Implement a copy constructor for the Li s List(const List<T>&);
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13.37 Implement the assignment operator for the Li s t class template: ListcT>& operator=(const List<T>&); 13.38
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Add the following two member functions to the Li s
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void insertAtEnd(T t); int removeFromEnd(T& t);
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// insert t at the end of the list // remove last item t from the list
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Add the following member functions to the Li s
void append(const List<T>&);
class template:
This function appends the list passed to it to the list that owns the function call. It does not create any new nodes.
13.40 Modify the Li
class template by adding a dummy node to the end of each list. The dummy node will act like a newline character in that it signals the end of the list. It is identified as the only node whose next pointer points to itself. Its data field is not used.
TEMPLATES AND ITERATORS
[CHAP. 13
Add the following member functions to the Li s t class template:
void reverse();
This function reverses the list, like this:
void reverse();
Do it two ways. First, do it by moving the actual data, using a stack. Then do it in place by changing pointers and not moving any data.
Add the following member functions to the Li s t class template:
void merge(const List<T>&);
This function merges the list passed to it with the list that owns the function call. It assumes that both lists are sorted in increasing order, and thus requires that the order operators <, >, etc., are defined for the type T. It does not create any new nodes.
13.43 Modify the insert ( > function in the List class template so that it maintains the list in
increasing order. This presupposes that only types and classes that have implemented an order relation will be passed to the template parameter T. 13.44 Implement the Li s t class template by using circular lists. This is done simply by having the next pointer of the last node point to the first node instead of being NULL.
13.45 Use the circularly linked implementation of Problem 13.44 to solve the Josephus Problem.
This problem simulates the elimination of a group of n soldiers standing in a circle, using an increment m, where 1 L m < n. The soldiers are eliminated one at a time by counting up to m. For example, if there are n=8 soldiers and the increment is m=3, the order of elimination is 3, 6, 1,5,2, 8,4,7. That should be the output from the program with input 8 and 3.
Answers to Review Questions
13.1 Afunction template is a template that is used to generate functions. A templatefunction is a function that is produced by a template. For example, swap (T& , T& ) in Example 13.1 is a function template, but thecall swap(m, n ) generates the actual template function that is invoked by the call. 13.2 A class template is a template that is used to generate classes. A template class is a class that is produced by a template. For example, Stack in Example 13.3 is a class template, but the type Stackhnb used in the declarations is an actual template class.
CHAP. 131
TEMPLATES
ITERATORS
13.3 Vectors have the advantage of direct access (also called random access ) to their components by means
of the subscript operator. So if the elements are kept in order, we can locate them very quickly using the Binary Search Algorithm. Lists have the advantage of being dynamic, so that they never use more space than is currently needed, and they aren t restricted to a predetermined size (except for the size of the computer s memory). So vectors have a time advantage and lists have a space advantage.
13.4 Both iterators and array index act as locators into a data structure. The following code shows that they
work the same way: // an array of 100 floats float a[lOO]; int i = 0; // an index for the array = 3.14159; dil for (i = 0; i c 100; i++) tout CC a[i]; Listcfloab list; // a list Df floats // an iterator for the list ListItercfloab it (list); it = 3.14159; for (it.reset(); !it; it++) tout CC it(>;
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