ssrs qr code There are two things wrong. The variable n the <iostream.h> headerfile. = 3 in Software

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There are two things wrong. The variable n the <iostream.h> headerfile. = 3
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is not declared, and cou
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is being used without including
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1.10 a. 37/ (5*2) evaluatesto 37/10 b. 37/5/2 e v a l u a t e s t o (37/5)
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/2 = 7/2 = 3
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c. This is not valid because there is no operator between 3 7 a n d ( 5 / 2 ) . T h e intended operation was 3 7 * ( 5 / 2 ) , which evaluates to 3 7 / 2 = 18 d. 37%(5%2) e. 37%5%2 evaluatesto 37%1 = 0 2%2 = 0
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evaluatesto (37%5)%2 =
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$ 37 - 5 - 2 evaluatesto (37 - 5) - 2 = 32 - 2 = 30 g. This is not valid because there is no operator between ( 3 7 - 5 > a n d 2. T h e intended operation was ( 3 7 - 5 ) * 2, which evaluates to 3 2 * 2 = 6 4
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1.11 a. m - 8 - n evaluates to ( 2 4 -8)-7=16-7=9 b. m = n = 3 evaluates to 3 c. m%n evaluates to 2 4 %7 = 3 d. m%n++ evaluates to 24% (7++) = 24%7 = 3 e. m%++n evaluates to 24% (++7) = 24%8 = 0 f. ++m - n-evaluatesto (++24) - (7--) = 25 - 7 = 8
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g. m += n -= 2 evaluatesto += (7 -= 2) = 24 += 5 = 29 1.12 a. r2 d2 is a valid identifier b. H20 is a valid identifier C. d. secondCousinOnceRemoved 2ndBir thday isavalididentifier
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is not a valid identifier because its first character is a digit isavalididentifier
e. the-United-States-of-America J is -TIME - a valid identifier
g. - 12 3 4 5 is a valid identifier h. x ( 3 ) is not a valid identifier because it contains the characters ( and ) i. cos t-in-$ is not a valid identifier because it contains the character $
2
Conditional Statements and Integer Types
The programs in 1 all have sequential execution: each statement in the program executes once, in the order that they are listed. Conditional statements allow for more flexible programs where the execution of some statements depends upon conditions that change while the program is running. This chapter describes the if statement, the if . . . else statement, and the switch statement also shows how to include simple input into your programs.
2.1 INPUT
In C++, input is analogous to output. But instead of data flowing out to the output stream tout, we have data flowing in from the input stream tin (pronounced see-in ). The name stands for console input.
EXAMPLE 2.1 Integer Input
Here is a simple program that reads integer input:
main0
int age; tout << "How old are you: "; tin >> age; tout << "In 10 years, you will be ' << age + 10 << ".\n"; > How old are you: 19 'Jri 3.0 yct%u23, you wiU be 29. _
The type shown in boldface in the shaded sample run is the input that is typed by the user.
The symbol >> is the extraction operator, also called the input operator. It is usually used with the tin input stream, which is usually the user s keyboard. Thus, when the statement
tin >> age;
executes, the system pauses, waiting for input. As soon as an integer is input, it is assigned to age and the program continues. Notice that the preprocessor directive:
#include <iostream.h>
is missing from Example 2.1. It & required in any program that uses either tin or tout. But since nearly every program in this book does use either tin or tout, we will assume that you know to include this line at the beginning of your source code file. Omitting it from these
CONDITIONAL STATEMENTS AND INTEGER TYPES
[CHAP. 2
examples simply saves some print space. We will also omit the return statement at the end of the main ( > function in all future examples. The input object tin is analogous to the output object tout. Each is a C++ stream object that acts as a conduit through which bytes flow. The bytes flow into the running program through the tin obiect. and thev flow out through the tout object. This can be visualized like this:
{include <iostream.h> nain0 ( int age; tout << "How old are you: "; tin >> age; tout << "In 10 years, you will be
' cc age + 10 -C-C ".\n";
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