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EXAMPLE 2.2 Character Input
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main0 1 char first, last; tout << "Enter your initials:\n"; tout CC "\tFirst name initial: ";
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tin >> f i r s t ;
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tout CC "\tLast name initial: ";
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tin >> l a s t ;
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tout CC "Hello,
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'I CC last << ".!\n";
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CHAP. 21
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CONDITIONAL STATEMENTS AND INTEGER TYPES
This example illustrates a standard way to format input. The first output line alerts the user to what general input is needed. This is followed by a sequence of specific input requests, called user prompts. Each user prompt is indented with the tab character \ t, and by omitting the newline character \ n it leaves the cursor on the same line for the user to enter a response there.
EXAMPLE 2.3 Multiple Input in the Same Stream
More than one variable may be read in the same input statement:
main0 char first, last; tout cc "Enter your first and last initials: "; tin >> first >> last; tout << "Hello, ' CC first << '. 'I CC last << ".!\n";
This shows that the input stream tin reads the items from left to right; i.e., the left-most variable is read first. Since the char type is an integer type, tin will ignore all leading white space (i.e., blanks, tabs, and newlines) when it reads input. So the input in this example could have been entered as
Notice that this prevents the input of blanks as characters using input operator CC. In later chapters, we will see more specialized methods for character input. 2.2 THE if STATEMENT
The if statement allows conditional execution. Its syntax is
if (condition) statement;
where
condi ti on is an integer expression and s ta temen t is any executable statement. The ta temen t will be executed only if the condi ti on has a nonzero value. (Whenever an integer
expression is being evaluated as a condition, a nonzero value is interpreted to mean true and a zero value to mean false. ) Notice the required parentheses around the condi t ion. EXAMPLE
2.4 Testing for Divisibility
main0 -t int n, d; tout cc "Enter two integers: "; tin >> n >> d; if (n%d == 0) tout CC n CC It is divisible by ' CC d CC endl;
Enter twu, integers: 24 6 24 is divisible by-S .
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CONDITIONAL STATEMENTS AND INTEGER TYPES
[CHAP. 2
This program reads two integers and then checks the value of the remainder n % d. In this run, the value of 24 % 6 is 0, which means that 24 is divisible by 6.
The trouble with this last example is that it .doesn t do anything when n is not divisible by d:
Enter two integers: 24 5
To execute an alternative statement when the condition is zero, we need the statement.
i f . . . el se
2 . 3 T H E i f . . . else STATEMENT
T h e i f . . . else statement executes one of two alternative statements, according to the value of the specified condition. It has the syntax
if (condition) statementl; else statement2;
where condi t ion is an integer expression, and s tat ement 1 and s tat ement 2 are any statements. The statement1 is executedif the condition has anonzero value, and statement2 is
executed if the condition has a zero value.
EXAMPLE 2.5
This is the same program as in Example 2.4, except that an el se clause has been added:
main0 -i int n, d; tout << "Enter two integers: "; tin >> n >> d; if (n%d == 0) tout -cc n << is divisible by ' -CC d -CC endl; e l s e tout c c n c c w i s n o t d i v i s i b l e b y CC d CC e n d l ; Enter twu
integers: 24 5
not divisible by 5
Since 24 % 5 == 4, the condition ( n%d = = 0 ) is false and the e 1 s e clause executes.
A condition like (n%d = = o > is an expression whose value is interpreted as being either false or true. In C++ those two values are integers: 0 means false, and any nonzero integer means true. Because of that correspondence, conditions can be ordinary integer expressions. In particular, the integer expression (n%d > itself can be used as a condition. It is nonzero (i.e., true ) precisely when n is not divisible by d, we should reverse the two print statements in the previous example to make sense:
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