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CHAP. 31
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ITERATION AND FLOATING TYPES
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EXAMPLE 3.23 Generating Pseudo-Random Numbers #include #include #include <iostream.h> <stdlib.h> <time.h>
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main0 1 unsigned seed = time(NULL); tout << "seed = 'I CC seed -X endl; srand(seed); int min, max; tout << "Enter minimum and maximum: 'I; // lowest and highest numbers tin >> min >> max; // number of numbers in range int range = max - min + 1; for (int i = 0; i < 20; i++) { int r = rand()/lOO%range + min; tout c-c r << I II; > tout K-C endl; seed = 808237677 Enter minimum and maximum: 1 3.00 85 57 1 10 5 73 81 43 46 42 17 44 48 3 3 7 4 41 4 30 6 8 seed = 808238101 Enter minimum a& maximum: 22 66 63 29 56 22 53 57 341 56 43 36 6 2 30 $1 57 26.61
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The first run generates 20 integers uniformly distributed between 1 and 100. The second run generates
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20 integers uniformly distributed between 22 and 66. In the for loop, we divide rand ( ) by 100 first to strip way the two right-most digits of the ran-
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dom number. This is to compensate for the problem that this particular random number generator has of ~ producing numbers that alternate odd and even. Then rand ( ) / 10 0 %range produces random numbers in the range 0 to range-l, and rand ( ) / 10 0 %range + min produces random numbers in the range min to max.
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A much better amxoach to generating Dseudo-random numbers is described in Problem 8.20. Review Questions
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What is the minimum number of iterations that
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a. a while loop could make
6. a do.. . whi le loop could make
What is wrong with the following loop:
while (n <= 100) sum += n*n;
ITERATION AND FLOATING TYPES
[CHAP. 3
If s is a compound statement, and el, e2, and e3 are expressions, then what is the difference between the program fragment:
for (el; e2; e3) s;
and the fragment:
el; while (e2) s; e3 ; > 3.4 {
What is wrong with the following program:
main0 1 const double pi; int n; pi = 3.14159265358979; n = 22;
3.5 3. 6 3.7
What is an infinite loop, and how can it be useful How can a loop be structured so that it terminates with a statement in the middle of its block What why should tests for equality with floating-point variables be avoided
Solved Problems
Trace the following code fragment, showing the value of each variable each time it changes:
int x, y, z;
x=y=z=6;
X *=
+= z -= 4;
First, 6 is assigned to z, y, and x. Then z is decremented by 4, obtaining the value 2. Then y is incremented by 2, obtaining the value 8. Then x is multiplied by 8, obtaining the value 48. 3. 9
Assuming that e is an expression and loops into an equivalent while loop:
a. for ( ; e; ) s b. for ( ; ; e) s
is a statement, convert each of the following for
a. while (e> s; b. while (1) { s; e;},
assuming that s contains no continue statement. (See Exercise 3.3.)
CHAP. 31
ITERATION AND FLOATING TYPES
Convert the following for loop into a whi le loop:
for (int i = 1; i C= n; i++) tout CC i*i; int i = 1; while (i C= n) { tout CC i*i; it-+; >
Describe the output from the following program:
main0 for (int i = 0; i c 8; i++) if (i%2 == 0) tout CC i + 1 cc endl; else if (i%3 == 0) tout CC i*i CC endl; else if (i%5 == 0) tout CC 2*i - 1 CC endl; else tout CC i CC endl;
Describe the output from the following program:
main0 for (int i = 0; i c 8; i++) { if (i%2 == 0) tout CC i + 1 CC endl; else if (i%3 == 0) continue; else if (i%5 == 0) break; tout << Tnd of program.\n"; tout cc "'End of program.\n";
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End of program,' EQd:. id! grogs;ram. - . ..'_' ,. ; I,. 5'. '. I E.nd _ sfs .-.. grogrik~ .,. ,., pjj@.& ..af p&Jgj$m, ,, .: .
._ .I . . ., ', ,.
In a 32-bit float type, 23 bits are used to store the mantissa and,8 bits are used to store the exponent.
a. How many significant digits of precision does the 32-bit float type yield I b. What is the range of magnitude for the 32-bit float type
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