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Write a program that reads a sequence of names, one per line, and then sorts and prints them.
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We assume that names have no more than 25 characters and that there will be no more than 25 names. We ll read all the input in at once and store it all in a single buffer. Since each name will be terminated with a NUL character, the buffer needs to be large enough to hold 25*(20 + 1) + 1 characters (25 21-character strings plus one last NUL character). The program is modularized into five function calls. The call input ( bu f f er ) reads everything intothe buffer.Thecall tokenize(name, numNames, buffer) tokenizes the buffer, storing pointers to its names in the name array and returning the number of names in nurnNames. The call print(name, numNames ) prints all the names that are stored in buf f er. The call sort(name, numNames ) does an indirect sort on the names stored in buf f er by rearranging the pointers stored in the name array. #include #include const const const void void void void main0 char* name[maxNumNames]; char buffer[bufferLength+l]; int nurnNames; input(buffer); tokenize(name, num.Names, buffer); print(name, numNames); sort(name, numNames); print(name, num.Names); ciostream.h> cstring.h>
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int nameLength = 20; int maxNumNames = 25; int bufferLength = maxNumNames*(nameLength + 1); input(char* buffer); tokenize(char** name, int& numNames, char* buffer); print(char** name, int numNames); sort(char** name, int nurnNames);
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The entire input is done by the single call cin.getline (bu ffer, buf ferlength, This reads characters until the $ character 1 s read, storing all the characters in buffer.
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// Reads up to 25 strings into buffer: void input(char* buffer) 1 tout << "Enter up to " CC maxNurnNames CC ' names, one per line.' << " Terminate with \I$\'. \nNames are limited to " CC nameLength CC " characters.\n'; cin.getline(buffer, bufferlength, '$I);
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T h e t okeni z e ( ) function uses the s t r t ok ( ) function to scan through the bu f f er, tokenizing each substring that ends with the newline character I\n Iand storing its address in the name array. The for loop continues until p points to the sentinel 1 I. Notice that the function s name $ parameter is declared as a char* * because it is an array of pointers to chars. Also note that the counter n is declared as an in t & (passed by reference) so that its new value is returned to main ( > .
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// Copies address of each string in buffer into name array: void tokenize(char** name, int& n , char* buffer)
char* p = strtok (buffer, "\n" > ; for (n = 0; p &SC *p != $I; n ++I name[n] = p; p = strtok(NULL, "\n"); 1 1
// p points to each token -t
The print ( ) and sort ( ) functions are similar to those seen before, except that both operate here indirectly. Both functions operate on the name array, using to access the names that are stored in bu f f er. Notice that the sort ( ) function changes only the name array; the bu f f er is left unchanged.
// Prints the n names stored in buffer: void print(char** name, int n)
tout cc "The names are:\n";
for (int i = 0; i c n; i++) tout cc '\t' <c i+l cc ". " << name[i] cc endl;
// Sorts the n names stored in buffer: void sort(char** name, int n) char* temp; for (int i = 1; i < n; i++) for (int j = 0; j c n-i; j++) if (strcmp(name[j], name[j+l]) temp = name[j]; name[j] = name[j+l]; name[j+l] = temp; >
// Bubble Sort > 0) {
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On this sample run the user entered 7 names and then the sentinel $ . The names were then printed, sorted, and printed again.
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