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The call strncpy(s1,s2,2) replaces the first 2 characters of s1 with XY, leaving the rest of s1 unchanged. The effect of strncpy(s1,s2,2) can be visualized as shown here. Since s2 has length 3, strncpy(s1,s2,2) copies 2 bytes (excluding the NUL character ), overwriting the first 2 characters of s1. This has no effect upon the length of s1 which is 7.
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If n < strlen(s2), as it is in the above example, X X s2 then strncpy(s1,s2,n) simply copies the first n s2 Y Y Z Z characters of s2 into the beginning of s1. However, if n strlen(s2), then strncpy(s1,s2,n) has the same effect as strcpy(s1,s2): it makes s1 a duplicate of s2 with the same length. The strcat() and strncat() functions work the same as the strcpy() and strncpy() functions except that the characters from the second C-string are copied onto the end of the first C-string. The term cat comes from the word catenate meaning string together. EXAMPLE 8.17 The String Concatenation Function strcat()
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This program traces call strcat(s1,s2) which appends the C-string s2 onto the end of s1: int main() { char s1[] = "ABCDEFG"; char s2[] = "XYZ"; cout << "Before strcat(s1,s2):\n"; cout << "\ts1 = [" << s1 << "], length = " << strlen(s1) << endl; cout << "\ts2 = [" << s2 << "], length = " << strlen(s2) << endl; strcat(s1,s2); cout << "After strcat(s1,s2):\n"; cout << "\ts1 = [" << s1 << "], length = " << strlen(s1) << endl; cout << "\ts2 = [" << s2 << "], length = " << strlen(s2) << endl; } Before strcat(s1,s2): s1 = [ABCDEFG], length = 7 s2 = [XYZ], length = 3 After strcat(s1,s2): s1 = [ABCDEFGXYZ], length = 10 s2 = [XYZ], length = 3 The call strcat(s1,s2) appends XYZ onto the A A s1 s1 end of s1. It can be visualized as shown here. Since B B C C s2 has length 3, strcat(s1,s2) copies 4 bytes D D E E (including the NUL character, shown as ), overwritF F G G ing the NUL characters of s1 and its following 3 X Y bytes. The length of s1 is increased to 10. Z
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If any of the extra bytes following s1 that are needed to copy s2 are in use by any other object, then all of s1 and its appended s2 will be copied to some other free section of memory.
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C-STRINGS
EXAMPLE 8.18 The Second String Concatenation Function strncat()
This program traces calls strncat(s1,s2,n): #include <cstring> #include <iostream> using namespace std; int main() { // test-driver for the strncat() function: char s1[] = "ABCDEFG"; char s2[] = "XYZ"; cout << "Before strncat(s1,s2,2):\n"; cout << "\ts1 = [" << s1 << "], length = " cout << "\ts2 = [" << s2 << "], length = " strncat(s1,s2,2); cout << "After strncat(s1,s2,2):\n"; cout << "\ts1 = [" << s1 << "], length = " cout << "\ts2 = [" << s2 << "], length = " } Before strncat(s1,s2,2): s1 = [ABCDEFG], length = 7 s2 = [XYZ], length = 3 After strncat(s1,s2,2): s1 = [ABCDEFGXY], length = 9 s2 = [XYZ], length = 3 The call strncat(s1,s2,2) appends XY onto the end of s1. The effect can be visualized as shown here. s1 Since s2 has length 3, strncat(s1,s2,2) copies 2 bytes overwriting the NUL character of s1 and the byte that follows it. Then it puts the NUL character in the next byte to complete the C-string s1. This increases its length to 9. (If either of the extra 2 bytes had been in use by some other object, then the entire 10 characters ABCDEFGXY would have been written in s2 some other free part of memory.)
<< strlen(s1) << endl; << strlen(s2) << endl;
<< strlen(s1) << endl; << strlen(s2) << endl;
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