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The test driver repeatedly reads a word, prints it, pluralizes it, and prints it again. The loop terminates when the user enters a single blank for a word: bool pluralize(char*); int main() { char word[80]; for (;;) { cin.getline(word, 80); if (*word == ' ') break; cout << "\tThe singular is [" << word << "].\n"; pluralize(word); cout << "\t The plural is [" << word << "].\n"; } } wish The singular is [wish]. The plural is [wishes]. hookah The singular is [hookah]. The plural is [hookahs]. bus The singular is [bus]. The plural is [buses]. toy The singular is [toy]. The plural is [toys]. navy The singular is [navy]. The plural is [navies]. quiz The singular is [quiz]. The plural is [quizzes]. quartz The singular is [quartz]. The plural is [quartzes]. computer The singular is [computer]. The plural is [computers]. 8.5 We assume that names have no more than 20 characters and that there will be no more than 25 names. We ll read all the input in at once and store it all in a single buffer. Since each name will be terminated with a NUL character, the buffer needs to be large enough to hold 25*(20 + 1) + 1 characters (25 21-character strings plus one last NUL character). The program is modularized into five function calls. The call input(buffer) reads everything into the buffer. The call tokenize(name, numNames, buffer) tokenizes the buffer, storing pointers to its names in the name array and returning the number of names in numNames. The call print(name, numNames) prints all the names that are stored in buffer. The call sort(name, numNames) does an indirect sort on the names stored in buffer by rearranging the pointers stored in the name array. #include <cstring> #include <iostream> using namespace std; const int NAME_LENGTH = 20; const int MAX_NUM_NAMES = 25;
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const int BUFFER_LENGTH = MAX_NUM_NAMES*(NAME_LENGTH + 1); void input(char* buffer); void tokenize(char** name, int& numNames, char* buffer); void print(char** name, int numNames); void sort(char** name, int numNames); int main() { char* name[MAX_NUM_NAMES]; char buffer[BUFFER_LENGTH+1]; int numNames; input(buffer); tokenize(name, numNames, buffer); print(name, numNames); sort(name, numNames); print(name, numNames); } The entire input is done by the single call cin.getline(buffer, BUFFER_LENGTH, '$'). This reads characters until the $ character is read, storing all the characters in buffer. void input(char* buffer) { // reads up to 25 strings into buffer: cout << "Enter up to " << MAX_NUM_NAMES << " names, one per" << " line. Terminate with \'$\'.\nNames are limited to " << NAME_LENGTH << " characters.\n"; cin.getline(buffer, BUFFER_LENGTH, '$'); } The tokenize() function uses the strtok() function to scan through the buffer, tokenizing each substring that ends with the newline character '\n' and storing its address in the name array. The for loop continues until p points to the sentinel '$'. Notice that the function s name parameter is declared as a char** because it is an array of pointers to chars. Also note that the counter n is declared as an int& (passed by reference) so that its new value is returned to main(). void tokenize(char** name, int& n, char* buffer) { // copies address of each string in buffer into name array: char* p = strtok(buffer, "\n"); // p points to each token for (n = 0; p && *p != '$'; n++) { name[n] = p; p = strtok(NULL, "\n"); } } The print() and sort() functions are similar to those seen before, except that both operate here indirectly. Both functions operate on the name array. void print(char** name, int n) { // prints the n names stored in buffer: cout << "The names are:\n"; for (int i = 0; i < n; i++) cout << "\t" << i+1 << ". " << name[i] << endl; } void sort(char** name, int n) { // sorts the n names stored in buffer: char* temp; for (int i = 1; i < n; i++) // Bubble Sort for (int j = 0; j < n-i; j++) if (strcmp(name[j], name[j+1]) > 0) { temp = name[j];
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