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name[j] = name[j+1]; name[j+1] = temp; } } Enter up to 25 names, one per line. Names are limited to 20 characters. Washington, George Adams, John Jefferson, Thomas Madison, James Monroe, James Adams, John Quincy Jackson, Andrew $The names are: 1. Washington, George 2. Adams, John 3. Jefferson, Thomas 4. Madison, James 5. Monroe, James 6. Adams, John Quincy 7. Jackson, Andrew The names are: 1. Adams, John 2. Adams, John Quincy 3. Jackson, Andrew 4. Jefferson, Thomas 5. Madison, James 6. Monroe, James 7. Washington, George
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On this sample run the user entered 7 names and then the sentinel $ . The names were then printed, sorted, and printed again. The function first locates the end of the C-string. Then it swaps the first character with the last character, the second character with the second from last character, etc.: void reverse(char* s) { char* end, temp; for (end = s; *end; end++) ; // find end of s while (s < end - 1) { temp = *--end; *end = *s; *s++ = temp; } } The test driver uses the getline() function to read the C-string. Then it prints it, reverses it, and prints it again: void reverse(char*); int main() { char string[80]; cin.getline(string, 80); cout << "The string is [" << string << "].\n"; reverse(string); cout << "The string is [" << string << "].\n"; }
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Today is Wednesday. The string is [Today is Wednesday.]. The string is [.yadsendeW si yadoT]. 8.7 int main() { char word[80]; while (cin >> word) if (*word) cout << "\t\"" << word << "\"\n"; } Today is Wednesday. "Today" "is" "Wednesday." ^Z char* Strchr(const char* s, int c) { for (const char* p=s; p && *p; p++) if (*p==c) return (char*)p; return 0; } int numchr(const char* s, int c) { int n=0; for (const char* p=s; p && *p; p++) if (*p==c) ++n; return n; } char* Strrchr(const char* s, int c) { const char* pp=0; for (const char* p=s; p && *p; p++) if (*p==c) pp = p; return (char*)pp; } char* Strstr(const char* s1, const char* s2) { if (*s2==0) return (char*)s1; // s2 is the empty string for ( ; *s1; s1++) if (*s1==*s2) for (const char* p1=s1, * p2=s2; *p1==*p2; p1++, p2++) if (*(p2+1)==0) return (char*)s1; return 0; } char* Strncpy(char* s1, const char* s2, size_t n) { char* p=s1; for ( ; n>0 && *s2; n--) *p++ = *s2++; for ( ; n>0; n--) *p++ = 0; return s1; }
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char* Strcat(char* s1, const char* s2) { char* p=s1; for ( ; *p; p++) ; for ( ; *s2; p++, s2++) *p = *s2; *p = 0; return s1; } int Strcmp(char* s1, const char* s2) { for ( ; *s1==*s2; s1++, s2++) if (*s1==0) return 0; return (int)(*s1-*s2); } int Strncmp(char* s1, const char* s2, size_t n) { for ( ; n>0; s1++, s2++, n--) if (*s1!=*s2) return (int)(*s1-*s2); else if (*s1==0) return 0; return 0; } size_t Strspn(const char* s1, const char* s2) { const char *p1, *p2; for ( p1 = s1 ; *p1; p1++) for ( p2 = s2 ; ; p2++ ) if ( *p2 == '\0' ) // end of s2 reached; no match found return ( p1 - s1 ) ; // so *p1 is not in s2[] else if ( *p1 == *p2 ) // *p1 is not the one break ; // aborts inner for loop return ( p1 - s1 ) ; // returning length of s1 } size_t Strcspn(const char* s1, const char* s2) { const char *p1, *p2; for ( p1 = s1 ; *p1; p1++) for ( p2 = s2 ; *p2 ; p2++ ) if ( *p1 == *p2 ) // *p1 found in s2[] return ( p1 - s1 ) ; // and p1-s1 is its index return ( p1 - s1 ) ; // returning length of s1 } char* Strpbrk(const char* s1, const char* s2) { const char *p1, *p2; for ( p1 = s1 ; *p1; p1++) for ( p2 = s2 ; *p2 ; p2++ ) if ( *p1 == *p2 ) // *p1 found in s2[] return (char*) p1 ; // so returns its address return NULL ; // no character of s1 is in s2[] } int freqInWords(const char* sentence, char ch) { int count = 0 ; char* copy = new char[ strlen(sentence) ] ; copy = strcpy( copy, sentence ) ; if ( copy == NULL ) return 0 ; char *p = strtok(copy, "\t\n \v\f\r" ) ;
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