ssrs 2016 qr code Copyright 2000 The McGraw-Hill Companies, Inc. Click Here for Terms of Use. in Software

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Copyright 2000 The McGraw-Hill Companies, Inc. Click Here for Terms of Use.
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STANDARD C++ STRINGS
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After that extraction has finished, the cin n 46 newline character is \n int istream still in the input stream. If the next input statement is another formatted input, then like all whitespace characters that newline character will be ignored.
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The extraction operator >> formats the data that it receives through its input stream. This means that it extracts characters from the stream and uses them to form a value of the same type as its second operand. In the process it ignores all whitespace characters that precede the characters it uses. A direct consequence of this rule is that it is impossible to use the extraction operator to read whitespace characters. For that you must use an unformatted input function. The operator expression
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cin >> x
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has a value that can be interpreted in a condition as boolean; i.e., either true or false depending upon whether the input is successful. That allows such an expression to be used to control a loop. EXAMPLE 9.2 Using the Extraction Operation to Control a Loop
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int main() { int n; while (cin >> n) cout << "n = " << n << endl; } 46 n = 46 22 44 66 88 n = 22 n = 44 n = 66 n = 88 33, 55, 77, 99 n = 33 The loop continues iterating as long as the integer data is separated by only whitespace. The first non-whitespace character, the comma ',' causes the input to fail, thereby stopping the loop.
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9.3 UNFORMATTED INPUT The <iostream> files define several functions inputting characters and C-strings that do not skip over whitespace. The most common are the cin.get() function for reading individual characters and the cin.getline() function for reading C-strings. EXAMPLE 9.3 Inputting Characters with the cin.get() Function
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while (cin.get(c)) { if (c >= 'a' && c <= 'z') c += 'A' - 'a'; cout.put(c);
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// capitalize c
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if (c == '\n') break; } This loop is controlled by the input expression (cin.get(c)). When the input stream object cin detects the end-of-file (signaled interactively by Ctrl+Z or Ctrl+D), the expression evaluates to false and stops the loop. This loop also terminates with a break statement after reading and processing the newline character '\n'. The if statement simply capitalizes all lowercase letters, and the cout.put(c) statement prints the character. Here is a sample run: Cogito, ergo sum! COGITO, ERGO SUM!
EXAMPLE 9.4 Inputting C-Strings with the cin.getline() Function
This program shows how to read text data line-by-line into an array of C-strings: const int LEN=32; // maximum word length const int SIZE=10; // array size typedef char Name[LEN]; // defines Name to be a C-string type int main() { Name king[SIZE]; // defines king to be an array of 10 names int n=0; while(cin.getline(king[n++], LEN) && n<SIZE) ; --n; // now n == the number of names read for (int i=0; i<n; i++) cout << '\t' << i+1 << ". " << king[i] << endl; } The object king is an array of 10 objects of type Name. The typedef defines Name as a synonym for C-strings of 32 chars (31 non-null). The function call cin.getline(king[n++], LEN) reads characters from cin until either it has extracted LEN-1 characters or it encounters the newline character, whichever comes first. It copies these characters into the C-string king[n]. If it encounters the newline character, it extracts it and ignores it (i.e., it does not copy it into the C-string). Then it increments n. Note that the body of the while loop is empty. The loop stops when either cin detects the end-of-file or when n == SIZE. Since n Kings.dat starts at 0 and is incremented after the last name Kenneth II (971-995) is read, its value is always 1 greater than the Constantine III (995-997) number of names read. So it gets decremented Kenneth III (997-1005) once at the end so that its value equals the Malcolm II (1005-1034) number of names read. Then it is easy to print Duncan I (1034-1040) them or process them in other ways using a Macbeth (1040-1057) simple for loop. Lulach (1057-1058) When input is read from this text file, Malcolm III (1058-1093) the output is 1. Kenneth II (971-995) 2. Constantine III (995-997) 3. Kenneth III (997-1005) 4. Malcolm II (1005-1034) 5. Duncan I (1034-1040) 6. Macbeth (1040-1057) 7. Lulach (1057-1058) 8. Malcolm III (1058-1093)
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