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If T is a class (instead of an ordinary type), its constructor will be called by the declaration of data. Note that the class List<T> is declared here to be a friend of the ListNode class. This will allow the member functions of the List class to access the protected members of the Node class. For this statement to compile, some compilers require the following forward reference to precede the ListNode template definition: template<class T> class List; This simply tells the compiler that the identifier List will be defined later as a class template. Here is the List class template interface, which follows the ListNode template definition: template<class T> class List { public: List() : first(0) { } ~List(); void insert(T t); // insert t at front of list int remove(T& t); // remove first item t in list bool isEmpty() { return (first == 0); } void print(); protected: ListNode<T>* first; ListNode<T>* newNode(T& t, ListNode<T>* p) { ListNode<T>* q = new ListNode<T>(t,p); return q; } }; A List object contains only the pointer named first. This points to a ListNode object. The default constructor initializes the pointer to first NULL. After items have been inserted into the list, the first pointer will List<int> point to the first item in the list. The newNode() function invokes the new operator to obtain a new ListNode object by means of the ListNode() constructor. The new node will contain the T value t in its data field and the pointer p in its next field. The function returns a pointer to the new node. It is declared protected because it is a utility function that is used only by the other member functions. The List destructor is responsible for deleting all the items in the list: template<class T> List<T>::~List() { ListNode<T>* temp; for (ListNode<T>* p = first; p; ) // traverses list { temp = p; p = p->next; delete temp; } }
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This has to be done in a loop that traverses the list. Each node is deleted by invoking the delete operator on a pointer to the node. The insert() function creates a new node containing the T value t and then inserts this new node at the beginning of the list: template<class T> void List<T>::insert(T t) { ListNode<T>* p = newNode(t,first); first = p; } Since the new node will be made the first node in the list, its next pointer should point to the node that is currently first in the list. Passing the first pointer to the NewNode constructor does that. Then the first pointer is reset to point to the new node. The remove() function removes the first item from the list, returning its data value by reference in the parameter t. The function s return value is 1 or 0 according to whether the operation succeeded: template<class T> int List<T>::remove(T& t) { if (isEmpty()) return 0; // flag to signal no removal t = first->data; // data value returned by reference ListNode<T>* p = first; first = first->next; // advance first pointer to remove node delete p; return 1; // flag to signal successful removal } The print() function simply traverses the list, printing each node s data value: template<class T> void List<T>::print() { for (ListNode<T>* p=first; p; p=p->next) cout << p->data << " -> "; cout << "*\n"; } Here is a test driver and a sample run: #include <iostream.h> #include "List.h"
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int main() { List<string> friends; friends.insert("Bowen, Van"); friends.insert("Dixon, Tom"); friends.insert("Mason, Joe"); friends.insert("White, Ann"); friends.print(); string name; friends.remove(name); cout << "Removed: " << name << endl; friends.print(); } White, Ann -> Mason, Joe -> Dixon, Tom -> Bowen, Van -> * Removed: White, Ann Mason, Joe -> Dixon, Tom -> Bowen, Van -> * Notice that, since each item is inserted at the beginning of the list, they end up in the opposite order from their insertion.
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