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2.1 2.2 2.3 Write and run a program like the one in Example 2.2 on page 19 that prints the ASCII codes for only the 10 upper case and lower case vowels. Use Appendix A to check your output. Modify the program in Example 2.15 on page 28 so that it uses type double instead of float. Then see how much better it performs on the input that illustrated round-off error. Write and run a program to find which, if any, arithmetic operations can be applied to a variable that will change its value from any of the three numeric constants inf, -inf, and nan to something else. Write a program that converts inches to centimeters. For example, if the user enters 16.9 for a length in inches, the output would be 42.926 cm . (One inch equals 2.54 centimeters.)
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2.1 2.2 if (count > 100) cout << "Too many"; a. Either cout should be used in place of cin, or the extraction operator >> should be used in place of the insertion operator <<. b. Parentheses are required around the condition x < y, and a semicolon is required at the end of the if clause before the else. There is more than one statement between the if clause and the else clause. They need to be made into a compound statement by enclosing them in braces { }. A reserved word is a keyword in a programming language that serves to mark the structure of a statement. For example, the keywords if and else are reserved words. A standard identifier is a keyword that defines a type. Among the 63 keywords in C++, if, else, and while are some of the reserved words, and char, int, and float are some of the standard identifiers. The second enum definition attempts to redefine the constants SPRING, SUMMER, and FALL. Enumerators must be valid identifiers. String literals like "Jerry" and "Henry" are not identifiers.
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2.1 int main() { // prints the ASCII cout << "int('A') = cout << "int('E') = cout << "int('I') = cout << "int('O') = cout << "int('U') = cout << "int('a') = cout << "int('e') = cout << "int('i') = cout << "int('o') = cout << "int('u') = } int('A') = 65 int('E') = 69 int('I') = 73 int('O') = 79 int('U') = 85
codes of the vowels " << int('A') << endl; " << int('E') << endl; " << int('I') << endl; " << int('O') << endl; " << int('U') << endl; " << int('a') << endl; " << int('e') << endl; " << int('i') << endl; " << int('o') << endl; " << int('u') << endl;
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[CHAP. 2
int('a') = 97 int('e') = 101 int('i') = 105 int('o') = 111 int('u') = 117 int main() { // implements the quadratic formula double a, b, c; cout << "Enter the coefficients:" << endl; cout << "\ta: "; cin >> a; cout << "\tb: "; cin >> b; cout << "\tc: "; cin >> c; cout << "The equation is: " << a << "*x*x + " << b << "*x + " << c << " = 0" << endl; double d = b*b - 4*a*c; double sqrtd = sqrt(d); double x1 = (-b + sqrtd)/(2*a); double x2 = (-b - sqrtd)/(2*a); cout << "The solutions are:" << endl; cout << "\tx1 = " << x1 << endl; cout << "\tx2 = " << x2 << endl; cout << "Check:" << endl; cout << "\ta*x1*x1 + b*x1 + c = " << a*x1*x1 + b*x1 + c << endl; cout << "\ta*x2*x2 + b*x2 + c = " << a*x2*x2 + b*x2 + c << endl; } Enter the coefficients of a quadratic equation: a: 2 b: 8.001 c: 8.002 The equation is: 2*x*x + 8.001*x + 8.002 = 0 The solutions are: x1 = -2 x2 = -2.0005 Check: a*x1*x1 + b*x1 + c = 0 a*x2*x2 + b*x2 + c = 0 The following program changes the value of x from inf to -inf and vice versa. But no arithmetic operation will change the value of a variable once it becomes nan. int main() { // changes the value of x after it becomes inf: float x=1e30; cout << "x= " << x << endl; x *= x; cout << "x= " << x << endl; x *= -1.0; cout << "x= " << x << endl; x *= -1.0; cout << "x= " << x << endl; }
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