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if (n > 2) { if (n < 6) cout << "OK"; } else cout << "NG"; The braces are needed here to override the else matching rule. This else is intended to match the first if. The second statement should be written if (n > 2) if (n < 6) cout << "OK"; else cout << "NG"; Here the braces are not needed because the else is intended to be matched with the second if. A fall through in a switch statement is a case that does not include a break statement, thereby causing control to continue right on to the next case statement. This expression evaluates to 1 if x < y, it evaluates to 0 if x == y, and it evaluates to 1 if x > y. absx = ( x>0 x : -x ); a. if (count > 100) cout << "too many"; b. cout << (count > 100 "too many" : "" );
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3.1 This version of Example 3.1 on page 36 prints a response only when n is divisible by d: int main() { int n, d; cout << "Enter two positive integers: "; cin >> n >> d; if (n%d == 0) cout << n << " is divisible by " << d << endl; } Enter two positive integers: 56 7 56 is divisible by 7 This version of Example 3.5 on page 39 prints the minimum of four input integers: int main() { int n1, n2, n3, n4; cout << "Enter four integers: "; cin >> n1 >> n2 >> n3 >> n4; int min=n1; // now min <= n1 if (n2 < min) min = n2; // now min <= n1, n2 if (n3 < min) min = n3; // now min <= n1, n2, n3 if (n4 < min) min = n4; // now min <= n1, n2, n3, n4 cout << "Their minimum is " << min << endl; } Enter four integers: 44 88 22 66 Their minimum is 22 This program finds the median of three input integers: int main() { int n1, n2, n3; cout << "Enter three integers: "; cin >> n1 >> n2 >> n3; cout << "Their median is "; if (n1 < n2) if (n2 < n3) cout << n2; // n1 <
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else if (n1 < n3) cout << n3; else cout << n1; else if (n1 < n3) cout << n1; else if (n2 < n3) cout << n2; else cout << n3; } Enter three integers: 44 88 22 Their median is 44 3.4
// // // // //
n1 n3 n2 n2 n3
< <= <= < <=
n3 n1 n1 n3 n2
<= < < <= <=
n2 n2 n3 n1 n1
This program has the same effect as the one in Example 3.6 on page 39: int main() { int x, y; cout << "Enter two integers: "; cin >> x >> y; if (x > y) cout << y << " <= " << x << endl; else cout << x << " <= " << y << endl; } Enter two integers: 66 44 44 <= 6 Modification of the program in Example 3.7 on page 40: int main() { int n=44; cout << "n = " << n << endl; { cout << "Enter an integer: "; cin >> n; cout << "n = " << n << endl; } { cout << "n = " << n << endl; } { int n; cout << "n = " << n << endl; } cout << "n = " << n << endl; } n = 44 Enter an integer: 77 n = 77 n = 77 n = 4251897 n = 77 Here we used the else if construct because the three outcomes depend upon age being in one of three disjoint intervals: int main() { int age; cout << "Enter your age: "; cin >> age; if (age < 18) cout << "You are a child.\n"; else if (age < 65) cout << "You are an adult.\n"; else cout << "you are a senior citizen.\n"; } Enter your age: 44 You are an adult.
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