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while (true) { long f2 = f0 + f1; if (f2 > bound) break; cout << ", " << f2; f0 = f1; f1 = f2; }
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// terminates the loop immediately
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} Enter a positive integer: 1000 Fibonacci numbers < 1000: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987
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This while loop contains a block of five statements. When the condition (f2 > bound) is evaluated to be true, the break statement executes, terminating the loop immediately, without executing the last three statements in that iteration. Note the use of the newline character \n in the string ":\n0, 1". This prints the colon : at the end of the current line, and then prints 0, 1 at the beginning of the next line.
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EXAMPLE 4.6 Using the exit(0) Function
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The exit() function provides another way to terminate a loop. When it executes, it terminates the program itself: int main() { long bound; cout << "Enter a positive integer: "; cin >> bound; cout << "Fibonacci numbers < " << bound << ":\n0, 1"; long f0=0, f1=1; while (true) { long f2 = f0 + f1; if (f2 > bound) exit(0); // terminates the program immediately cout << ", " << f2; f0 = f1; f1 = f2; } } Enter a positive integer: 1000 Fibonacci numbers < 1000: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987 Since this program has no statements following its loop, terminating the loop is the same as terminating the program. So this program runs the same as the one in Example 4.5.
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The program in Example 4.6 illustrates one way to break out of an infinite loop. The next example shows how to abort an infinite loop. But the preferred method is to use a break statement, as illustrated in Example 4.20 on page 71. EXAMPLE 4.7 Aborting Infinite Loop
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Without some termination mechanism, the loop will run forever. To abort its execution after it starts, press <Ctrl>+C (i.e., hold the Ctrl key down and press the C key on your keyboard):
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int main() { long bound; cout << "Enter a positive integer: "; cin >> bound; cout << "Fibonacci numbers < " << bound << ":\n0, 1"; long f0=0, f1=1; while (true) // ERROR: INFINITE LOOP! (Press <Ctrl>+C.) { long f2 = f0 + f1; cout << ", " << f2; f0 = f1; f1 = f2; } } Enter a positive integer: 1000 Fibonacci numbers < 1000: 0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597 81, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 5 040, 1346269, 2178309, 3524578, 5702887, 9227465, 14930352, 24157817, 63245986, 102334155, 165580141, 267914296, 433494437, 701408733, 11349
Since this program has no statements following its loop, terminating the loop is the same as terminating the program. So this program runs the same as the one in Example 4.5.
4.3 THE do..while STATEMENT The syntax for the do..while statement is
do statement while (condition); where condition is an integral expression and statement is any executable statement. It repeatedly executes the statement and then evaluates the condition until that condition evaluates to false. The do..while statement works the same as the while statement except that its condition is
evaluated at the end of the loop instead of at the beginning. This means that any control variables can be defined within the loop instead of before it. It also means that a do...while loop will always iterate at least once, regardless of the value of its control condition. EXAMPLE 4.8 Using a do..while Loop to Compute a Sum of Consecutive Integers
This program has the same effect as the one in Example 4.1 on page 60: int main() { int n, i=0; cout << "Enter a positive integer: "; cin >> n; long sum=0; do sum += i++; while (i <= n); cout << "The sum of the first " << n << " integers is " << sum; }
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