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4.7 THE goto STATEMENT The break statement, the continue statement, and the switch statement each cause the program control to branch to a location other than where it normally would go. The destination of the branch is determined by the context: break goes to the next statement outside the loop, continue goes to the loop s continue condition, and switch goes to the correct case constant. All three of these statements are called jump statements because they cause the control of the program to jump over other statements. The goto statement is another kind of jump statement. Its destination is specified by a label within the statement. A label is simply an identifier followed by a colon placed in front of a statement. Labels work like the case statements inside a switch statement: they specify the destination of the jump. Example 4.22 illustrated how a break normally behaves within nested loops: execution breaks out of only the innermost loop that contains the break statement. Breaking out of several or all of the loops in a nest requires a goto statement, as the next example illustrates. EXAMPLE 4.24 Using a goto Statement to Break Out of a Nest of Loops
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int main() { const int N=5; for (int i=0; i<N; i++) { for (int j=0; j<N; j++) { for (int k=0; k<N; k++) if (i+j+k>N) goto esc; else cout << i+j+k << " "; cout << "* "; } esc: cout << "." << endl; // inside the i loop, outside the j loop } } 0 1 2 3 4 * 1 2 3 4 5 * 2 3 4 5 . 1 2 3 4 5 * 2 3 4 5 . 2 3 4 5 . 3 4 5 . 4 5 . When the goto is reached inside the innermost k loop, program execution jumps out to the labeled output statement at the bottom of the outermost i loop. Since that is the last statement in the i loop, the i loop will go on to its next iteration after executing that statement. When i and j are 0, the k loop iterates 5 times, printing 0 1 2 3 4 followed by a star *. Then j increments to 1 and the k loop iterates 5 times again, printing 1 2 3 4 5 followed by a star *. Then j increments to 2 and the k loop iterates 4 times, printing 2 3 4 5. But then on the next iteration of the k loop, i = 0, j = 2, and k = 4, so i+j+k = 6, causing the goto statement to execute for the first time. So execute jumps immediately to the labeled output statement, printing a dot and advancing to the next line. Note that both the k loop and the j loop are aborted before finishing all their iterations. Now i = 1 and the middle j loop begins iterating again with j = 0. The k loop iterates 5 times, printing 1 2 3 4 5 followed by a star *. Then j increments to 1 and the k loop iterates 4 times, printing 2 3 4 5. But then on the next iteration of the k loop, i = 1, j = 2, and k = 3, so i+j+k = 6, causing the goto statement to execute for the second time. Again execution jumps immediately to the labeled output statement, printing a dot and advancing to the next line.
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On the subsequent three iterations of the outer i loop, the inner k loop never completes its iterations because i+j+4 is always greater than 5 (because i is greater than 2). So no more stars are printed. Note that the labeled output statement could be placed inside any of the loops or even outside of all of them. In the latter case, the goto statement would terminate all three of the loops in the nest. Also note how the labeled statement is indented. The convention is to shift it to the left one indentation level to make it more visible. If it were not a labeled statement, it would be indented as } cout << "." << endl; } instead of } esc: cout << "." << endl; }
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Example 4.24 illustrates one way to break out of a nest of loops. Another method is to use a flag. A flag is a boolean variable that is initialized to false and then later set to true to signal an exceptional event; normal program execution is interrupted when the flag becomes true. This is illustrated by the following example. EXAMPLE 4.25 Using a Flag to Break Out of a Nest of Loops
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This program has the same output as that in Example 4.24: int main() { const int N=5; bool done=false; for (int i=0; i<N; i++) { for (int j=0; j<N && !done; j++) { for (int k=0; k<N && !done; k++) if (i+j+k>N) done = true; else cout << i+j+k << " "; cout << "* "; } cout << "." << endl; // inside the i loop, outside the j loop done = false; } } When the done flag becomes true, both the innermost k loop and the middle j loop will terminate, and the outer i loop will finish its current iteration by printing the dot, advancing to the beginning of the next line, and resetting the done flag to false. Then it starts its next iteration, the same as in Example 4.24.
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4.8 GENERATING PSEUDO-RANDOM NUMBERS One of the most important applications of computers is the simulation of real-world systems. Most high-tech research and development is heavily dependent upon this technique for studying how systems work without actually having to interact with them directly. Simulation requires the computer generation of random numbers to model the uncertainty of the real world. Of course, computers cannot actually generate truly random numbers because computers are deterministic: given the same input, the same computer will always produce the
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