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void read(Score score) { for (int s=0; s<NUM_STUDENTS; s++) { cout << "Student " << s << ": "; for (int q=0; q<NUM_QUIZZES; q++) cin >> score[s][q]; } } void printQuizAverages(Score score) { for (int s=0; s<NUM_STUDENTS; s++) { float sum = 0.0; for (int q=0; q<NUM_QUIZZES; q++) sum += score[s][q]; cout << "\tStudent " << s << ": " << sum/NUM_QUIZZES << endl; } } void printClassAverages(Score score) { for (int q=0; q<NUM_QUIZZES; q++) { float sum = 0.0; for (int s=0; s<NUM_STUDENTS; s++) sum += score[s][q]; cout << "\tQuiz " << q << ": " << sum/NUM_STUDENTS << endl; } } Enter 5 quiz scores for each student: Student 0: 8 7 9 8 9 Student 1: 9 9 9 9 8 Student 2: 5 6 7 8 9 The quiz averages are: Student 0: 8.2 Student 1: 8.8 Student 2: 7 The class averages are: Quiz 0: 7.33333 Quiz 1: 7.33333 Quiz 2: 8.33333 Quiz 3: 8.33333 Quiz 4: 8.66667 This uses a typedef to define the alias Score for the two-dimensional array type. This makes the function headers more readable. The printQuizAverages() function prints the average of each of the 3 rows of scores, while the printClassAverages() function prints the average of each of the 5 columns of scores.
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EXAMPLE 6.21 Processing a Three-Dimensional Array
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This program simply counts the number of zeros in a three-dimensional array: int numZeros(int a[][4][3], int n1, int n2, int n3); int main() { int a[2][4][3] = { { {5,0,2}, {0,0,9}, {4,1,0}, {7,7,7} }, { {3,0,0}, {8,5,0}, {0,0,0}, {2,0,9} } }; cout << "This array has " << numZeros(a,2,4,3) << " zeros:\n"; }
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int numZeros(int a[][4][3], int n1, int n2, int n3) { int count = 0; for (int i = 0; i < n1; i++) for (int j = 0; j < n2; j++) for (int k = 0; k < n3; k++) if (a[i][j][k] == 0) ++count; return count; } This array has 11 zeros: Notice how the array is initialized: it is a 2-element array of 4-element arrays of 3 elements each. That makes a total of 24 elements. It could have been initialized like this: int a[2][4][3]={5,0,2,0,0,9,4,1,0,7,7,7,3,0,0,8,5,0,0,0,0,2,0,9}; or like this: int a[2][4][3]={{5,0,2,0,0,9,4,1,0,7,7,7},{3,0,0,8,5,0,0,0,0,2,0,9}}; But these are more difficult to read and understand than the three-dimensional initializer list. Also notice the three nested for loops. In general, processing a d-dimensional array is done with d for loops, one for each dimension.
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6.1 6.2 6.3 6.4 6.5 6.6 6.7 How many different types can the elements of an array have What type and range must an array s subscript have What values will the elements of an array have when it is declared if it does not include an initializer What values will the elements of an array have when it is declared if it has an initializer with fewer values than the number of elements in the array What happens if an array s initializer has more values than the size of the array How does an enum statement differ from a typedef statement When a multi-dimensional array is passed to a function, why does C++ require all but the first dimension to be specified in the parameter list
Solved Programming Problems
6.1 Modify the program in Example 6.1 on page 126 so that each input is prompted and each output is labeled, like this:
Enter 5 numbers a[0]: 11.11 a[1]: 33.33 a[2]: 55.55 a[3]: 77.77 a[4]: 99.99 In reverse order, they are: a[4] = 99.99 a[3] = 77.77 a[2] = 55.55 a[1] = 33.33 a[0] = 11.11
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Modify the program in Example 6.1 on page 126 so that it fills the array in reverse and then prints them in the order that they are stored, like this:
Enter 5 numbers: a[4]: 55.55 a[3]: 66.66 a[2]: 77.77 a[1]: 88.88 a[0]: 99.99 In reverse order, they are: a[0] = 99.99 a[1] = 88.88 a[2] = 77.77 a[3] = 66.66 a[4] = 55.55
Modify the program in Example 6.9 on page 131 so that it tests the following function:
float ave(int[] a, int n); // returns the average of the first n elements of a[]
6.4 6.5
Modify the program in Example 6.10 on page 132 so that it prints the array, its sum, and its average. (See Example 6.9 on page 131 and Problem 6.3.) Modify the program in Example 6.11 on page 133 so that it prints the memory address and its contents for each element of an array. For an array named a, use the expressions a, a+1, a+2, etc. to obtain the addresses of a[0], a[1], a[2], etc., and use the expressions *a, *(a+1), *(a+2), etc. to obtain the contents of those locations. Declare the array as
unsigned int a[];
6.6 6.7 6.8
so that the array element values will be printed as integers when inserted into the cout stream. Modify the program in Example 6.12 on page 133 so that it returns the last location of the target instead of the first. Modify the program in Example 6.15 on page 136 so that it returns true if and only if the array is nonincreasing. Write and test the following function that returns the minimum value among the first n elements of the given array:
float min(float a[], int n);
Write and test the following function that returns the index of the first minimum value among the first n elements of the given array:
int minIndex(float a[], int n);
6.10 Write and test the following function that returns through its reference parameters both the maximum and the minimum values stored in an array:
void getExtremes(float& min, float& max, float a[], int n);
Write and test the following function that returns through its reference parameters both the largest and the second largest values (possibly equal) stored in an array:
void largest(float& max1, float& max2, float a[], int n);
6.12 Write and test the following function that removes an item from an array:
void remove(float a[], int& n, int i); The function removes a[i] by shifting all the elements above that position are down and decrementing n.
6.13 Write and test the following function that attempts to remove an item from an array:
bool removeFirst(float a[], int& n, float x);
The function searches the first n elements of the array a for the item x. If x is found, its first occurrence is removed, all the elements above that position are shifted down, n is decre-
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