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EXAMPLE 7.4 Using Pointer Variables
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This program defines the int variable n and the int* variable pn: int main() { int n=44; cout << "n = " << n << ", &n = " << &n << endl; int* pn=&n; // pn holds the address of n cout << " pn = " << pn << endl; cout << "&pn = " << &pn << endl; } n = 44, &n = 0x0064fddc pn = 0x0064fddc &pn = 0x0064fde0 The variable n is initialized to 44. Its address is 0x0064fddc. The variable pn is initialized to &n which is the address of n, so the value of pn is 0x0064fddc, as the second line of output shows. But pn is a separate object, as the third line of output shows: it has the distinct address 0x0064fde0.
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0x0064fdda 0x0064fddb 0x0064fddc 0x0064fddd 0x0064fdde 0x0064fddf 0x0064fde0 0x0064fde1 0x0064fde2 0x0064fde3 0x0064fde4 0x0064fde5
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The variable pn is called a pointer because its value points to the location of another value. The value of a pointer is an address. That address depends upon the state of the individual computer on which the program is running. In most cases, the actual value of that address (here, 0x0064fddc) is not relevant to the issues that concern the programmer. So diagrams like the one pn above are usually drawn more simply like this. This captures the int* essential features of n and pn: pn is a pointer to n, and n has the value 44. A pointer can be thought of as a locator : it locates another object. 7.4 THE DEREFERENCE OPERATOR
If pn points to n, we can obtain the value of n directly from p; the expression *pn evaluates to the value of n. This evaluation is called dereferencing the pointer pn, and the symbol * is called the dereference operator. EXAMPLE 7.5 Dereferencing a Pointer
This is the same program as in Example 7.4 with one more line of code: int main() { int n=44; cout << "n = " << n << ", &n = " << &n << endl; int* pn=&n; // pn holds the address of n cout << " pn = " << pn << endl; cout << "&pn = " << &pn << endl; cout << "*pn = " << *pn << endl; }
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[CHAP. 7
n = 44, &n = 0x0064fdcc pn = 0x0064fdcc &pn = 0x0064fdd0 *pn = 44 This shows that *pn is an alias for n: they both have the value 44.
EXAMPLE 7.6 Pointers to Pointers
This continues to build upon the program from Example 7.4: int main() { int n=44; cout << " n = " << n << endl; cout << " &n = " << &n << endl; int* pn=&n; // pn holds the address of n cout << " pn = " << pn << endl; cout << " &pn = " << &pn << endl; cout << " *pn = " << *pn << endl; int** ppn=&pn; // ppn holds the address of pn cout << " ppn = " << ppn << endl; cout << " &ppn = " << &ppn << endl; cout << " *ppn = " << *ppn << endl; cout << "**ppn = " << **ppn << endl; } n = 44 &n = 0x0064fd78 pn = 0x0064fd78 &pn = 0x0064fd7c pn *pn = 44 int* ppn = 0x0064fd7c &ppn = 0x0064fd80 *ppn = 0x0064fd78 ppn **ppn = 44
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The variable ppn points to pn which points to n. So *ppn is an alias for pn, just as *pn is an alias for n. Therefore **ppn is also an alias for n.
Note in Example 7.6 that each of the three variables n, pn, and ppn, has a different type: int, int*, and int**. In general, if T1 and T2 are different types, then any of their derived types will also be different. So although pn and ppn are both pointers, they are not the same type: pn has type pointer to int, while ppn has type pointer to int*. The reference operator & and the dereference operator * are inverses: n == *p whenever p == &n. This can also be expressed as *&n == n and &*p == p. EXAMPLE 7.7 Referencing Is the Opposite of Dereferencing
This also builds upon the program from Example 7.4: int main() { int n=44; cout << " n = " << n << endl; cout << " &n = " << &n << endl; int* pn=&n; // pn holds the address of n
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