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CHAP. 7]
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EXAMPLE 7.11 Examining the Addresses of Array Elements
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int main() { short a[] = {22, 33, 44, 55, 66}; cout << "a = " << a << ", *a = " << *a << endl; for (short* p = a; p < a + 5; p++) cout << "p = " << p << ", *p = " << *p << endl; } a = 0x3fffd08, *a = 22 p = 0x3fffd08, *p = 22 p = 0x3fffd0a, *p = 33 p = 0x3fffd0c, *p = 44 p = 0x3fffd0e, *p = 55 p = 0x3fffd10, *p = 66 Initially, a and p are the same: they are both pointers to short and they have the same value (0x3fffd08). Since a is a constant pointer, it cannot be incremented to traverse the array. Instead, we increment p and use the exit condition p < a + 5 to terminate the loop. This computes a + 5 to be the hexadecimal address 0x3fffd08 + 5*sizeof(short) = 0x3fffd08 + 5*2 = 0x3fffd08 + 0xa = 0x3fffd1 2, so the loop continues as long as p < 0x3fffd12.
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The array subscript operator [] is equivalent to the dereference operator *. They provide direct access into the array the same way:
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a[0] == *a a[1] == *(a + 1) a[2] == *(a + 2), etc.
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So the array a could be traversed like this:
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for (int i = 0; i < 8; i++) cout << *(a + i) << endl;
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The next example illustrates how pointers can be combined with integers to move both forward and backward in memory. EXAMPLE 7.12 Pattern Matching
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In this example, the loc function searches through the first n1 elements of array a1 looking for the string of integers stored in the first n2 elements of array a2 inside it. If found, it returns a pointer to the location within a1 where a2 begins; otherwise it returns the NULL pointer. short* loc(short* a1, short* a2, int n1, int n2) { short* end1 = a1 + n1; for (short* p1 = a1; p1 < end1; p1++) if (*p1 == *a2) { int j; for (j = 0; j < n2; j++) if (p1[j] != a2[j]) break; if (j == n2) return p1; } return 0; }
int main() { short a1[9] = {11, 11, 11, 11, 11, 22, 33, 44, 55};
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[CHAP. 7
short a2[5] = {11, 11, 11, 22, 33}; cout << "Array a1 begins at location\t" << a1 << endl; cout << "Array a2 begins at location\t" << a2 << endl; short* p = loc(a1, a2, 9, 5); if (p) { cout << "Array a2 found at location\t" << p << endl; for (int i = 0; i < 5; i++) cout << "\t" << &p[i] << ": " << p[i] << "\t" << &a2[i] << ": " << a2[i] << endl; } else cout << "Not found.\n"; } Array a1 begins at location 0x3fffd12 Array a2 begins at location 0x3fffd08 Array a2 found at location 0x3fffd16 0x3fffd16: 11 0x3fffd08: 11 0x3fffd18: 11 0x3fffd0a: 11 0x3fffd1a: 11 0x3fffd0c: 11 0x3fffd1c: 22 0x3fffd0e: 22 0x3fffd1e: 33 0x3fffd10: 33
The pattern matching algorithm uses two loops. The outer loop is controlled by the pointer p1 which points to elements in array a1 where the inner loop will begin checking for a match with array a2. The inner loop is controlled by the integer j which is used to compare corresponding elements of the two arrays. If a mismatch is found, the inner loop aborts and the outer loop continues by incrementing p1 to look for a match starting with the next element of a1. If the inner loop is allowed to finish, then the condition (j == n2) will be true and the current location pointed to by p1 is returned.
The test driver verifies that the match has indeed been found by checking the actual addresses. EXAMPLE 7.13 THE new OPERATOR When a pointer is declared like this:
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