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EXAMPLE 7.15 Using Dynamic Arrays
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The get() function here creates a dynamic array: void get(double*& a, int& n) { cout << "Enter number of items: "; cin >> n; a = new double[n]; cout << "Enter " << n << " items, one per line:\n"; for (int i = 0; i < n; i++) { cout << "\t" << i+1 << ": "; cin >> a[i]; } } void print(double* a, int n) { for (int i = 0; i < n; i++) cout << a[i] << " "; cout << endl; } int main() { double* a; // a is simply an unallocated pointer int n; get(a,n); // now a is an array of n doubles print(a,n); delete [] a; // now a is simply an unallocated pointer again get(a,n); // now a is an array of n doubles print(a,n); }
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CHAP. 7]
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Enter number of items: 4 Enter 4 items, one per line: 1: 44.4 2: 77.7 3: 22.2 4: 88.8 44.4 77.7 22.2 88.8 Enter number of items: 2 Enter 2 items, one per line: 1: 3.33 2: 9.99 3.33 9.99 Inside the get() function, the new operator allocates storage for n doubles after the value of n is obtained interactively. So the array is created on the fly while the program is running. Before get() is used to create another array for a, the current array has to be deallocated with the delete operator. Note that the subscript operator [] must be specified when deleting an array. Note that the array parameter a is a pointer that is passed by reference: void get(double*& a, int& n) This is necessary because the new operator will change the value of a which is the address of the first element of the newly allocated array.
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7.10 USING const WITH POINTERS A pointer to a constant is different from a constant pointer. This distinction is illustrated in the following example. EXAMPLE 7.16 Constant Pointers and Pointers to Constants
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This fragment declares four variables: a pointer p , a constant pointer cp, a pointer pc to a constant, and a constant pointer cpc to a constant: int n = 44; // an int int* p = &n; // a pointer to an int ++(*p); // ok: increments int *p ++p; // ok: increments pointer p int* const cp = &n; // a const pointer to an int ++(*cp); // ok: increments int *cp ++cp; // illegal: pointer cp is const const int k = 88; // a const int const int * pc = &k; // a pointer to a const int ++(*pc); // illegal: int *pc is const ++pc; // ok: increments pointer pc const int* const cpc = &k; // a const pointer to a const int ++(*cpc); // illegal: int *cpc is const ++cpc; // illegal: pointer cpc is const
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Note that the reference operator * may be used in a declaration with or without a space on either side. Thus, the following three declarations are equivalent:
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int* p; int * p; int *p; // indicates that p has type int* (pointer to int) // style sometimes used for clarity // old C style
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[CHAP. 7
7.11 ARRAYS OF POINTERS AND POINTERS TO ARRAYS The elements of an array may be pointers. Here is an array of 4 pointers to type double:
double* p[4];
Its elements can allocated like any other pointer:
p[0] = new double(2.718281828459045); p[1] = new double(3.141592653589793);
p 2.718281828459045
double
We can visualize this array like this. 2 3.141592653589793 The next example illustrates a useful application of double 3 pointer arrays. It shows how to sort a list indirectly by changing the pointers to the elements instead of moving the elements themselves. This is equivalent to the Indirect Bubble Sort shown in Problem 5.12. EXAMPLE 7.17 Indirect Bubble Sort
void sort(float* p[], int n) { float* temp; for (int i = 1; i < n; i++) for (int j = 0; j < n-i; j++) if (*p[j] > *p[j+1]) { temp = p[j]; p[j] = p[j+1]; p[j+1] = temp; } } On each iteration of the inner loop, if the floats of adjacent pointers are out of order, then the pointers are swapped.
7.12 POINTERS TO POINTERS A pointer may point to another pointer. For example,
char c = 't'; char* pc = &c; char** ppc = &pc; char*** pppc = &ppc; ***pppc = 'w'; // changes value of c to 'w'
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