Private array name ( ) As data type in VS .NET

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Private array name ( ) As data type
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Public array name ( ) As data type
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To specify the actual array size, we use the ReDim statement; i.e.,
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ReDim array name (subscript 1 upper limit, subscript 2 upper limit, etc.)
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Lower limits may also appear within the ReDim statement; i.e.,
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ReDim array name ( subscript 1 lower limit To subscript 1 upper limit, subscript 2 lower limit To subscript 2 upper limit, etc.) As data type
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Unlike the Dim statement, integer variables or expressions may be used to represent the subscript limits. The ReDim statement need not immediately follow the Dim statement; it can (and usually does) appear at some later point within the program. Moreover, it may appear more than once, allowing the array to be resized each time it appears.
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Fig. 8.16
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ARRAYS
[CHAP. 8
EXAMPLE 8.12
Here is a skeletal outline of a procedure that utilizes a dynamic array.
Sub Sample() Dim x()As Integer, n As Integer . . . . . ReDim x(10) . . . . . ReDim x(30) . . . . . n = . . . . . ReDim x(n) . . . . . End Sub
Within the Dim statement, we see that x is declared as a dynamic array, because of the empty parentheses. We then dimension x to be a 20-element array. Subsequently, the size of x is again altered, first as a 30-element array, and then as an n-element array. In the last case, the value assigned to the integer variable n will determine the array size.
When a numerical array is redimensioned, the values previously assigned to the array elements will be reset to zero. Similarly, when a string array is redimensioned, the strings previously assigned to the array elements will replaced by empty strings. However, the previously assigned values will be retained if the ReDim statement includes the keyword Preserve; i.e.,
ReDim Preserve array name (subscript 1 upper limit, subscript 2 upper limit, etc.)
When the Preserve feature is utilized, only the upper limit of the last subscript can be altered; i.e., you cannot alter the lower limit of the last subscript, nor can you alter any of the other subscripts.
EXAMPLE 8.13
In this skeletal outline, we make use of the Preserve feature within a ReDim statement.
Sub Sample() Dim x()As Integer, j as Integer . . . . . ReDim x(10) For j = 1 To 10 x(j) = j ^ 2 Next j . . . . . ReDim Preserve x(12) . . . . . End Sub
The For-Next loop assigns a value to each of the ten array elements. The last ReDim statement causes two additional elements to be added to the array, while preserving the ten previously assigned values. Without including Preserve in the ReDim statement, the first ten array elements would have been reset to zero.
CHAP. 8]
ARRAYS
EXAMPLE 8.14 DEVIATIONS ABOUT AN AVERAGE USING DYNAMIC ARRAYS
In Example 8.11 we presented a Visual Basic project that enters a series of numbers, calculates their average and then determines the deviation of each number about the average. We now modify this project to use dynamic arrays. The use of dynamic arrays enhances the generality of the project in several ways. First, the project is no longer restricted to processing ten or fewer numbers. Moreover, the code is simplified in two ways an error trap for values of n greater than 10 is no longer required, nor is a double loop required to clear the array. The modified code is shown below. The new Dim statement and the two required ReDim statements are italicized. Also, note that Format functions have been added to several of the Print statements.
Option Base 1 Dim x() As Double, i As Integer, n As Integer Private Sub Form_Load() Form1.Caption = "Deviations About an Average" Label1.Caption = "Deviations About an Average" Label1.FontSize = 12 Label1.Alignment = 2 'Center Command1.Caption = "Go" Command1.FontSize = 10 Command2.Caption = "Clear" Command2.FontSize = 10 Command2.Enabled = False Command3.Caption = "End" Command3.FontSize = 10 End Sub Private Sub Command1_Click() Dim Prompt As String Dim Sum As Double, Average As Double n = Val(InputBox("How many values ")) ReDim x(n, 2) Command2.Enabled = True 'Calculate the Average Sum = 0 For i = 1 To n Prompt = "Please enter a value for i = " & Str(i) x(i, 1) = Val(InputBox(Prompt)) Sum = Sum + x(i, 1) Next i Average = Sum / n 'Calculate the Deviations About the Average Sum = 0 For i = 1 To n x(i, 2) = x(i, 1) Average Sum = Sum + x(i, 2) Next I
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