how to generate barcode in vb.net 2008 ExERCISE 3-1 Using Compound Assignment Operators in Java

Making Code 3 of 9 in Java ExERCISE 3-1 Using Compound Assignment Operators

ExERCISE 3-1 Using Compound Assignment Operators
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This exercise will clear up any confusion about compound assignment operators. The following application will be used for the exercise. Don t run it until after step 3.
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public class Main { public static void main(String[] args) { byte a; a = 10; System.out.println(a += 3); a = 15; System.out.println(a -= 3); a = 20; System.out.println(a *= 3); a = 25; System.out.println(a /= 3); a = 30; System.out.println(a %= 3); /* Optional as outside of scope of exam */ a = 35; System.out.println(a &= 3); a = 40; System.out.println(a ^= 3); a = 45;
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Programming with Java Operators and Strings
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System.out.println(a a = 50; System.out.println(a a = 55; System.out.println(a a = 60; System.out.println(a /* End optional */ } }
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|= 3); <<= 3); >>= 3); >>>= 3);
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1. Grab a pencil and a piece of paper. Optionally, you can use Table 3-2 as your worksheet. 2. For each statement that has a compound assignment operator, rewrite the statement without the compound assignment operator and replace the variable with its associated value. For example, let s take the assignment statement with the addition compound assignment operator:
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a = 5; System.out.println(a += 3);
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It would be rewritten as (a = a + 3), specifically (a = 5 + 3);
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TABlE 3-2
Refactoring Compound Assignment Statements
Assigned Value of a
a = 10; a = 15; a = 20; a = 25; a = 30; a = 35; a = 40; a = 45; a = 50; a = 55; a = 60;
Compound Assignment
a += 3; a -= 3; a *= 3; a /= 3; a %= 3; a &= 3; a ^= 3; a |= 3; a <<= 3; a >>= 3; a >>>= 3;
Refactored Statement
a = 10 + 3;
New Value of a
Understanding Fundamental Operators
3. Evaluate the expressions, without using a computer. 4. Compile and run the given application. Compare your results. Note that many of these operators do not appear on the exam. The point of the exercise is getting you properly acquainted with compound assignment operators, by repetition.
Arithmetic Operators
The exam will include nine arithmetic operators. Five of these operators are used for basic operations (addition, subtraction, multiplication, division, and modulus). The other four operators are used for incrementing and decrementing a value. We ll examine the five operators used for basic operations first.
Basic Arithmetic Operators
The five basic arithmetic operators are
n + addition (sum) operator n - subtraction (difference) operator n * multiplication (product) operator n / division (quotient) operator n % modulus (remainder) operator
Adding, subtracting, multiplying, dividing, and producing remainders with operators is straightforward. The following examples demonstrate this.
/* Addition (+) operator example */ int greyCannonBalls = 50; int blackCannonBalls = 50; int totalCannonBalls = greyCannonBalls + blackCannonBalls; // 100 /* Subtraction (-) operator example */ int firedCannonBalls = 10; totalCannonBalls = totalCannonBalls - firedCannonBalls; // 90 /* Multiplication (*) operator example */ int matches = 20;
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int matchboxes = 20; int totalMatches = matches * matchboxes; // 400 /* Division (/) operator example */ int pirates = 104; int pirateShips = 3; int assignedPiratesPerShip = pirates / pirateShips; // 34 /* Remainder (modulus) (%) operator example */ (left operand is divided by right operand and the remainder is produced) int pirateRemainder = pirates % pirateShips; // 2
Prefix Increment, Postfix Increment, Prefix Decrement, and Postfix Decrement Operators
Four operators allow decrementing or incrementing of variables:
n ++x prefix increment operator n --x prefix decrement operator n x++ postfix increment operator n x-- postfix decrement operator
Prefix increment and prefix decrement operators provide a shorthand way of incrementing the value of a variable by 1. Rather than creating an expression as y=x+1, you could write y=++x. Similarly, you could replace the expression y=x-1 with y=--x. This works because the execution of the prefix operators occurs on the operand prior to the evaluation of the whole expression. Postfix increment and postfix decrement characters execute the postfix operators after the expression has been evaluated. Therefore y = x++ would equate to y=x followed by x=x+1. And y = x-- would equate to y=x, followed by x=x-1. It s important to note that y=++x is not exactly equivalent to y=x+1 because the value of x changes in the former but not in the latter. This is the same for y=--x and y=x-1. The prefix increment operator increments a value by 1 before an expression has been evaluated.
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