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Answer:
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3 A . The first expression statement (!(true & !(false))) evaluates to false. Here, the right operand is negated to true by the (Boolean invert) operator, the Boolean AND operator equates the expression of the two operands to true, and the (Boolean invert) operator equates the resultant value to false. The second expression statement (!(true | !(false))) evaluates to false. Here, the right operand is negated to true by the (Boolean invert) operator, the Boolean OR operator equates the expression of the two operands to true, and the (Boolean invert) operator equates the resultant value to false. The third expression statement (!(true ^ !(false))) evaluates to true. Here, the right operand is negated to true by the (Boolean invert) operator, the Boolean XOR operator equates the expression of the two operands to false, and the (Boolean invert) operator equates the resultant value to true.
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B, C, nd D are incorrect answers as justified by the correct answer s explanation. a 5. Given:
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public class ArithmeticResultsOutput { public static void main (String[] args) int i1 = 100; int j1 = 200; if ((i1 == 99) & (--j1 == 199)) { System.out.print("Value1: " + (i1 + } else { System.out.print("Value2: " + (i1 + } int i2 = 100; int j2 = 200; if ((i2 == 99) && (--j2 == 199)) { System.out.print("Value1: " + (i2 + } else { System.out.print("Value2: " + (i2 + } int i3 = 100; int j3 = 200; if ((i3 == 100) | (--j3 == 200)) { System.out.print("Value1: " + (i3 + } else { System.out.print("Value2: " + (i3 + } int i4 = 100; int j4 = 200; if ((i4 == 100) || (--j4 == 200)) { System.out.print("Value1: " + (i4 + } else { System.out.print("Value2: " + (i4 + } } } {
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j1) + " "); j1) + " ");
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What will be printed to standard out
A. Value2: 300 Value2: 300 Value1: 300 Value1: 300
B. Value2: 299 Value2: 300 Value1: 299 Value1: 300 C. Value1: 299 Value1: 300 Value2: 299 Value2: 300 D. Value1: 300 Value1: 299 Value2: 300 Value2: 299
Answer:
3 B is the correct because Value2: 299 Value2: 300 Value1: 299 Value1: 300 will be printed to the standard out. Note that && and || are short-circuit operators. So When the first operand of a conditional AND (&&) expression evaluates to false, the second operand is not evaluated. When the first operand of a conditional OR (||) expression evaluates to true, the second operand is not evaluated. Thus, for the second and fourth if statements, the second operand isn t evaluated. Therefore, the prefix increment operators are never executed and do not affect the values of the j[x] variables.
A, C,and D are incorrect answers as justified by the correct answer s explanation. 6. Given the following code segment:
public void validatePrime() { long p = 17496; // 'prime number' candidate Double primeSquareRoot = Math.sqrt(p); boolean isPrime = true; for (long j = 2; j <= primeSquareRoot.longValue(); j++) { if (p % j == 0) { // Print divisors System.out.println(j + "x" + p / j); isPrime = false; } } System.out.println("Prime number: " + isPrime); }
Which of the following is true Hint: 17496 is not a prime number. A. The code will not compile due to a syntactical error somewhere in the code. B. he code will not compile since the expression (p % j == 0) should be written as T ((p % j) == 0). C. D. Divisors will be printed to standard out (for example, x8478, and so on), along with 2 Prime number: false as the final output. Divisors will be printed to standard out (for example, x8478, and so on), along with 2 Prime number: 0 as the final output.
3:
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