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SQL Server 2000 Stored Procedure & XML Programming
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You should not use a cursor as an output parameter of a stored procedure unless you have to. Such a solution is inferior because procedures are coupled and prone to errors. If you are working with SQL Server 2000, you should use table-valued user-defined functions as part of your Select statements instead.
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Using Identity Values
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In previous chapters, I introduced the function of identity values in a table. They are used to generate surrogate keys unique identifiers based on sequential numbers.
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Identity values are similar to the autonumber data type in Access tables. But there is one difference that generates many questions in Usenet newsgroups among developers who are used to Access/DAO behavior. When you insert a record into a table, the value of the autonumber fied is immediately available in Access. Unfortunately, due to the nature of the client/server environment, this is not the case in SQL Server. The best way to insert a record into a SQL Server table and obtain an identity key is to use a stored procedure. The following stored procedure, prInsertInventory, presents such a solution. A new record is inserted into a table and the key is read using the @@identity function.
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Create Procedure prInsertInventory -- insert inventory record and return Id @intEquipmentId int, @intLocationId int, @inyStatusId tinyint, @intLeaseId int, @intLeaseScheduleId int, @intOwnerId int, @mnsRent smallmoney, @mnsLease smallmoney, @mnsCost smallmoney, @inyAcquisitionTypeID int, @intInventoryId int output As Set Nocount On Declare @intErrorCode int Select @intErrorCode = @@Error
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9: Advanced Stored Procedure Programming
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If @intErrorCode = 0 Begin Insert into Inventory (EquipmentId, LocationId, StatusId, LeaseId, LeaseScheduleId, OwnerId, Rent, Lease, Cost, AcquisitionTypeID) Values ( @intEquipmentId, @intLocationId, @inyStatusId, @intLeaseId, @intLeaseScheduleId, @intOwnerId, @mnsRent, @mnsLease, @mnsCost, @inyAcquisitionTypeID) Select @intErrorCode = @@Error, @intInventoryId = @@identity End Return @intErrorCode
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Identity Values and Triggers
Unfortunately, the previous solution does not always work as you might expect. SQL Server has a bug/feature that can change a value stored in the @@identity global variable. If the table in which the record was inserted (in this case, Inventory) has a trigger that inserts a record into some other table with an identity key, the value of that key will be recorded in @@identity. You can reproduce this behavior using the following script. It must be executed against the tempdb database.
Create Table a (a_id int identity(1,1), a_desc varchar(20), b_desc varchar(20)) Go Create Table b (b_id int identity(1,1), b_desc varchar(20)) Go Create Trigger tr_a_I On dbo.a After Insert -- For Insert As If @@Rowcount = 0 Return Insert Into b (b_desc)
SQL Server 2000 Stored Procedure & XML Programming
Select b_desc from inserted Go
Now execute this batch:
Insert into b (b_desc) Values ('1') Insert into a (a_desc, b_desc) Values ('aaa', 'bbb') Select @@identity [IdentityValue]
Query Analyzer returns the following result:
(1 row(s) affected)
(1 row(s) affected)
IdentityValue ---------------------------------------2 (1 row(s) affected)
The first Insert statement adds the first record to table b. The second Insert statement adds the first record in a table. Because there is a trigger on the table, another record (the second one) will be inserted into table b, and the value of @@identity will be set to 2. If there was no trigger, the Select statement would return a value of 1.
Last Identity Value in the Scope
The problem with identity values and triggers has been resolved in the proper manner with SQL Server 2000. The new Scope_Identity() function returns the last identity value generated in the current scope of the current process. The following example adds this function to the code executed earlier against the tempdb database:
Insert into b (b_desc) Values ('1') Insert into a (a_desc, b_desc)
9: Advanced Stored Procedure Programming
Values ('aaa', 'bbb')
Select @@identity [@@Identity], SCOPE_IDENTITY() [SCOPE_IDENTITY()]
When you execute it, notice that the Scope_Identity() function returns the proper result:
(1 row(s) affected) (1 row(s) affected) @@Identity SCOPE_IDENTITY() ---------------------------------------- ----------------------------4 2 (1 row(s) affected)
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