visual basic barcode printing Legal Overloads in Java

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Legal Overloads
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Let s look at a method we want to overload:
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public void changeSize(int size, String name, float pattern) { }
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The following methods are legal overloads of the changeSize() method:
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public void changeSize(int size, String name) { } public int changeSize(int size, float pattern) { } public void changeSize(float pattern, String name) throws IOException { }
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Be careful to recognize when a method is overloaded rather than overridden. You might see a method that appears to be violating a rule for overriding, but which is actually a legal overload, as follows:
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Overridden and Overloaded Methods (Exam Objective 6.2)
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public class Foo { public void doStuff(int y, String s) { } public void moreThings(int x) { } } class Bar extends Foo { public void doStuff(int y, float s) throws IOException { } }
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You might be tempted to see the IOException as the problem, seeing that the overridden doStuff() method doesn t declare an exception, and knowing that IOException is checked by the compiler. But the doStuff() method is not overridden at all! Subclass Bar overloads the doStuff() method, by varying the argument list, so the IOException is fine.
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Invoking Overloaded Methods
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When a method is invoked, more than one method of the same name might exist for the object type you re invoking a method on. For example, the Horse class might have three methods with the same name but with different argument lists, which means the method is overloaded. Deciding which of the matching methods to invoke is based on the arguments. If you invoke the method with a String argument, the overloaded version that takes a String is called. If you invoke a method of the same name but pass it a float, the overloaded version that takes a float will run. If you invoke the method of the same name but pass it a Foo object, and there isn t an overloaded version that takes a Foo, then the compiler will complain that it can t find a match. The following are examples of invoking overloaded methods:
class Adder { public int addThem(int x, int y) { return x + y; } // Overload the addThem method to add doubles instead of ints public double addThem(double x, double y) { return x + y; } } // From another class, invoke the addThem() method public class TestAdder { public static void main (String [] args) {
5: Object Orientation, Overloading and Overriding, Constructors, and Return Types
Adder add = new Adder(); int b = 27; int c = 3; int result = a.addThem(b,c); // Which addThem is invoked double doubleResult = a.addThem(22.5,89.36); // Which addThem } }
In the preceding TestAdder code, the first call to a.addThem(b,c) passes two ints to the method, so the first version of addThem() the overloaded version that takes two int arguments is called. The second call to a.addThem(22.5, 89.36) passes two doubles to the method, so the second version of addThem() the overloaded version that takes two double arguments is called. Invoking overloaded methods that take object references rather than primitives is a little more interesting. Say you have an overloaded method such that one version takes an Animal and one takes a Horse (subclass of Animal). If you pass a Horse object in the method invocation, you ll invoke the overloaded version that takes a Horse. Or so it looks at first glance:
class Animal { } class Horse extends Animal { } class UseAnimals { public void doStuff(Animal a) { System.out.println("In the Animal version"); } public void doStuff(Horse h) { System.out.println("In the Horse version"); } public static void main (String [] args) { UseAnimals ua = new UseAnimals(); Animal animalObj = new Animal(); Horse horseObj = new Horse(); ua.doStuff(animalObj); ua.doStuff(horseObj); } }
The output is what you expect:
Overridden and Overloaded Methods (Exam Objective 6.2)
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