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Hashtable: Like a slower HashMap (as with Vector, due to its synchronized
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methods). No null values or null keys allowed
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LinkedHashMap: Faster iterations; iterates by insertion order or last accessed,
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allows one null key, many null values (new with 1.4)
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TreeMap: A sorted map, in natural order Garbage Collection In Java, garbage collection provides some automated memory management. All objects in Java live on the heap.
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7: Objects and Collections
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The heap is also known as the garbage collectible heap. The purpose of garbage collecting is to find and delete objects that can t
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Only the JVM decides exactly when to run the garbage collector. You (the programmer) can only recommend when to run the garbage collector. You can t know the G.C. algorithm; maybe it uses mark and sweep, maybe it s
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Objects must be considered eligible before they can be garbage collected. An object is eligible when no live thread can reach it. To reach an object, a live thread must have a live, reachable reference variable
to that object.
Java applications can run out of memory. Islands of objects can be garbage collected, even though they have references. To reiterate: garbage collection can t be forced. Request garbage collection with System.gc(); (recommended). Class Object has a finalize() method. The finalize() method is guaranteed to run once and only once before
the garbage collector deletes an object.
Since the garbage collector makes no guarantees, finalize() may never run. You can uneligibilize an object from within finalize().
Self Test
SELF TEST
The following questions will help you measure your understanding of the material presented in this chapter. Read all of the choices carefully, as there may be more than one correct answer. Choose all correct answers for each question.
HashCode and equals() (Exam Objective 9.2)
1. Given the following,
11. 12. 13. 14. 15. 16. x = 0; if (x1.hashCode() != x2.hashCode() ) if (x3.equals(x4) ) x = x + 10; if (!x5.equals(x6) ) x = x + 100; if (x7.hashCode() == x8.hashCode() ) System.out.println("x = " + x); x = x + 1;
x = x + 1000;
and assuming that the equals () and hashCode() methods are property implemented, if the output is x = 1111 , which of the following statements will always be true
A. x2.equals(x1) B. x3.hashCode() == x4.hashCode() C. x5.hashCode() != x6.hashCode() D. x8.equals(x7) 2. Given the following,
class Test1 { public int value; public int hashCode() { return 42; } } class Test2 { public int value; public int hashcode() { return (int)(value^5); } }
which statement is true
A. class Test1 will not compile. B. The Test1 hashCode() method is more efficient than the Test2 hashCode() method. C. The Test1 hashCode() method is less efficient than the Test2 hashCode() method.
7: Objects and Collections
D. class Test2 will not compile. E. The two hashcode() methods will have the same efficiency. 3. Which two statements are true about comparing two instances of the same class, given that the equals() and hashCode() methods have been properly overridden (Choose two.) A. If the equals() method returns true, the hashCode() comparison == must return true. B. If the equals() method returns false, the hashCode() comparison != must return true. C. If the hashCode() comparison == returns true, the equals() method must return true. D. If the hashCode() comparison == returns true, the equals() method might return true. E. If the hashCode() comparison != returns true, the equals() method might return true. 4. Which class does not override the equals() and hashCode() methods, inheriting them directly from class Object A. java.lang.String B. java.lang.Double C. java.lang.StringBuffer D. java.lang.Character E. java.util.ArrayList 5. What two statements are true about properly overridden hashCode() and equals() methods A. hashCode() doesn t have to be overridden if equals() is. B. equals() doesn t have to be overridden if hashCode() is. C. hashCode() can always return the same value, regardless of the object that invoked it. D. If two different objects that are not meaningfully equivalent both invoke hashCode(), then hashCode() can t return the same value for both invocations. E. equals() can be true even if it s comparing different objects.
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