visual basic barcode program %java BitShift Before shift x equals -2147483648 After shift x equals 134217728 in Java

Creator PDF417 in Java %java BitShift Before shift x equals -2147483648 After shift x equals 134217728

%java BitShift Before shift x equals -2147483648 After shift x equals 134217728
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As we can see, the new number is positive because the negative bit wasn t kept. In bit representation, the old number is
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1000 0000 0000 0000 0000 0000 0000 0000
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and the new number is
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0000 1000 0000 0000 0000 0000 0000 0000
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Notice how the leftmost bits are filled in with zeroes, even though the original sign bit was a 1. That s why the unsigned right shift operator is often referred to as the zero filled right shift operator. One important implication of using >>> vs. >> is that the result of an unsigned right shift is always positive, regardless of the original sign bit. You also need to know that all operands in a bit shift are promoted to at least an int (a long if the second operand is a long). And what happens if you try to shift by more places than the number of bits in the number being shifted For example, what happens if you try to shift an int by 33 The rule to remember is: the number of bits shifted is always going to be the right operand modulus the total number of bits for that primitive type. So for an int, that means you ll shift by the right operand modulus 32, and for a long, the right operand modulus 64. For example, if you try to shift an int by, say, 34, it looks like this,
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int x = 2; int y = x >> 34;
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3: Operators and Assignments
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but because it s meaningless to shift by 34, since you don t even have that many bits, you actually end up shifting by 34 % 32 (we can use the remainder operator to figure this out), which leaves us with a remainder of 2. So the result is actually
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int y = x >> 2;
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You need to know what the bit shifts are actually doing in practical terms. A right shift operator is actually causing the number being shifted to be divided by 2 to the power of the number of bits to shift. For example, shifting x >> 4 4 8 is exactly the same as saying x / 2 . And x >> 8 is exactly the same as x / 2 . With the left shift operator, the result is exactly the same as multiplying the number being shifted by 2 to the power of the number of bits to shift. So shifting x << 3 is the same as saying x * 23. One day, you will thank us for pointing this out. (We accept checks and chocolate!)
EXERCISE 3-1 Using Shift Operators
1. Try writing a class that takes an integer of 1, shifts the bit 31 to the left, then 31 to the right. 2. What number does this now represent 3. What is the bit representation of the new number
Bitwise Operators
The bitwise operators take two individual bit numbers, then use AND/OR to determine the result on a bit-by-bit basis. There are three bitwise operators:
& AND | inclusive OR ^ exclusive OR
The & operator compares corresponding bits between two numbers. If both bits are 1, the final bit is also 1. If only one of the bits is 1, the resulting bit is 0.
Java Operators (Exam Objective 5.1)
Once again, for bitwise operations we must convert numbers to bit representations. Table 3-3 displays the truth table for each of these operators. The left side of the table displays the x and y values, and the right side shows the result of the operator on these two values. Let s compare two numbers, 10 and 9, with the & operator:
1010 & 1001 = 1000
Try putting the second operand directly beneath the first, to make it easier to see the result. For the preceding comparison (10 and 9), you can look at it as
1 0 1 0 & 1 0 0 1 ___________ 1 0 0 0
As we can see, only the first bit (8) is a 1 in both locations, hence the final number is 1000 in bit representation (or 8 in decimal). Let s see this in some code:
class Bitwise { public static void main(String [] args) { int x = 10 & 9; // 1010 and 1001 System.out.println("1010 & 1001 = " + x); } }
When we run this code, the following output is produced:
%java Bitwise 1010 & 1001 = 8
The | (OR) operator is different from the & (AND) operator when it compares corresponding bits. Whereas the & operator will set a resulting bit to 1 only if both
TABLE 3-3
X 0 0 1
Y 0 1 0
& (AND) 0 0 0
| (OR) 0 1 1
^ (XOR) 0 1 1
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