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qr code vb.net free Impedance Transformation in Visual Studio .NET
CHAPTER 9 Impedance Transformation Code 128 Reader In .NET Framework Using Barcode Control SDK for .NET framework Control to generate, create, read, scan barcode image in .NET framework applications. Drawing ANSI/AIM Code 128 In Visual Studio .NET Using Barcode generator for .NET framework Control to generate, create Code 128C image in Visual Studio .NET applications. Problem 181 Suppose, in Fig. 208, that the inductance of each coil is 800 microhenrys and that C 0:04 microfarads. What value of RL should be used At what frequency will the characteristic impedance be equal to zero What value of impedance will the generator see at the frequency at which Z0 0 (d) Why doesn t the generator see zero impedance in part (c) r 1 C Thus, since , we have that RL L r r p !L C L2 C ! LC !L ! RL L L hence eq. (348) becomes " 1 V2 p 2 LC=2 j! LC 1 !2 LC=4 V1 1 ! which has the form " 1 V2 V1 A jB In the above the variable is frequency, ! radians/second, in which ! denotes ANY FREQUENCY in general. It will be helpful, however, in understanding what eq. (351) says, if the equation is written in terms of the ratio of ! to some PARTICULAR VALUE of ! that we ll denote by !0 . In doing this, !0 can be any particular value we choose, but in the case of eq. (351) one convenient way would be to set !2 0 that is, LC 4 !2 0 352 4 LC 351 (a) (b) (c) Read Code128 In VS .NET Using Barcode reader for .NET Control to read, scan read, scan image in .NET applications. Encoding Barcode In .NET Framework Using Barcode encoder for VS .NET Control to generate, create bar code image in Visual Studio .NET applications. and if you now substitute the above value of LC into eq. (351) you should nd that " 1 V2 V1 1 2 !=!0 2 j2 !=!0 1 !=!0 2 353 Barcode Reader In Visual Studio .NET Using Barcode scanner for Visual Studio .NET Control to read, scan read, scan image in .NET framework applications. Printing Code 128 Code Set C In C# Using Barcode printer for .NET framework Control to generate, create Code 128C image in VS .NET applications. " so that the ratio 2 =V1 is now expressed in terms of the value of ! relative to the xed p V value !0 2= LC , and we say that the equation is normalized relative to !0 . The advantage of doing this is that now we can investigate eq. (351) in general terms without having to carry along the values of L and C. As a further step let us make the substitution h !=!0 thus eq. (352) becomes " 1 1 V2 V1 1 2h2 j2h 1 h2 A jB 355 354 USS Code 128 Generator In VS .NET Using Barcode creator for ASP.NET Control to generate, create USS Code 128 image in ASP.NET applications. Code 128 Code Set A Maker In Visual Basic .NET Using Barcode printer for .NET framework Control to generate, create Code 128C image in Visual Studio .NET applications. CHAPTER 9 Impedance Transformation
GS1 RSS Drawer In VS .NET Using Barcode printer for .NET Control to generate, create GS1 DataBar14 image in Visual Studio .NET applications. Encode Matrix Barcode In .NET Framework Using Barcode drawer for Visual Studio .NET Control to generate, create 2D Barcode image in Visual Studio .NET applications. Now let it be given that we wish to investigate only the manner in which the magnitude " of V2 =V1 varies with h; in which case you can verify that eq. (355) becomes " V2 1 1 p p 356 V 2 B2 A 1 4 h6 h4 1 thus, " V2 1 4 h6 h4 1=2 V 1 GTIN  13 Generator In .NET Framework Using Barcode creation for VS .NET Control to generate, create GTIN  13 image in .NET framework applications. Industrial 2 Of 5 Generator In .NET Framework Using Barcode creator for Visual Studio .NET Control to generate, create 2/5 Industrial image in VS .NET applications. 357 Make EAN13 In Java Using Barcode creation for Android Control to generate, create EAN13 image in Android applications. Make UPCA Supplement 2 In VS .NET Using Barcode maker for ASP.NET Control to generate, create UPC Code image in ASP.NET applications. which in terms of decibels becomes (see eqs. (319), (320), and (321)) dB 10 log 1 4 h6 h4 358 Reading Bar Code In None Using Barcode reader for Software Control to read, scan read, scan image in Software applications. Code39 Maker In None Using Barcode generator for Font Control to generate, create Code39 image in Font applications. Now, using your calculator, you can verify that the following table of values is correct for eq. (358), in which we ve rounded o dB values to two decimal places. Bar Code Decoder In Visual Basic .NET Using Barcode Control SDK for .NET Control to generate, create, read, scan barcode image in .NET framework applications. Barcode Encoder In C# Using Barcode generator for .NET framework Control to generate, create bar code image in .NET framework applications. h 0.1 0.2 0.4 0.6 0.8 0.9 dB 0.00 0.03 0.39 1.75 3.87 3.00 h 1.0 1.2 1.4 1.6 1.8 2.0 2.2 dB 0.00 6.67 11.97 16.22 19.73 22.86 25.57 Make UPCA Supplement 2 In ObjectiveC Using Barcode printer for iPad Control to generate, create UPCA Supplement 5 image in iPad applications. EAN128 Maker In Java Using Barcode maker for Eclipse BIRT Control to generate, create GS1 128 image in Eclipse BIRT applications. A plot of the above results on semilog paper is given in Fig. 209, with a brief discussion following. Fig. 209
Thus the gain of the lowpass network of Fig. 208 is practically constant from h 0 to h 0:3; then, as h increases, the gain rises to a maximum value of 3.87 dB for h 0:8, after which the gain rapidly decreases as h increases in value. The rise in gain from h 0:3 to CHAPTER 9 Impedance Transformation
h 1:0 is due to a resonant condition that comes into play between L and C, the e ect peaking, very approximately, at h 0:8. Then, as h increases in value beyond h 1:0, the condition of resonance is lost and the gain begins to rapidly decrease. It is thus the presence of both inductance and capacitance, L and C, having the possibility of resonance, that causes the curve of Fig. 209 to be so much improved over the simple curve of Fig. 191. As inspection of Fig. 209 shows that the gain falls o rapidly for values of h greater than 1, and for that reason h 1 is sometimes taken to be the cuto condition for Fig. 208. Since h !=!0 , it follows that h 1 when ! !0 ; thus the cuto frequency, !c , can be taken to be equal to !0 and hence, by eq. (352), 2 !c p LC 359 Lastly, we should mention that the term constantk is applied to Fig. 208 because the " " values of Z1 and Z2 are such that their product has a constant value, independent of frequency; thus " " Z1 Z2 j!L 1=j!C L=C Problem 182 In Fig. 208, suppose C 0:015 mF. If a cuto frequency of 100,000 Hz is desired, what must be the inductance of each coil (Answer: 337.7 mH) Problem 183 " Using eq. (355), show that the phase shift of V2 with respect to V1 is equal to arctan 2h 1 h2 = 1 2h2

