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qr code generator vb.net Reactance and Impedance in Visual Studio .NET
CHAPTER 8 Reactance and Impedance Code 128 Code Set C Reader In VS .NET Using Barcode Control SDK for VS .NET Control to generate, create, read, scan barcode image in .NET framework applications. Code 128 Code Set C Printer In .NET Using Barcode creation for Visual Studio .NET Control to generate, create Code 128B image in .NET applications. In using the foregoing equations, all we need do is write each impedance in the form of a complex number R j!L, and then apply the algebra of complex numbers, remembering j 2 1. Problem 118 In Fig. 133, the resistance and inductance values are in ohms and henrys. Scanning ANSI/AIM Code 128 In .NET Using Barcode decoder for .NET Control to read, scan read, scan image in .NET framework applications. Barcode Creation In .NET Framework Using Barcode generator for Visual Studio .NET Control to generate, create barcode image in Visual Studio .NET applications. Fig. 133
Reading Barcode In VS .NET Using Barcode reader for .NET Control to read, scan read, scan image in Visual Studio .NET applications. Painting Code 128A In C#.NET Using Barcode drawer for .NET framework Control to generate, create Code 128C image in .NET framework applications. " Given that the applied reference voltage V is 60 volts rms, and that ! 2f 100 rad/sec, nd* " (a) impedance ZT seen by generator, " (b) generator current IT , (c) (d) (e) (f ) (g) phase angle between generator voltage and generator current, " I1 " I2 " I3 Encode Code 128C In .NET Framework Using Barcode creation for ASP.NET Control to generate, create Code128 image in ASP.NET applications. Making Code 128A In Visual Basic .NET Using Barcode printer for .NET framework Control to generate, create USS Code 128 image in .NET framework applications. verify that the sum of the answers to (d), (e), (f ) equals the answer to (b). " (h) using V V =08 60 volts rms as the reference vector, make a rough sketch of the vector diagram showing the answers to (d) through (g). Problem 119 The load on a generator of V =08 volts rms consists of a resistance of R ohms in parallel with a coil of inductance L henrys, as shown in Fig. 134. Encode Linear Barcode In VS .NET Using Barcode encoder for Visual Studio .NET Control to generate, create 1D image in .NET framework applications. Painting EAN 128 In Visual Studio .NET Using Barcode encoder for .NET Control to generate, create GS1128 image in .NET applications. Fig. 134
Barcode Generator In .NET Using Barcode maker for VS .NET Control to generate, create bar code image in .NET framework applications. Code 93 Encoder In Visual Studio .NET Using Barcode encoder for Visual Studio .NET Control to generate, create USS 93 image in VS .NET applications. " Using eq. (209), write the equation for the generator current IT . Write the nal 0 00 answer in the rectangular form I jI . Bar Code Creation In None Using Barcode generation for Font Control to generate, create bar code image in Font applications. Painting Barcode In None Using Barcode generator for Font Control to generate, create barcode image in Font applications. * We are here assuming there is NO MAGNETIC COUPLING between the two coils; that is, the magnetic eld of each coil is con ned to that coil only. The important case where this is not true is studied in Chap. 10. Generate Code 128A In C# Using Barcode generator for Visual Studio .NET Control to generate, create Code 128B image in VS .NET applications. UCC  12 Generator In None Using Barcode maker for Software Control to generate, create UCC  12 image in Software applications. CHAPTER 8 Reactance and Impedance
UCC128 Maker In .NET Framework Using Barcode printer for Reporting Service Control to generate, create EAN / UCC  14 image in Reporting Service applications. Generating UPCA Supplement 5 In Java Using Barcode maker for Java Control to generate, create UPCA Supplement 5 image in Java applications. Let us pause here, just a moment, to again point out the close correspondence between the procedures used in dc circuit analysis and steadystate ac circuit analysis. Consider, for example, eqs. (32) and (34) in section 2.6; note that, to convert these two " equations to the ac case (eqs. (207) and (209)), all we need do is replace the Rs with Z s " R j!L) and apply the algebra of complex numbers, remembering that (in which Z j 2 1. In the same way, the treatment of seriesparallel ac networks exactly parallels the " treatment of dc networks in section 2.7, with the Rs replaced by Z s. Likewise, the basic dc procedure of loop current analysis, explained in section 4.4, applies also to ac circuit analysis, remembering, of course, that j 2 1. In this regard, " consider the example of Fig. 135, containing two ac generators of known voltages V1 and "2 and three unknown loop currents, as shown. V Making EAN13 Supplement 5 In None Using Barcode drawer for Online Control to generate, create EAN13 image in Online applications. 1D Barcode Printer In Visual C# Using Barcode printer for .NET Control to generate, create 1D image in .NET framework applications. Fig. 135
All the quantities in Fig. 135 denote complex numbers representing both the rms vector " values of voltage and current and the passive network components (the Z s). In this regard, using eq. (158) in Chap. 6, the two generator voltages can be put in the complex rectangular form; thus " V1 V1 =08 V1 cos 0 j sin 0 V1 1 j0 V1 and " V2 V2 =8 V2 cos j sin V20 jV200 In the example of Fig. 135, let us assume that the voltages and impedances are given, and that the problem is to nd the unknown values of the currents. In doing this, the voltage and current arrows shown in the gure are used in conjunction with KIRCHHOFF s VOLTAGE LAW, following the same basic procedure outlined for dc networks in section 4.4, except now we re dealing with complex (vector) quantities instead of scalar "" quantities. Also, the VOLTAGE DROPS will now be of the form ZI instead of RI as in the dc case. Thus, upon applying the rules of section 4.4, we have that the equations for the ac network of Fig. 135 are " " " " " " Z2 I2 0 I3 V1 Z1 Z2 I1 " " " " " " " " Z2 I1 Z2 Z3 Z4 I2 Z4 I3 0 " " " " " " " 0 I1 Z4 I2 Z4 Z5 I3 V2 " In regard to Fig. 135, it should be noted that the value of voltage V2 must be given with " respect to the reference voltage V1 V1 =08. Fundamentally, this is done by remembering that the voltages are sinusoidal waves of the same frequency, the wave of V2 being degrees out of phase with V1 . (See discussion given with eq. (108) in section 5.6.) Lastly, to solve the resulting simultaneous equations for any particular value of current it will generally be easiest to use the method of determinants.

