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barcode printing using vb.net Current calculations in Software
Current calculations Denso QR Bar Code Scanner In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. Make QR Code In None Using Barcode creator for Software Control to generate, create Quick Response Code image in Software applications. The first way to use Ohm s Law is to find current values in dc circuits. In order to find the current, you must know the voltage and the resistance, or be able to deduce them. Refer to the schematic diagram of Fig. 47. It consists of a variable dc generator, a voltmeter, some wire, an ammeter, and a calibrated, widerange potentiometer. Component values have been left out of this diagram, so it s not a wiring diagram. But QRCode Reader In None Using Barcode recognizer for Software Control to read, scan read, scan image in Software applications. Encode QR Code JIS X 0510 In C#.NET Using Barcode generation for Visual Studio .NET Control to generate, create QR Code image in .NET applications. 70 Basic dc circuits values can be assigned for the purpose of creating sample Ohm s Law problems. While calculating the current in the following problems, it is necessary to mentally cover up the meter. Denso QR Bar Code Generation In VS .NET Using Barcode generator for ASP.NET Control to generate, create QR Code ISO/IEC18004 image in ASP.NET applications. Create Denso QR Bar Code In .NET Using Barcode encoder for Visual Studio .NET Control to generate, create Denso QR Bar Code image in VS .NET applications. Circuit for working Ohm s Law problems.
Denso QR Bar Code Encoder In VB.NET Using Barcode encoder for .NET Control to generate, create QR image in .NET framework applications. Make Code39 In None Using Barcode generation for Software Control to generate, create Code 3 of 9 image in Software applications. Suppose that the dc generator (Fig. 47) produces 10 V, and that the potentiometer is set to a value of 10 . Then what is the current This is easily solved by the formula I E/R. Just plug in the values for E and R; they are both 10, because the units were given in volts and ohms. Then I 10/10 1 A. Printing Data Matrix ECC200 In None Using Barcode encoder for Software Control to generate, create Data Matrix image in Software applications. EAN 13 Creation In None Using Barcode creator for Software Control to generate, create GS1  13 image in Software applications. Problem 42 Barcode Maker In None Using Barcode maker for Software Control to generate, create barcode image in Software applications. Generate GTIN  128 In None Using Barcode creation for Software Control to generate, create EAN / UCC  13 image in Software applications. The dc generator (Fig. 47) produces 100 V and the potentiometer is set to 10 K . What is the current First, convert the resistance to ohms: 10 K 10,000 . Then plug the values in: I 100/10,000 0.01 A. This might better be expressed as 10 mA. Engineers and technicians prefer to keep the numbers within reason when specifying quantities. Although it s perfectly all right to say that a current is 0.01 A, it s best if the numbers can be kept at 1 or more, but less than 1,000. It is a little silly to talk about a current of 0.003 A, or a resistance of 107,000 , when you can say 3 mA or 107 K . UCC  14 Encoder In None Using Barcode generation for Software Control to generate, create EAN  14 image in Software applications. UPCA Maker In ObjectiveC Using Barcode drawer for iPhone Control to generate, create GTIN  12 image in iPhone applications. Problem 43 Make EAN13 In None Using Barcode creation for Excel Control to generate, create EAN13 image in Microsoft Excel applications. Bar Code Drawer In Java Using Barcode creator for Android Control to generate, create bar code image in Android applications. The dc generator (Fig. 47) is set to provide 88.5 V, and the potentiometer is set to 477 M . What is the current This problem involves numbers that aren t exactly round, and one of them is huge. But you can use a calculator. The resistance is first changed to ohms, giving E/R 88.5/ 477,000,000 . Then you plug into the Ohm s Law formula: I 477,000,000 0.000000186 A 0.186 uA. This value is less than 1, but there isn t much European Article Number 13 Encoder In None Using Barcode drawer for Font Control to generate, create EAN13 image in Font applications. UPCA Creator In ObjectiveC Using Barcode printer for iPad Control to generate, create UPCA image in iPad applications. Problem 41 Data Matrix ECC200 Decoder In Visual Basic .NET Using Barcode recognizer for .NET framework Control to read, scan read, scan image in VS .NET applications. Code 128C Printer In ObjectiveC Using Barcode drawer for iPhone Control to generate, create Code128 image in iPhone applications. AM FL Y
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Resistance calculations 71 you can do about it unless you are willing to use units of nanoamperes (nA), or billionths of an ampere. Then you can say that the current is 186 nA. Voltage calculations
The second use of Ohm s Law is to find unknown voltages when the current and the resistance are known. For the following problems, uncover the ammeter and cover the voltmeter scale instead in your mind. Problem 44 Suppose the potentiometer (Fig. 47) is set to 100 ohms, and the measured current is 10 mA. What is the dc voltage Use the formula E I R. First, convert the current to amperes: 10 mA = 0. 01 A. Then multiply: E 0. 01 100 1 V. That s a low, safe voltage, a little less than what is produced by a flashlight cell. Problem 45 Adjust the potentiometer (Fig. 47) to a value of 157 K , and let the current reading be 17 mA. What is the voltage of the source Now you have to convert both the resistance and the current values to their proper units. A resistance of 157 K is 157,000 ; a current of 17 mA is 0. 017 A. Then E IR 0.017 157,000 2669 V 2.669 kV. You might want to round this off to 2.67 kV. This is a dangerous voltage. If you touch the terminals you ll get clobbered. Problem 46 You set the potentiometer (Fig. 47) so that the meter reads 1.445 A, and you observe that the potentiometer scale shows 99 ohms. What is the voltage These units are both in their proper form. Therefore, you can plug them right in and use your calculator: E IR 1. 445 99 143.055 V. This can, and should, be rounded off to 143 V. A purist would go further and round it to the nearest 10 volts, to 140 V. It s never a good idea to specify your answer to a problem with more significant figures than you re given. The best engineers and scientists go by the rule of significant figures: keep to the least number of digits given in the data. If you follow this rule in Problem 46, you must round off the answer to two significant figures, getting 140 V, because the resistance specified (99 ) is only accurate to two digits.

