barcode printing using vb.net The unit of capacitance in Software

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The unit of capacitance
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When a battery is connected between the plates of a capacitor, it takes some time before the electric field reaches its full intensity. The voltage builds up at a rate that depends on the capacitance: the greater the capacitance, the slower the rate of change of voltage in the plates. The unit of capacitance is an expression of the ratio between the amount of current flowing and the rate of voltage change across the plates of a capacitor. A capacitance of one farad, abbreviated F, represents a current flow of one ampere while there is a potential-difference increase or decrease of one volt per second. A capacitance of one farad also results in one volt of potential difference for an electric charge of one coulomb. The farad is a huge unit of capacitance. You ll almost never see a capacitor with a value of 1 F. Commonly employed units of capacitance are the microfarad ( F) and the picofarad (pF). A capacitance of 1 F represents a millionth (10-6) of a farad, and 1 pF is a millionth of a microfarad, or a trillionth of a farad (10-12 F). Some quite large capacitances can be stuffed into physically small components. Conversely, some capacitors with small values take up large volumes. The bulkiness of a capacitor is proportional to the voltage that it can handle, more than it is related to the capacitance. The higher the rated voltage, the bigger, physically, the component will be.
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202 Capacitance
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Capacitors in series
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With capacitors, there is almost never any mutual interaction. This makes capacitors somewhat easier to work with than inductors. Capacitors in series add together like resistors in parallel. If you connect two capacitors of the same value in series, the result will be half the capacitance of either component alone. In general, if there are several capacitors in series, the composite value will be less than any of the single components. It is important that you always use the same size units when determining the capacitance of any combination. Don t mix microfarads with picofarads. The answer that you get will be in whichever size units you use for the individual components. Suppose you have several capacitors with values C1, C2, C3, . . . Cn all connected in series. Then you can find the reciprocal of the total capacitance, 1/C, using the following formula: 1/C 1/C1 1/C2 1/C3 1/Cn
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The total capacitance, C, is found by taking the reciprocal of the number you get for 1/C. If two or more capacitors are connected in series, and one of them has a value that is extremely tiny compared with the values of all the others, the composite capacitance can be taken as the value of the smallest component.
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Problem 11-1
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Two capacitors, with values of C1 0.10 F and C2 (Fig. 11-3). What is the total capacitance 0.050 F, are connected in series
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11-3 Capacitors in series.
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Using the above formula, first find the reciprocals of the values. They are 1/C1 and 1/C2 20. Then 1/C 10 20 30, and C 1/30 0.033 F.
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Problem 11-2
Two capacitors with values of 0.0010 F and 100 pF are connected in series. What is the total capacitance Convert to the same size units. A value of 100 pF represents 0. 000100 F. Then you can say that C1 0.0010 F and C2 0.00010 F. The reciprocals are 1/C1 1000 and
Capacitors in parallel 203 1/C2 10,000. Therefore, 1/C 1,000 10,000 11,000, and C 0. 000091 F. This number is a little awkward, and you might rather say it s 91 pF. In the above problem, you could have chosen pF to work with, rather than F. In either case, there is some tricky decimal placement involved. It s important to doublecheck calculations when numbers get like this. Calculators will take care of the decimal placement problem, sometimes using exponent notation and sometimes not, but a calculator can only work with what you put into it! If you put a wrong number in, you will get a wrong answer, perhaps off by a factor of 10, 100, or even 1,000.
Problem 11-3
Five capacitors, each of 100 pF, are in series. What is the total capacitance If there are n capacitors in series, all of the same value so that C1 C2 C3 . . . Cn, the total value C is just 1/n of the capacitance of any of the components alone. Because there are five 100-pF capacitors here, the total is C 100/5 20 pF.
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