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barcode in vb.net 2010 Impedance and Admittance in Software
244 Impedance and Admittance Recognize Code 3 Of 9 In None Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications. Make Code 39 Full ASCII In None Using Barcode printer for Software Control to generate, create USS Code 39 image in Software applications. 14. An inductor has a value of 44 mH at 60 Hz. What is the inductive susceptance, stated as an imaginary number (a) BL = j0.060 (b) BL = j0.060 (c) BL = j17 (d) BL = j17 15. Susceptance and conductance add to form (a) complex impedance. (b) complex inductance. (c) complex reactance. (d) complex admittance. 16. Absolutevalue impedance is equal to the square root of which of the following (a) G 2 + B 2 (b) R 2 + X 2 (c) Zo (d) Y 2 + R 2 17. Inductive susceptance is defined in (a) imaginary ohms. (b) imaginary henrys. (c) imaginary farads. (d) imaginary siemens. 18. Capacitive susceptance values can be defined by (a) positive real numbers. (b) negative real numbers. (c) positive imaginary numbers. (d) negative imaginary numbers. 19. Which of the following is false (a) BC = 1/XC. (b) Complex impedance can be depicted as a vector. (c) Characteristic impedance is complex. (d) G = 1/R. 20. In general, as the absolute value of the impedance in a circuit increases, (a) the flow of ac increases. (b) the flow of ac decreases. (c) the reactance decreases. (d) the resistance decreases. Code 39 Extended Decoder In None Using Barcode reader for Software Control to read, scan read, scan image in Software applications. Making Code39 In Visual C#.NET Using Barcode printer for Visual Studio .NET Control to generate, create Code 39 Extended image in Visual Studio .NET applications. CHAPTER
Printing Code 39 In Visual Studio .NET Using Barcode generation for ASP.NET Control to generate, create Code 39 Full ASCII image in ASP.NET applications. Code39 Generator In .NET Using Barcode generation for .NET Control to generate, create Code 39 Extended image in .NET applications. RLC and GLC Circuit Analysis
Code 3 Of 9 Generator In VB.NET Using Barcode generation for VS .NET Control to generate, create Code 39 image in .NET framework applications. Generate UCC.EAN  128 In None Using Barcode generation for Software Control to generate, create USS128 image in Software applications. WHEN YOU SEE AN AC CIRCUIT THAT CONTAINS COILS AND/OR CAPACITORS, YOU SHOULD ENVISION a complexnumber plane, either RX (resistancereactance) or GB (conductanceadmittance). The RX plane applies to series circuit analysis. The GB plane applies to parallel circuit analysis. European Article Number 13 Generation In None Using Barcode printer for Software Control to generate, create EAN13 image in Software applications. Print DataMatrix In None Using Barcode encoder for Software Control to generate, create Data Matrix ECC200 image in Software applications. Complex Impedances in Series
Drawing Barcode In None Using Barcode printer for Software Control to generate, create barcode image in Software applications. Drawing Code 128A In None Using Barcode maker for Software Control to generate, create Code 128 Code Set B image in Software applications. When you see resistors, coils, and capacitors in series, each component has an impedance that can be represented as a vector in the RX plane. The vectors for resistors are constant, regardless of the frequency. But the vectors for coils and capacitors vary with frequency. ISSN  13 Printer In None Using Barcode creation for Software Control to generate, create ISSN  10 image in Software applications. Matrix 2D Barcode Generation In C# Using Barcode printer for VS .NET Control to generate, create Matrix 2D Barcode image in .NET applications. Pure Reactances Pure inductive reactances (X L ) and capacitive reactances (X C ) simply add together when coils and capacitors are in series. Thus, X = X L + X C. In the RX plane, their vectors add, but because these vectors point in exactly opposite directions inductive reactance upward and capacitive reactance downward (Fig. 161) the resultant sum vector inevitably points either straight up or straight down, unless the reactances are equal and opposite, in which case they cancel and the result is the zero vector. Problem 161 Suppose a coil and capacitor are connected in series, with jX L = j200 and jX C = j150. What is the net reactance Just add the values: jX = jX L + jX C = j200 + ( j150) = j(200 150) = j50. This is a pure inductive reactance, because it is positive imaginary. Problem 162 Suppose a coil and capacitor are connected in series, with jXL = j30 and jX C = j110. What is the net reactance Data Matrix 2d Barcode Printer In None Using Barcode maker for Office Word Control to generate, create ECC200 image in Office Word applications. EAN13 Maker In Java Using Barcode generation for Java Control to generate, create GS1  13 image in Java applications. Copyright 2006, 2002, 1997, 1993 by The McGrawHill Companies, Inc. Click here for terms of use.
Recognize EAN / UCC  13 In C# Using Barcode scanner for .NET Control to read, scan read, scan image in Visual Studio .NET applications. Print EAN / UCC  13 In Java Using Barcode maker for Java Control to generate, create UPC  13 image in Java applications. 246 RLC and GLC Circuit Analysis
Scanning Data Matrix 2d Barcode In Java Using Barcode decoder for Java Control to read, scan read, scan image in Java applications. Paint EAN13 In .NET Framework Using Barcode generation for .NET framework Control to generate, create GS1  13 image in .NET applications. 161 Pure inductance and
pure capacitance are represented by reactance vectors that point straight up and down.
Again, add the values: jX = j30 + ( j110) = j(30 110) = j80. This is a pure capacitive reactance, because it is negative imaginary. Problem 163 Suppose a coil of inductance L = 5.00 H and a capacitor of capacitance C = 200 pF are connected in series. Suppose the frequency is f = 4.00 MHz. What is the net reactance First, calculate the reactance of the inductor at 4.00 MHz. Proceed as follows: jXL = j6.28f L = j(6.28 4.00 5.00) = j126 Next, calculate the reactance of the capacitor at 4.00 MHz. Proceed as follows: jX C = j[1/(6.28f C )] = j[1/(6.28 4.00 0.000200)] = j199 Finally, add the inductive and capacitive reactances to obtain the net reactance: jX = jXL + jX C = j126 + ( j199) = j 73 This is a pure capacitive reactance. Problem 164 What is the net reactance of the aforementioned inductor and capacitor combination at the frequency f = 10.0 MHz

