# barcode in vb.net 2010 Vector diagram in Software Maker Code 3 of 9 in Software Vector diagram

17-6 Vector diagram
Recognizing USS Code 39 In None
Using Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
Drawing Code 39 Extended In None
Using Barcode generation for Software Control to generate, create Code39 image in Software applications.
showing the phase angle for a purely capacitive impedance of 0 j40. The R and jX scales are relative.
Reading ANSI/AIM Code 39 In None
Using Barcode scanner for Software Control to read, scan read, scan image in Software applications.
Painting Code39 In C#.NET
Using Barcode generation for Visual Studio .NET Control to generate, create Code 39 Full ASCII image in Visual Studio .NET applications.
True Power, VA Power, and Reactive Power 271
Code39 Drawer In .NET Framework
Using Barcode generation for ASP.NET Control to generate, create ANSI/AIM Code 39 image in ASP.NET applications.
Create Code 3 Of 9 In VS .NET
Using Barcode maker for .NET Control to generate, create USS Code 39 image in VS .NET applications.
17-7 Vector diagram
Print Code 3/9 In VB.NET
Using Barcode printer for .NET framework Control to generate, create Code 3/9 image in .NET applications.
Code128 Printer In None
Using Barcode creation for Software Control to generate, create Code128 image in Software applications.
showing the phase angle for a complex impedance of 50 + j50. The R and jX scales are relative.
Code 39 Maker In None
Using Barcode drawer for Software Control to generate, create Code 3 of 9 image in Software applications.
Printing GS1 - 13 In None
Using Barcode encoder for Software Control to generate, create EAN-13 Supplement 5 image in Software applications.
Problem 17-4 Suppose a circuit has an absolute-value impedance Z of 100 , with a resistance R = 80 . What is the power factor Simply find the ratio PF = R/Z = 80/100 = 0.8 = 80%. Note that it doesn t matter whether the reactance in this circuit is capacitive or inductive. Problem 17-5 Suppose a circuit has an absolute-value impedance of 50 , purely resistive. What is the power factor Here, R = Z = 50 . Therefore, PF = R/Z = 50/50 = 1 = 100%. Problem 17-6 Suppose a circuit has a resistance of 50 and a capacitive reactance of 30 in series. What is the power factor Use the cosine method. First, find the phase angle. Remember the formula: = arctan (X/R), where X is the reactance and R is the resistance. Therefore, = arctan ( 30/50) = arctan ( 0.60) = 31 . The power factor is the cosine of this angle; PF = cos ( 31 ) = 0.86 = 86%. Problem 17-7 Suppose a circuit has a resistance of 30 and an inductive reactance of 40 . What is the power factor Use the R/Z method. Find the absolute-value impedance: Z 2 = R 2 + X 2 = 30 2 + 40 2 = 900 + 1600 = 2500. Therefore, Z = 25001/2 = 50 , so PF = R/Z = 30/50 = 0.60 = 60%. This problem can be represented vectorially by a 30:40:50 right triangle, as shown in Fig. 17-8. How Much of the Power Is True The preceding formulas allow you to figure out, given the resistance, reactance, and VA power, how many watts are true or real power, and how many watts are imaginary or reactive power. This is important in RF equipment, because some RF wattmeters display VA power rather than true power. When there is reactance in a circuit or system, the wattage reading is therefore exaggerated.
EAN / UCC - 14 Creation In None
Using Barcode creation for Software Control to generate, create GS1-128 image in Software applications.
Paint UCC - 12 In None
Using Barcode drawer for Software Control to generate, create UPC-A Supplement 5 image in Software applications.
272 Power and Resonance in Alternating-Current Circuits
MSI Plessey Drawer In None
Using Barcode creator for Software Control to generate, create MSI Plessey image in Software applications.
Generating GS1-128 In None
Using Barcode maker for Font Control to generate, create UCC - 12 image in Font applications.
17-8 Illustration for
1D Maker In VS .NET
Using Barcode drawer for ASP.NET Control to generate, create Linear image in ASP.NET applications.
Drawing USS Code 128 In Java
Using Barcode drawer for Java Control to generate, create Code-128 image in Java applications.
Problem 17-7. (The vertical and horizontal scale increments differ; this is a common practice in graphs, often done for illustration convenience.)
Code 39 Full ASCII Encoder In Visual Studio .NET
Using Barcode generation for .NET Control to generate, create Code 3 of 9 image in .NET framework applications.
GS1 - 12 Drawer In Objective-C
Using Barcode creator for iPad Control to generate, create UPC Symbol image in iPad applications.
Problem 17-8 Suppose a circuit has 50 of resistance and 30 of inductive reactance in series. A wattmeter shows 100 W, representing the VA power. What is the true power First, calculate the power factor. Suppose you use the phase-angle method. Then:
Data Matrix ECC200 Creator In Visual C#.NET
Using Barcode creator for VS .NET Control to generate, create Data Matrix ECC200 image in VS .NET applications.
Linear Generator In VB.NET
Using Barcode encoder for .NET Control to generate, create 1D image in Visual Studio .NET applications.
= arctan (X/R ) = arctan (30/50) = 31 The power factor is the cosine of the phase angle. Thus: PF = cos 31 = 0.86 = 86% Remember that PF = PT/PVA. This formula can be rearranged to solve for true power: PT = PF PVA = 0.86 100 = 86 W
Problem 17-9 Suppose a circuit has a resistance of 1000 in parallel with a capacitance of 1000 pF. The frequency is 100 kHz. If a wattmeter designed to read VA power shows a reading of 88.0 W, what is the true power This problem is rather complicated because the components are in parallel. To begin, be sure the units are all in agreement so the formulas will work right. Convert the frequency to megahertz: f = 100 kHz = 0.100 MHz. Convert capacitance to microfarads: C = 1000 pF = 0.001000 F. From the previous chapter, recall the formula for capacitive susceptance, and calculate it for this situation:
BC = 6.28f C = 6.28 0.100 0.001000 = 0.000628 S
Power Transmission 273
The conductance of the resistor, G, is the reciprocal of the resistance, R, as follows: G = 1/R = 1/1000 = 0.001000 S Now, use the formulas for calculating resistance and reactance in terms of conductance and susceptance in parallel circuits. First, find the resistance: R = G/(G 2 + B 2) = 0.001000/(0.0010002 + 0.0006282) = 0.001000/0.000001394 = 717 Then, find the reactance: X = B/(G 2 + B 2) = 0.000628/0.000001394 = 451 Next, calculate the phase angle: = arctan (X/R) = arctan ( 451/717) = arctan ( 0.629) = 32.2 The power factor is found from the phase angle as follows: PF = cos = cos ( 32.2 ) = 0.846 = 84.6% The VA power, PVA, is given as 88.0 W. Therefore: PT = PF PVA = 0.846 88.0 = 74.4 W