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CHAPTER 8 EXPRESSIONS AND OPERATORS
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For example, the following code compares some regular and verbatim string literals: string rst1 = "Hi there!"; string vst1 = @"Hi there!"; string rst2 = "It started, \"Four score and seven...\""; string vst2 = @"It started, ""Four score and seven..."""; string rst3 = "Value 1 \t 5, Val2 \t 10"; string vst3 = @"Value 1 \t 5, Val2 \t 10"; // Interprets tab esc sequence // Does not interpret tab
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string rst4 = "C:\\Program Files\\Microsoft\\"; string vst4 = @"C:\Program Files\Microsoft\"; string rst5 = " Print \x000A Multiple \u000A Lines"; string vst5 = @" Print Multiple Lines"; Printing these strings produces the following output: Hi there! Hi there! It started, "Four score and seven..." It started, "Four score and seven..." Value 1 5, Val2 Value 1 \t 5, Val2 \t 10 C:\Program Files\Microsoft\ C:\Program Files\Microsoft\ Print Multiple Lines Print Multiple Lines 10
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Note The compiler saves memory by having identical string literals share the same memory location in
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the heap.
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CHAPTER 8 EXPRESSIONS AND OPERATORS
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Order of Evaluation
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An expression can be made up of many nested sub-expressions. The order in which the subexpressions are evaluated can make a difference in the final value of the expression. For example, given the expression 3 * 5 + 2, there are two possible results depending on the order in which the sub-expressions are evaluated, as shown in Figure 8-3. If the multiplication is performed first, the result is 17. If the 5 and the 2 are added together first, the result is 21.
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Figure 8-3. Simple order of evaluation
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Precedence
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You know from your grade school days that in the preceding example, the multiplication must be performed before the addition because multiplication has a higher precedence than addition. But unlike grade school days, when you had four operators and two levels of precedence, things are a bit more complex with C#, which has over 45 operators and 14 levels of precedence. The complete list of operators and their precedences is given in Table 8-4. The table lists the highest precedence operators at the top, and continues down to the lowest precedence operators at the bottom. Table 8-4. Operator Precedence: Highest to Lowest
Category
Primary Unary Multiplicative Additive Shift Relational and type Equality Logical AND Logical XOR Logical OR Conditional AND Conditional OR
Operators
a.x, f(x), a[x], x++, x--, new, typeof, checked, unchecked +, -, !, ~, ++x, --x, (T)x *, /, % +, <<, >> <, >, <=, >=, is, as ==, != & ^ | && ||
CHAPTER 8 EXPRESSIONS AND OPERATORS
Category
Conditional Assignment
Operators
: =, *=, /=, %=, +=, -=, <<=, >>=, &=, ^=, |=
Associativity
If all the operators in an expression have different levels of precedence, then evaluate each sub-expression, starting at the one with the highest level, and work down the precedence scale. But what if two sequential operators have the same level of precedence For example, given the expression 2 / 6 * 4, there are two possible evaluation sequences: (2 / 6) * 4 = 4/3 or 2 / (6 * 4) = 1/12 When sequential operators have the same level of precedence, the order of evaluation is determined by operator associativity. That is, given two operators of the same level of precedence, one or the other will have precedence, depending on the operators associativity. Some important characteristics of operator associativity are the following, and are summarized in Table 8-5: Left-associative operators are evaluated from left to right. Right-associative operators are evaluated from right to left. Binary operators, except the assignment operators, are left-associative. The assignment operators and the conditional operator are right-associative. Therefore, given these rules, the preceding example expression should be grouped left to right, giving (2 / 6 ) * 4, which yields 4/3. Table 8-5. Summary of Operator Associativity
Type of Operator
Assignment operators Other binary operators The conditional operator
Associativity
Right-associative Left-associative Right-associative
You can explicitly set the order of evaluation of the sub-expressions of an expression by using parentheses. Parenthesized sub-expressions Override the precedence and associativity rules Are evaluated in order from the innermost nested set to the outermost
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