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17 Reading Code 39 Full ASCII In VS .NET Using Barcode Control SDK for .NET Control to generate, create, read, scan barcode image in .NET framework applications. Code 39 Full ASCII Drawer In .NET Framework Using Barcode generator for .NET Control to generate, create Code 39 Full ASCII image in VS .NET applications. which simplifies to (x + 2)2 /a2 9/b2 + (z 4)2 /c2 = 0 If we add the quantity 9/b2 to both sides, we obtain (x + 2)2 /a2 + (z 4)2 /c2 = 9/b2 Now we can divide through by the quantity 9/b2, getting (x + 2)2 /(9a2 /b2) + (z 4)2 /(9c2 /b2) = 1 which can also be expressed as (x + 2)2 /(3a/b)2 + (z 4)2 /(3c/b)2 = 1 This is a generalized equation for an ellipse in the Cartesian plane, where the variables are x and z The center of the ellipse has the coordinates (x0,z0) = ( 2,4) The semiaxes have lengths 3a/b and 3c/b 10 Here, once again, is the generalized equation that we derived for the elliptic cone described in Problem 8: (x + 2)2 /a2 (y 3)2 /b2 + (z 4)2 /c2 = 0 This cone intersects the xy plane in a curve where z = 0 at every point If we set z = 0 in the above equation, we get (x + 2)2 /a2 (y 3)2 /b2 + (0 4)2 /c2 = 0 We can simplify this equation to (x + 2)2 /a2 (y 3)2 /b2 + 16/c2 = 0 If we subtract the quantity 16/c2 from both sides, we obtain (x + 2)2 /a2 (y 3)2 /b2 = 16/c2 Dividing through by the quantity 16/c2, we obtain (x + 2)2 /(16a2 /c2) (y 3)2 /(16b2 /c2) = 1 which can be rewritten as (x + 2)2 /(4a/c)2 (y 3)2 /(4b/c)2 = 1 Recognize Code 39 Extended In .NET Framework Using Barcode recognizer for .NET framework Control to read, scan read, scan image in Visual Studio .NET applications. Bar Code Generation In Visual Studio .NET Using Barcode printer for VS .NET Control to generate, create barcode image in .NET applications. 564 WorkedOut Solutions to Exercises: 1119 Barcode Reader In .NET Framework Using Barcode recognizer for VS .NET Control to read, scan read, scan image in Visual Studio .NET applications. Paint Code 3/9 In Visual C# Using Barcode generator for VS .NET Control to generate, create Code 39 Full ASCII image in .NET framework applications. Finally, we can multiply the entire equation through by 1 to obtain (y 3)2 /(4b/c)2 (x + 2)2 /(4a/c)2 = 1 This is a generalized equation for a hyperbola in the Cartesian xy plane It s oriented differently than the hyperbolas in Chap 13, however Instead of opening in the positive and negative x directions as the hyperbolas in Chap 13 do, this pair of curves opens in the positive and negative y directions The coordinates of the center are (x0,y0) = ( 2,3) The lengths of the semiaxes are 4a/c and 4b/c Code 39 Extended Generation In .NET Framework Using Barcode generation for ASP.NET Control to generate, create Code 39 Extended image in ASP.NET applications. Printing Code 3 Of 9 In Visual Basic .NET Using Barcode creation for .NET Control to generate, create ANSI/AIM Code 39 image in .NET framework applications. 18
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Encoding Bar Code In Java Using Barcode drawer for Android Control to generate, create barcode image in Android applications. Create GS1128 In ObjectiveC Using Barcode generator for iPhone Control to generate, create GTIN  128 image in iPhone applications. 2 Stated again for reference, the threeway equation for our line is 4x = 5y = 6z Dividing the entire equation through by 60, we obtain x /15 = y /12 = z/10 The generalized standardform symmetric equation is (x x0)/a = (y y0)/b = (z z0)/c where (x0,y0,z0) are the coordinates of a specific point on the line, and a, b, and c are the direction numbers In this case, we have x0 = 0 y0 = 0 z0 = 0 This tells us that the origin (0,0,0) is on the line We also have a = 15 b = 12 c = 10 so the line s direction numbers are (15,12,10) This ordered triple is in lowest form, so the direction vector m is m = 15i + 12j + 10k 3 We ve been given the symmetric equation (x 2)/3 = (4y 8)/4 = (z + 5)/( 2) We can divide out the middle portion to get (x 2)/3 = y 2 = (z + 5)/( 2) This equation is in the standard symmetric form Once again, the generalized standardform symmetric equation is (x x0)/a = (y y0)/b = (z z0)/c In this situation, we have x0 = 2 y0 = 2 z0 = 5 Code39 Scanner In Visual C# Using Barcode recognizer for .NET Control to read, scan read, scan image in Visual Studio .NET applications. EAN13 Supplement 5 Generation In ObjectiveC Using Barcode generator for iPad Control to generate, create EAN / UCC  13 image in iPad applications. 566 WorkedOut Solutions to Exercises: 1119 Making EAN13 In None Using Barcode generation for Online Control to generate, create EAN13 image in Online applications. Code39 Drawer In None Using Barcode generator for Font Control to generate, create Code 39 Extended image in Font applications. so we know that the point (2,2, 5) is on the line We can also see that a=3 b=1 c = 2 so the line s direction numbers are (3,1, 2) This ordered triple is in lowest form (We could divide it through by 1, but then we d get two negative elements instead of only one) The direction vector m is therefore m = 3i + j 2k 4 Stated again for convenience, the parametric equations for our object are x = 4 y=t z = t 2 1 The first equation tells us that the object lies in the plane x = 4, which is perpendicular to the x axis, parallel to the yz plane, and 4 units distant from the yz plane on the x side We can draw projections of the coordinate y and z axes into the plane x = 4, obtaining a Cartesian yz grid In that system, our object is a parabola defined by y=t and z = t2 1 Substituting y for t in the second equation gives us z = y 2 1 Figure B32 is a graph of this curve as it looks when we see the plane x = 4 broadside from a point on the positive x axis at a considerable distance from the origin Figure B32 Code 3/9 Encoder In None Using Barcode encoder for Microsoft Excel Control to generate, create Code 3/9 image in Microsoft Excel applications. Drawing Data Matrix 2d Barcode In None Using Barcode creation for Microsoft Word Control to generate, create Data Matrix 2d barcode image in Microsoft Word applications. 
