X cos 1 + X 2 2 X sin 1 X sin
Data Matrix Reader In NoneUsing Barcode Control SDK for Software Control to generate, create, read, scan barcode image in Software applications.
Create ECC200 In NoneUsing Barcode creator for Software Control to generate, create Data Matrix image in Software applications.
(34) (35)
Recognize Data Matrix In NoneUsing Barcode recognizer for Software Control to read, scan read, scan image in Software applications.
Painting DataMatrix In C#.NETUsing Barcode creation for VS .NET Control to generate, create DataMatrix image in .NET applications.
1 + X 2 2 X sin Considering the triangle abc
Encode ECC200 In .NET FrameworkUsing Barcode drawer for ASP.NET Control to generate, create Data Matrix image in ASP.NET applications.
Data Matrix Generation In .NETUsing Barcode generation for .NET framework Control to generate, create DataMatrix image in .NET applications.
sin sin = f R d f sin R d = sin
Create ECC200 In VB.NETUsing Barcode maker for Visual Studio .NET Control to generate, create ECC200 image in .NET applications.
Printing UPC-A Supplement 5 In NoneUsing Barcode creation for Software Control to generate, create UPC A image in Software applications.
d = R
Creating Bar Code In NoneUsing Barcode creation for Software Control to generate, create barcode image in Software applications.
Encoding Code128 In NoneUsing Barcode creation for Software Control to generate, create Code 128 image in Software applications.
Fig 341:
Encode DataMatrix In NoneUsing Barcode generator for Software Control to generate, create ECC200 image in Software applications.
UCC - 12 Generator In NoneUsing Barcode creator for Software Control to generate, create UCC - 12 image in Software applications.
Geometry of b and q
Encode International Standard Serial Number In NoneUsing Barcode generator for Software Control to generate, create International Standard Serial Number image in Software applications.
Data Matrix 2d Barcode Decoder In Visual Basic .NETUsing Barcode scanner for .NET Control to read, scan read, scan image in VS .NET applications.
f sin f cos = R sin sin
Bar Code Scanner In Visual C#.NETUsing Barcode recognizer for Visual Studio .NET Control to read, scan read, scan image in Visual Studio .NET applications.
Generating Bar Code In Visual Studio .NETUsing Barcode encoder for .NET framework Control to generate, create bar code image in .NET framework applications.
f cos 1 + X 2 2 X sin X cos
European Article Number 13 Printer In NoneUsing Barcode drawer for Word Control to generate, create EAN13 image in Office Word applications.
Bar Code Drawer In JavaUsing Barcode encoder for Java Control to generate, create barcode image in Java applications.
(36)
Encoding DataMatrix In NoneUsing Barcode creation for Microsoft Word Control to generate, create Data Matrix ECC200 image in Word applications.
Scan Barcode In JavaUsing Barcode recognizer for Java Control to read, scan read, scan image in Java applications.
Substituting for sin b from equation (34) d = R putting the value of X d = R R 1 + f 2 R 2 2 ( f R ) sin where d = chip thickness with f/R<<<1 we can write d = R R 1 2 ( f R ) sin (38) (37)
Precision Engineering
This equation can be simplified by using Taylor s series Let ( f/R ) sin q = a By using Taylor s series, the term can be expanded as
1 2a = (1 2a )2 = 1
2a 2 + + 2
This part of the expansion is very small as compared to the original value So the equation can be expressed as d = R R 1 2 ( f R ) sin d = R R (1 2 ( f R ) sin )
2 ( f R ) sin + + d = R R 1 2 d = R( f/R ) sin q d = f sin q (39) For typical conditions, q < 10 and sin q q d = fq The location of d is referenced by the distance Z measured from the tool centre to d on the plane of the cut as shown in the figure
Z = sin ( 90 ( + ) ) = cos ( + ) R
using the following identity: cos (a + b) = cos a sin b sin a cos b Substituting for sin a and cos b from equation (34) and (35) results in the following evolvement of Z: Z =
R sin (1 sin ) 1 + X 2 2X sin
R cos2 1 + X 2 2 X sin
R ( sin X sin2 X cos2 ) 1 + X 2 2X sin R ( sin X ) 1 + X 2 2X sin
(40)
Using the fact that X = f/R <<< 1 and q is small, Z becomes Z = R ( sin X ) = R ( sin f R )
Mechanics of Materials Cutting Substituting from equation 39 Z = R (d f f R) = d =
Rd f f
f (Z + f ) (41) R The equation contains a minor correction relative to Blake s result If the depth of the machining damage, Yc, at a critical depth, d = dc, were zero, that is, Yc = 0, then the measurement of Z = Zc would give a value of dc via equation 39 However, practically Yc is not zero, and also from productivity reasons, it is not desirable that it is zero Yc is proportionally dependent on the feed An increase in the feed causes an increase in the depth of damage and vice versa To continue with this fact, the geometry shown in Figure 342 is used As there is a nonzero Yc value, Z is shifted Zeff is now the measured value of the position for the onset of damage (ductile to brittle transaction) on the shoulder In the above Fig 342: The geometry used to derive values of @ figure, the chip has been moved from a shoulder distance h to allow an overlap of the damage from successive tool pass Zc is the value of Z corresponding to d = dc Zeff is the measured distance on the shoulder of the interrupted cut It can be seen that Zeff = Zc Z Figure 343 shows the enlarged key geometry From figure 343, Z = h Yc sin w h (42) Because both Yc and sin w are small relative to h, to evaluate h, distance p is added to Yc such that it forms a right angled triangle as shown in the figure, and the length of this new side can be expressed:
Fig 343: Triangle used to calculate ;
Precision Engineering n = R sin
so tan /2 = p/n p = R sin tan /2 Recognizing that and w are very small p =
R 2 2 h h cos = R R
(43)
is related to h using the data in figure 10 and by using the following equation: sin f = = so From the triangle p =
h2 2R
h sin w = Yc + p = Yc + where
h2 2R
sin w = Z/R
h 2Z c h + 2 RYc = 0 Using the quadratic formula,
h = Z c Z c 2 2 RYc The physically correct root corresponds to the minus sign so that h = Z c Z c 2 2 RYc We then have from equation 42 Zeff = Z c Z = Z c h = Z c 2 2 RYc